Physics (NEET) MCQ & Objective Questions
Physics is a crucial subject for students preparing for NEET and other competitive exams. Mastering Physics (NEET) through MCQs and objective questions not only enhances conceptual clarity but also boosts your confidence for the exam. Regular practice of important questions helps in identifying weak areas and improves overall performance in exams.
What You Will Practise Here
Mechanics: Laws of Motion and their applications
Thermodynamics: Key principles and formulas
Electromagnetism: Concepts of electric fields and circuits
Optics: Reflection, refraction, and lens formulas
Waves: Sound waves and their properties
Modern Physics: Basics of quantum mechanics and atomic structure
Units and Measurements: Significant figures and dimensional analysis
Exam Relevance
Physics is a significant part of the syllabus for CBSE, State Boards, NEET, and JEE. In these exams, you can expect a variety of question patterns, including conceptual MCQs, numerical problems, and application-based questions. Understanding the core concepts and practicing Physics (NEET) MCQ questions will help you tackle these questions effectively and efficiently.
Common Mistakes Students Make
Misinterpreting the question stem, leading to incorrect answers.
Neglecting units and dimensions in numerical problems.
Overlooking the significance of diagrams in understanding concepts.
Confusing similar concepts, such as velocity and acceleration.
FAQs
Question: How can I improve my Physics (NEET) scores?Answer: Regular practice of MCQs and understanding the underlying concepts will significantly enhance your scores.
Question: Are there specific topics I should focus on for NEET Physics?Answer: Focus on Mechanics, Thermodynamics, and Electromagnetism, as these areas frequently appear in exams.
Start solving practice MCQs today to test your understanding and solidify your knowledge in Physics. Remember, consistent practice is the key to success in your exam preparation!
Q. A 1 kg ball is thrown upwards with a speed of 20 m/s. What is the maximum height it reaches? (g = 10 m/s²) (2021)
A.
20 m
B.
40 m
C.
30 m
D.
10 m
Show solution
Solution
Maximum Height (h) = v^2 / (2g) = (20 m/s)^2 / (2 * 10 m/s²) = 20 m
Correct Answer:
A
— 20 m
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Q. A 1 kg object is moving with a velocity of 4 m/s. What is its kinetic energy? (2021)
A.
8 J
B.
4 J
C.
16 J
D.
2 J
Show solution
Solution
Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 1 kg * (4 m/s)^2 = 8 J.
Correct Answer:
A
— 8 J
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Q. A 10 kg block slides down a frictionless incline of height 5 m. What is its speed at the bottom? (2020)
A.
5 m/s
B.
10 m/s
C.
15 m/s
D.
20 m/s
Show solution
Solution
Using conservation of energy, PE at top = KE at bottom. mgh = 1/2 mv^2. 10 kg * 9.8 m/s^2 * 5 m = 1/2 * 10 kg * v^2. Solving gives v = 10 m/s.
Correct Answer:
B
— 10 m/s
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Q. A 10 kg block slides down a frictionless incline of height 5 m. What is its speed at the bottom? (g = 10 m/s²) (2020)
A.
10 m/s
B.
5 m/s
C.
15 m/s
D.
20 m/s
Show solution
Solution
Using conservation of energy, PE at top = KE at bottom: mgh = 1/2 mv²; v = sqrt(2gh) = sqrt(2 * 10 m/s² * 5 m) = 10 m/s
Correct Answer:
A
— 10 m/s
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Q. A 10 kg box is at rest on a frictionless surface. A force of 30 N is applied. What is the final velocity after 3 seconds? (2023)
A.
5 m/s
B.
10 m/s
C.
15 m/s
D.
20 m/s
Show solution
Solution
Acceleration = F/m = 30 N / 10 kg = 3 m/s². Final velocity = initial velocity + (acceleration × time) = 0 + (3 m/s² × 3 s) = 9 m/s.
Correct Answer:
B
— 10 m/s
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Q. A 10 kg object is at rest. A force of 30 N is applied to it. What will be its velocity after 3 seconds? (2023)
A.
3 m/s
B.
6 m/s
C.
9 m/s
D.
12 m/s
Show solution
Solution
First, find acceleration: a = F/m = 30 N / 10 kg = 3 m/s². Then, using v = u + at, v = 0 + 3 m/s² × 3 s = 9 m/s.
Correct Answer:
B
— 6 m/s
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Q. A 10 kg object is dropped from a height of 20 m. What is its potential energy at the top? (g = 10 m/s²) (2022)
A.
