Question: In a calorimetry experiment, if 50 g of water is heated from 25 °C to 75 °C, what is the heat absorbed (q) assuming specific heat capacity of water is 4.18 J/g°C?
Options:
Correct Answer: 2090 J
Solution:
q = mcΔT = 50 g × 4.18 J/g°C × (75-25)°C = 1045 J.