In a calorimetry experiment, if 50 g of water is heated from 25 °C to 75 °C, wha
Practice Questions
Q1
In a calorimetry experiment, if 50 g of water is heated from 25 °C to 75 °C, what is the heat absorbed (q) assuming specific heat capacity of water is 4.18 J/g°C?
1045 J
2090 J
1250 J
500 J
Questions & Step-by-Step Solutions
In a calorimetry experiment, if 50 g of water is heated from 25 °C to 75 °C, what is the heat absorbed (q) assuming specific heat capacity of water is 4.18 J/g°C?
Step 1: Identify the mass of water (m). In this case, it is 50 grams.
Step 2: Identify the specific heat capacity (c) of water. It is given as 4.18 J/g°C.
Step 3: Determine the initial temperature (T_initial) and final temperature (T_final) of the water. Here, T_initial is 25 °C and T_final is 75 °C.
Step 4: Calculate the change in temperature (ΔT) using the formula ΔT = T_final - T_initial. So, ΔT = 75 °C - 25 °C = 50 °C.
Step 5: Use the formula for heat absorbed (q), which is q = mcΔT. Substitute the values: q = 50 g × 4.18 J/g°C × 50 °C.
Step 6: Perform the multiplication: 50 g × 4.18 J/g°C = 209 J. Then, multiply 209 J by 50 °C to get q = 1045 J.
