Question: Calculate the enthalpy change (ΔH) for the reaction: 2NO(g) + O2(g) → 2NO2(g) given the following bond enthalpies: N≡N = 941 kJ/mol, O=O = 498 kJ/mol, N=O = 201 kJ/mol.
Options:
Correct Answer: -220 kJ
Solution:
ΔH = [2(201) + 498] - [2(941)] = -220 kJ.