In a reversible isothermal expansion of an ideal gas, what is the work done by t
Practice Questions
Q1
In a reversible isothermal expansion of an ideal gas, what is the work done by the gas?
W = nRT ln(Vf/Vi)
W = nRT (Vf - Vi)
W = -PΔV
W = 0
Questions & Step-by-Step Solutions
In a reversible isothermal expansion of an ideal gas, what is the work done by the gas?
Step 1: Understand that we are dealing with an ideal gas undergoing a reversible isothermal expansion. This means the temperature remains constant during the process.
Step 2: Identify the variables involved: n (number of moles of gas), R (universal gas constant), T (temperature in Kelvin), Vf (final volume), and Vi (initial volume).
Step 3: Recall the formula for work done by the gas during this process, which is W = nRT ln(Vf/Vi).
Step 4: Recognize that 'ln' refers to the natural logarithm, which is a mathematical function.
Step 5: To calculate the work done, you need to know the values of n, R, T, Vf, and Vi.
Step 6: Plug the values into the formula to find the work done by the gas.
