Defence Exams MCQ & Objective Questions
Defence Exams play a crucial role in shaping the future of aspiring candidates in India. These exams not only assess knowledge but also test the ability to apply concepts in real-world scenarios. Practicing MCQs and objective questions is essential for effective exam preparation, as it helps students identify important questions and enhances their understanding of key topics.
What You Will Practise Here
Fundamentals of Defence Studies
Key Historical Events and Their Impact
Important Defence Policies and Strategies
Current Affairs Related to National Security
Basic Concepts of Military Operations
Understanding Defence Technologies
Analysing Defence Budget and Expenditure
Exam Relevance
The topics covered in Defence Exams are highly relevant across various educational boards, including CBSE and State Boards, as well as competitive exams like NEET and JEE. Students can expect questions that focus on historical events, current affairs, and fundamental concepts related to defence. Common question patterns include multiple-choice questions that assess both theoretical knowledge and practical application.
Common Mistakes Students Make
Overlooking current affairs, which are often integrated into exam questions.
Confusing similar historical events or dates, leading to incorrect answers.
Neglecting the importance of definitions and key terms in objective questions.
Relying solely on rote memorization instead of understanding concepts.
FAQs
Question: What types of questions can I expect in Defence Exams?Answer: You can expect a mix of MCQs covering historical events, current affairs, and fundamental concepts related to defence.
Question: How can I improve my performance in Defence Exams?Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.
Start your journey towards success by solving practice MCQs today! Testing your understanding will not only boost your confidence but also prepare you for the important Defence Exams ahead.
Q. A 1 kg block of metal at 100°C is placed in 2 kg of water at 20°C. If the final temperature is 30°C, what is the specific heat capacity of the metal? (2023)
A.
0.5 J/kg°C
B.
1 J/kg°C
C.
2 J/kg°C
D.
4 J/kg°C
Show solution
Solution
Using conservation of energy: m1c1(T1 - Tf) = m2c2(Tf - T2), we find c1 = 2 J/kg°C.
Correct Answer:
C
— 2 J/kg°C
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Q. A 10 kg mass is lifted to a height of 5 m. What is the potential energy gained? (Take g = 10 m/s²)
A.
50 J
B.
100 J
C.
150 J
D.
200 J
Show solution
Solution
Potential energy PE = mgh = 10 kg * 10 m/s² * 5 m = 500 J.
Correct Answer:
B
— 100 J
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Q. A 10 kg object is dropped from a height of 5 m. What is its speed just before it hits the ground? (Use g = 9.8 m/s²) (2021)
A.
10 m/s
B.
15 m/s
C.
20 m/s
D.
25 m/s
Show solution
Solution
Using energy conservation, Potential Energy = Kinetic Energy at the ground. mgh = (1/2)mv². v = sqrt(2gh) = sqrt(2 × 9.8 m/s² × 5 m) ≈ 10 m/s.
Correct Answer:
B
— 15 m/s
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Q. A 10 kg object is lifted to a height of 5 m. What is the potential energy gained by the object? (Take g = 10 m/s²)
A.
50 J
B.
100 J
C.
150 J
D.
200 J
Show solution
Solution
Potential energy PE = mgh = 10 kg × 10 m/s² × 5 m = 500 J.
Correct Answer:
B
— 100 J
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Q. A 10 kg object is lifted to a height of 5 m. What is the potential energy gained? (Take g = 10 m/s²)
A.
50 J
B.
100 J
C.
150 J
D.
200 J
Show solution
Solution
Potential energy PE = mgh = 10 kg * 10 m/s² * 5 m = 500 J.
Correct Answer:
D
— 200 J
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Q. A 10 kg object is lifted to a height of 5 m. What is the potential energy gained? (Take g = 9.8 m/s²) (2021)
A.
490 J
B.
980 J
C.
390 J
D.
590 J
Show solution
Solution
Potential Energy (PE) = mgh = 10 kg × 9.8 m/s² × 5 m = 490 J.
Correct Answer:
B
— 980 J
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Q. A 10 kg object is lifted to a height of 5 m. What is the work done against gravity? (Take g = 10 m/s²)
A.
50 J
B.
100 J
C.
150 J
D.
200 J
Show solution
Solution
Work done W = mgh = 10 kg × 10 m/s² × 5 m = 500 J.
Correct Answer:
B
— 100 J
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Q. A 10 kg object is moving with a speed of 2 m/s. What is its momentum?
A.
20 kg·m/s
B.
10 kg·m/s
C.
5 kg·m/s
D.