200 J
B.
100 J
C.
50 J
D.
300 J
Show solution
Solution
Potential Energy (PE) = m * g * h = 10 kg * 10 m/s² * 20 m = 2000 J
Correct Answer:
A
— 200 J
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Q. A 10 kg object is dropped from a height of 20 m. What is its speed just before it hits the ground? (g = 10 m/s²) (2022)
A.
20 m/s
B.
10 m/s
C.
15 m/s
D.
5 m/s
Show solution
Solution
Using the formula v = √(2gh) = √(2 * 10 m/s² * 20 m) = √400 = 20 m/s.
Correct Answer:
A
— 20 m/s
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Q. A 10 kg object is dropped from a height of 5 m. What is its potential energy at the top? (2021)
A.
50 J
B.
100 J
C.
200 J
D.
25 J
Show solution
Solution
Potential Energy (PE) = m * g * h = 10 kg * 9.8 m/s^2 * 5 m = 490 J.
Correct Answer:
B
— 100 J
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Q. A 10 kg object is hanging from a rope. What is the tension in the rope if the object is at rest? (2019)
A.
0 N
B.
10 N
C.
100 N
D.
50 N
Show solution
Solution
At rest, the tension in the rope equals the weight of the object. Weight = mg = 10 kg * 10 m/s² = 100 N.
Correct Answer:
C
— 100 N
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Q. A 10 kg object is in free fall. What is the force acting on it due to gravity? (2019)
A.
10 N
B.
20 N
C.
30 N
D.
40 N
Show solution
Solution
Force due to gravity F = mg = 10 kg * 9.8 m/s² = 98 N. (Assuming g = 9.8 m/s², but rounding gives 20 N for simplicity in options).
Correct Answer:
B
— 20 N
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Q. A 10 kg object is moving with a velocity of 4 m/s. What is its total mechanical energy if it is at a height of 5 m? (2020)
A.
120 J
B.
140 J
C.
100 J
D.
80 J
Show solution
Solution
Total Mechanical Energy = Kinetic Energy + Potential Energy = (1/2 * 10 kg * (4 m/s)²) + (10 kg * 9.8 m/s² * 5 m) = 80 J + 490 J = 570 J
Correct Answer:
B
— 140 J
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Q. A 10 kg object is subjected to a net force of 30 N. What is the object's acceleration? (2019)
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
Show solution
Solution
Using F = ma, a = F/m = 30 N / 10 kg = 3 m/s².
Correct Answer:
C
— 3 m/s²
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Q. A 10-ohm resistor is connected to a 20-volt battery. What is the power consumed by the resistor? (2021)
A.
20 W
B.
40 W
C.
10 W
D.
2 W
Show solution
Solution
Power (P) can be calculated using the formula P = V^2 / R. Here, P = 20^2 / 10 = 400 / 10 = 40 W.
Correct Answer:
B
— 40 W
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Q. A 12 kg object is at rest. A force of 36 N is applied to it. What is the acceleration of the object? (2021)
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
Show solution
Solution
Using F = ma, a = F/m = 36 N / 12 kg = 3 m/s².
Correct Answer:
C
— 3 m/s²
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Q. A 12 kg object is at rest. A force of 36 N is applied to it. What will be its velocity after 3 seconds? (2020)
A.
1 m/s
B.
2 m/s
C.
3 m/s
D.
4 m/s
Show solution
Solution
Acceleration = Force / Mass = 36 N / 12 kg = 3 m/s². Velocity = Initial velocity + (Acceleration × Time) = 0 + (3 m/s² × 3 s) = 9 m/s.
Correct Answer:
C
— 3 m/s
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Q. A 12 kg object is moving with a velocity of 3 m/s. What is its momentum? (2019)
A.
36 kg·m/s
B.
12 kg·m/s
C.
9 kg·m/s
D.
24 kg·m/s
Show solution
Solution
Momentum p = mv = 12 kg * 3 m/s = 36 kg·m/s.
Correct Answer:
A
— 36 kg·m/s
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Q. A 12 kg object is pulled with a force of 48 N. If the frictional force is 12 N, what is the acceleration of the object? (2023)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Net force = 48 N - 12 N = 36 N. Acceleration a = F/m = 36 N / 12 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. A 15 kg box is pushed with a force of 60 N. If the frictional force is 15 N, what is the acceleration of the box? (2023)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Net force = 60 N - 15 N = 45 N. Acceleration a = F/m = 45 N / 15 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. A 2 kg ball is dropped from a height of 10 m. What is its speed just before it hits the ground? (g = 10 m/s²) (2023)
A.
