What is the standard enthalpy change (ΔH°) for the formation of 1 mole of CO2(g)
Practice Questions
Q1
What is the standard enthalpy change (ΔH°) for the formation of 1 mole of CO2(g) from C(s) and O2(g) given the following reactions: C(s) + O2(g) → CO2(g) ΔH° = -393.5 kJ?
-393.5 kJ
393.5 kJ
0 kJ
-273.15 kJ
Questions & Step-by-Step Solutions
What is the standard enthalpy change (ΔH°) for the formation of 1 mole of CO2(g) from C(s) and O2(g) given the following reactions: C(s) + O2(g) → CO2(g) ΔH° = -393.5 kJ?
Step 2: Note the enthalpy change (ΔH°) provided for this reaction, which is -393.5 kJ.
Step 3: Understand that this value represents the standard enthalpy change for the formation of 1 mole of CO2(g) from its elements in their standard states.
Step 4: Conclude that the standard enthalpy change (ΔH°) for the formation of 1 mole of CO2(g) is -393.5 kJ.