15 kg·m/s
Show solution
Solution
Momentum (p) = mass × velocity = 10 kg × 2 m/s = 20 kg·m/s.
Correct Answer:
A
— 20 kg·m/s
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Q. A 10 kg object is moving with a speed of 5 m/s. What is its momentum? (2022)
A.
50 kg m/s
B.
10 kg m/s
C.
25 kg m/s
D.
15 kg m/s
Show solution
Solution
Momentum = mass × velocity = 10 kg × 5 m/s = 50 kg m/s.
Correct Answer:
A
— 50 kg m/s
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Q. A 10 kg object is moving with a velocity of 5 m/s. What is its kinetic energy?
A.
125 J
B.
50 J
C.
100 J
D.
75 J
Show solution
Solution
Kinetic energy KE = (1/2)mv² = (1/2)(10)(5²) = 125 J.
Correct Answer:
A
— 125 J
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Q. A 100 g piece of metal at 150°C is placed in 200 g of water at 25°C. What is the final temperature of the system assuming no heat loss? (2019)
A.
30°C
B.
40°C
C.
50°C
D.
60°C
Show solution
Solution
Using the principle of conservation of energy, we can calculate the final temperature to be 50°C.
Correct Answer:
C
— 50°C
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Q. A 15-meter tall tree casts a shadow of 10 meters. What is the angle of elevation of the sun? (2019)
A.
30 degrees
B.
45 degrees
C.
60 degrees
D.
75 degrees
Show solution
Solution
tan(θ) = height/shadow = 15/10 = 1.5, θ = tan⁻¹(1.5) ≈ 56.31 degrees, which is closest to 60 degrees.
Correct Answer:
C
— 60 degrees
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Q. A 2 kg object is dropped from a height of 10 m. What is its speed just before it hits the ground? (Use g = 9.8 m/s²) (2021)
A.
14 m/s
B.
20 m/s
C.
10 m/s
D.
15 m/s
Show solution
Solution
Using energy conservation, PE = KE: mgh = 0.5mv². Solving gives v = √(2gh) = √(2 × 9.8 m/s² × 10 m) = 14 m/s.
Correct Answer:
A
— 14 m/s
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Q. A 2 kg object is heated from 20°C to 80°C. If the specific heat capacity is 0.5 J/g°C, how much heat is absorbed? (2019)
A.
60 kJ
B.
80 kJ
C.
100 kJ
D.
120 kJ
Show solution
Solution
Heat absorbed (Q) = mcΔT = (2000 g)(0.5 J/g°C)(60°C) = 60,000 J = 60 kJ.
Correct Answer:
B
— 80 kJ
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Q. A 2 kg piece of copper (specific heat = 0.385 J/g°C) is heated from 25°C to 75°C. How much heat is absorbed? (2022)
A.
2000 J
B.
3000 J
C.
4000 J
D.
5000 J
Show solution
Solution
Q = mcΔT = 2000 g * 0.385 J/g°C * (75°C - 25°C) = 38500 J.
Correct Answer:
B
— 3000 J
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Q. A 2 kg piece of iron at 150°C is placed in 1 kg of water at 20°C. What will be the final temperature of the system? (Specific heat of iron = 0.45 J/g°C, water = 4.18 J/g°C) (2023)
A.
25°C
B.
30°C
C.
35°C
D.
40°C
Show solution
Solution
Using heat transfer equations, we find the final temperature to be approximately 35°C.
Correct Answer:
C
— 35°C
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Q. A 5 kg block of metal is heated from 20°C to 100°C. If the specific heat capacity of the metal is 0.5 J/g°C, how much heat is required? (2023)
A.
2000 J
B.
2500 J
C.
3000 J
D.
3500 J
Show solution
Solution
Heat (Q) = m * c * ΔT = 5000 g * 0.5 J/g°C * (100°C - 20°C) = 5000 * 0.5 * 80 = 200000 J = 2000 J.
Correct Answer:
C
— 3000 J
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Q. A 5 kg object is dropped from a height of 10 m. What is its potential energy at the top? (Take g = 9.8 m/s²) (2020)
A.
49 J
B.
98 J
C.
39 J
D.
59 J
Show solution
Solution
Potential Energy (PE) = mgh = 5 kg × 9.8 m/s² × 10 m = 490 J.
Correct Answer:
B
— 98 J
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Q. A 5 kg object is dropped from a height of 10 m. What is its speed just before it hits the ground? (Use g = 9.8 m/s²) (2021)
A.
14 m/s
B.
20 m/s
C.
10 m/s
D.
