In a reversible isothermal expansion of an ideal gas, what is the work done by t

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Question: In a reversible isothermal expansion of an ideal gas, what is the work done by the gas?

Options:

Correct Answer: W = nRT ln(Vf/Vi)

Solution:

The work done by the gas during a reversible isothermal expansion is given by W = nRT ln(Vf/Vi).

In a reversible isothermal expansion of an ideal gas, what is the work done by the gas?

In a reversible isothermal expansion of an ideal gas, what is the work done by the gas?

Step 1: Understand that we are dealing with an ideal gas undergoing a reversible isothermal expansion. This means the temperature remains constant during the process.
Step 2: Identify the variables involved: n (number of moles of gas), R (universal gas constant), T (temperature in Kelvin), Vf (final volume), and Vi (initial volume).
Step 3: Recall the formula for work done by the gas during this process, which is W = nRT ln(Vf/Vi).
Step 4: Recognize that 'ln' refers to the natural logarithm, which is a mathematical function.
Step 5: To calculate the work done, you need to know the values of n, R, T, Vf, and Vi.
Step 6: Plug the values into the formula to find the work done by the gas.

Reversible Isothermal Expansion – This process involves an ideal gas expanding at a constant temperature, where the system is in equilibrium with its surroundings.
Work Done by Gas – The work done by the gas during expansion is calculated using the formula W = nRT ln(Vf/Vi), where n is the number of moles, R is the ideal gas constant, T is the temperature, Vf is the final volume, and Vi is the initial volume.
Ideal Gas Behavior – The ideal gas law (PV=nRT) applies, and the gas behaves ideally under the conditions of the problem.