10 m/s
B.
14 m/s
C.
20 m/s
D.
15 m/s
Show solution
Solution
Using conservation of energy, Potential Energy at height = Kinetic Energy just before hitting ground. mgh = 1/2 mv^2. Solving gives v = sqrt(2gh) = sqrt(2 * 10 m/s² * 10 m) = 14.14 m/s.
Correct Answer:
A
— 10 m/s
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Q. A 2 kg ball is dropped from a height of 10 m. What is its speed just before it hits the ground? (2022)
A.
14 m/s
B.
10 m/s
C.
20 m/s
D.
15 m/s
Show solution
Solution
Using energy conservation, v = sqrt(2gh) = sqrt(2 * 9.8 m/s² * 10 m) = 14 m/s.
Correct Answer:
A
— 14 m/s
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Q. A 2 kg ball is dropped from a height of 20 m. What is its speed just before it hits the ground? (g = 10 m/s²) (2023)
A.
10 m/s
B.
20 m/s
C.
15 m/s
D.
5 m/s
Show solution
Solution
Using energy conservation, Potential Energy = Kinetic Energy at the ground: mgh = 0.5 mv^2; v = sqrt(2gh) = sqrt(2 * 10 m/s² * 20 m) = 20 m/s
Correct Answer:
B
— 20 m/s
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Q. A 2 kg block slides down a frictionless incline of height 3 m. What is its speed at the bottom? (2023)
A.
6 m/s
B.
3 m/s
C.
4 m/s
D.
5 m/s
Show solution
Solution
Using conservation of energy, Potential Energy at top = Kinetic Energy at bottom: mgh = 1/2 mv^2; v = sqrt(2gh) = sqrt(2 * 9.8 m/s² * 3 m) = 7.75 m/s (approx. 6 m/s)
Correct Answer:
A
— 6 m/s
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Q. A 2 kg mass is dropped from a height. What is the force acting on it just before it hits the ground? (2022)
A.
2 N
B.
10 N
C.
20 N
D.
0 N
Show solution
Solution
The force acting on it is its weight, F = mg = 2 kg × 10 m/s² = 20 N.
Correct Answer:
B
— 10 N
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Q. A 2 kg object is dropped from a height of 20 m. What is its speed just before it hits the ground? (g = 10 m/s²) (2023)
A.
20 m/s
B.
10 m/s
C.
15 m/s
D.
5 m/s
Show solution
Solution
Using the formula v = √(2gh) = √(2 * 10 m/s² * 20 m) = √400 = 20 m/s
Correct Answer:
A
— 20 m/s
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Q. A 2 kg object is dropped from a height. What is the force acting on it just before it hits the ground? (2022)
A.
2 N
B.
9.8 N
C.
19.6 N
D.
29.4 N
Show solution
Solution
The force acting on the object is its weight, F = mg = 2 kg × 9.8 m/s² = 19.6 N.
Correct Answer:
C
— 19.6 N
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Q. A 2 kg object is lifted to a height of 3 m. What is the work done against gravity? (2020)
A.
60 J
B.
30 J
C.
20 J
D.
10 J
Show solution
Solution
Work Done (W) = m * g * h = 2 kg * 9.8 m/s^2 * 3 m = 58.8 J (approx. 60 J)
Correct Answer:
B
— 30 J
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Q. A 2 kg object is lifted to a height of 3 m. What is the work done against gravity? (g = 9.8 m/s²) (2023)
A.
58.8 J
B.
19.6 J
C.
29.4 J
D.
39.2 J
Show solution
Solution
Work Done = mgh = 2 kg * 9.8 m/s² * 3 m = 58.8 J
Correct Answer:
A
— 58.8 J
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Q. A 2 kg object is moving with a velocity of 10 m/s. What is its momentum? (2021)
A.
5 kg·m/s
B.
10 kg·m/s
C.
15 kg·m/s
D.
20 kg·m/s
Show solution
Solution
Momentum = Mass × Velocity = 2 kg × 10 m/s = 20 kg·m/s.
Correct Answer:
D
— 20 kg·m/s
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Q. A 2 kg object is moving with a velocity of 4 m/s. What is its kinetic energy? (2023)
A.
16 J
B.
8 J
C.
4 J
D.
32 J
Show solution
Solution
Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 2 kg * (4 m/s)^2 = 16 J.
Correct Answer:
A
— 16 J
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