15 m/s
Show solution
Solution
Using energy conservation, Potential Energy = Kinetic Energy. mgh = 1/2 mv². v = √(2gh) = √(2 × 9.8 m/s² × 10 m) = 14 m/s.
Correct Answer:
A
— 14 m/s
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Q. A 5 kg object is dropped from a height of 20 m. What is its velocity just before it hits the ground? (Take g = 10 m/s²)
A.
10 m/s
B.
20 m/s
C.
15 m/s
D.
25 m/s
Show solution
Solution
Using the formula v² = u² + 2gh, where u = 0, we have v = √(0 + 2*10*20) = √400 = 20 m/s.
Correct Answer:
B
— 20 m/s
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Q. A 5 kg object is lifted to a height of 10 m. What is the potential energy gained by the object? (Take g = 10 m/s²)
A.
50 J
B.
100 J
C.
150 J
D.
200 J
Show solution
Solution
Potential energy PE = mgh = 5 kg * 10 m/s² * 10 m = 500 J.
Correct Answer:
B
— 100 J
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Q. A 50 kg object is moving with a velocity of 10 m/s. What is its kinetic energy? (2022)
A.
2500 J
B.
500 J
C.
1000 J
D.
2000 J
Show solution
Solution
Kinetic energy KE = (1/2)mv² = (1/2)(50)(10²) = 2500 J.
Correct Answer:
A
— 2500 J
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Q. A bag contains 4 white and 6 black balls. If one ball is drawn at random, what is the probability that it is not black?
A.
2/5
B.
1/5
C.
1/2
D.
4/10
Show solution
Solution
Total balls = 4 + 6 = 10. Probability of not drawing a black ball = Number of white balls / Total balls = 4/10 = 2/5.
Correct Answer:
A
— 2/5
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Q. A bag contains 4 white balls and 6 black balls. If one ball is drawn at random, what is the probability that it is not black?
A.
2/5
B.
3/5
C.
4/5
D.
1/5
Show solution
Solution
Total balls = 4 + 6 = 10. Probability of not drawing a black ball = Number of white balls / Total balls = 4/10 = 2/5.
Correct Answer:
C
— 4/5
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Q. A bag contains 4 white balls and 6 black balls. If one ball is drawn at random, what is the probability that it is black?
A.
2/5
B.
3/5
C.
4/5
D.
1/5
Show solution
Solution
The total number of balls is 4 + 6 = 10. The number of black balls is 6. Therefore, the probability of drawing a black ball is 6/10 = 3/5.
Correct Answer:
B
— 3/5
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Q. A bag contains 4 white, 3 black, and 5 red balls. If one ball is drawn at random, what is the probability that it is not black?
A.
1/4
B.
3/4
C.
5/12
D.
2/3
Show solution
Solution
Total balls = 4 + 3 + 5 = 12. Non-black balls = 4 + 5 = 9. Probability = Non-black balls / Total balls = 9/12 = 3/4.
Correct Answer:
B
— 3/4
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Q. A bag contains 4 white, 5 black, and 6 red balls. If one ball is drawn at random, what is the probability that it is not black?
A.
1/3
B.
2/3
C.
5/11
D.
7/11
Show solution
Solution
Total balls = 4 + 5 + 6 = 15. Non-black balls = 4 + 6 = 10. Probability = Non-black balls / Total balls = 10/15 = 2/3.
Correct Answer:
D
— 7/11
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Q. A bag contains 5 red balls and 3 blue balls. What is the probability of drawing a red ball? (2022)
A.
3/8
B.
5/8
C.
1/2
D.
1/3
Show solution
Solution
Total balls = 5 + 3 = 8. Probability of red ball = Number of red balls / Total balls = 5/8.
Correct Answer:
B
— 5/8
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Q. A balanced diet consists of 50% carbohydrates, 30% proteins, and 20% fats. If a person consumes 2400 calories, how many calories are from carbohydrates?
A.
1000 calories
B.
1200 calories
C.
1400 calories
D.
1600 calories
Show solution
Solution
50% of 2400 calories = 0.50 * 2400 = 1200 calories.
Correct Answer:
B
— 1200 calories
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Q. A balanced diet should consist of what percentage of carbohydrates, proteins, and fats respectively? (2021)
A.
50%, 30%, 20%
B.
60%, 25%, 15%
C.
40%, 40%, 20%
D.
70%, 20%, 10%
Show solution
Solution
A balanced diet typically consists of 60% carbohydrates, 25% proteins, and 15% fats.
Correct Answer:
B
— 60%, 25%, 15%
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