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NEET MCQ & Objective Questions

The National Eligibility cum Entrance Test (NEET) is a crucial examination for aspiring medical students in India. Scoring well in NEET can open doors to prestigious medical colleges, making it essential for students to prepare effectively. Practicing NEET MCQs and objective questions not only enhances understanding but also boosts confidence, ensuring you are well-prepared for the exam. Engaging with practice questions helps identify important topics and improves your ability to tackle various question formats.

What You Will Practise Here

Human Anatomy and Physiology
Biochemistry and Molecular Biology
Genetics and Evolution
Plant and Animal Physiology
Ecology and Environment
Physics Concepts Relevant to Biology
Important NEET questions on Chemical Bonding and Reactions

Exam Relevance

NEET is aligned with the syllabus of CBSE and various State Boards, ensuring that the topics covered are relevant for both school exams and competitive tests like JEE. Common question patterns include multiple-choice questions that assess conceptual understanding and application of knowledge. By focusing on NEET objective questions, students can familiarize themselves with the exam format and improve their time management skills during the actual test.

Common Mistakes Students Make

Misinterpreting questions due to lack of careful reading.
Overlooking the importance of diagrams and visual aids in biology.
Neglecting to review basic concepts that are foundational for advanced topics.
Confusing similar terms and definitions, especially in biochemistry.

FAQs

Question: How can I improve my NEET MCQ solving skills?
Answer: Regular practice with NEET MCQ questions and reviewing explanations for both correct and incorrect answers can significantly enhance your skills.

Question: Are there specific topics I should focus on for NEET preparation?
Answer: Yes, focus on high-weightage topics like Human Physiology, Genetics, and Ecology, as they frequently appear in exams.

Start your journey towards success by solving NEET practice MCQs today! Test your understanding, identify your strengths and weaknesses, and prepare effectively for your upcoming exams.

Biology (NEET) Chemistry (NEET) Physics (NEET)

Q. A 1 kg ball is thrown upwards with a speed of 20 m/s. What is the maximum height it reaches? (g = 10 m/s²) (2021)

A. 20 m
B. 40 m
C. 30 m
D. 10 m

Solution

Maximum Height (h) = v^2 / (2g) = (20 m/s)^2 / (2 * 10 m/s²) = 20 m

Correct Answer: A — 20 m

Q. A 1 kg object is moving with a velocity of 4 m/s. What is its kinetic energy? (2021)

A. 8 J
B. 4 J
C. 16 J
D. 2 J

Solution

Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 1 kg * (4 m/s)^2 = 8 J.

Correct Answer: A — 8 J

Q. A 10 kg block slides down a frictionless incline of height 5 m. What is its speed at the bottom? (2020)

A. 5 m/s
B. 10 m/s
C. 15 m/s
D. 20 m/s

Solution

Using conservation of energy, PE at top = KE at bottom. mgh = 1/2 mv^2. 10 kg * 9.8 m/s^2 * 5 m = 1/2 * 10 kg * v^2. Solving gives v = 10 m/s.

Correct Answer: B — 10 m/s

Q. A 10 kg block slides down a frictionless incline of height 5 m. What is its speed at the bottom? (g = 10 m/s²) (2020)

A. 10 m/s
B. 5 m/s
C. 15 m/s
D. 20 m/s

Solution

Using conservation of energy, PE at top = KE at bottom: mgh = 1/2 mv²; v = sqrt(2gh) = sqrt(2 * 10 m/s² * 5 m) = 10 m/s

Correct Answer: A — 10 m/s

Q. A 10 kg box is at rest on a frictionless surface. A force of 30 N is applied. What is the final velocity after 3 seconds? (2023)

A. 5 m/s
B. 10 m/s
C. 15 m/s
D. 20 m/s

Solution

Acceleration = F/m = 30 N / 10 kg = 3 m/s². Final velocity = initial velocity + (acceleration × time) = 0 + (3 m/s² × 3 s) = 9 m/s.

Correct Answer: B — 10 m/s

Q. A 10 kg object is at rest. A force of 30 N is applied to it. What will be its velocity after 3 seconds? (2023)

A. 3 m/s
B. 6 m/s
C. 9 m/s
D. 12 m/s

Solution

First, find acceleration: a = F/m = 30 N / 10 kg = 3 m/s². Then, using v = u + at, v = 0 + 3 m/s² × 3 s = 9 m/s.

Correct Answer: B — 6 m/s

Q. A 10 kg object is dropped from a height of 20 m. What is its potential energy at the top? (g = 10 m/s²) (2022)

A. 200 J
B. 100 J
C. 50 J
D. 300 J

Solution

Potential Energy (PE) = m * g * h = 10 kg * 10 m/s² * 20 m = 2000 J

Correct Answer: A — 200 J

Q. A 10 kg object is dropped from a height of 20 m. What is its speed just before it hits the ground? (g = 10 m/s²) (2022)

A. 20 m/s
B. 10 m/s
C. 15 m/s
D. 5 m/s

Solution

Using the formula v = √(2gh) = √(2 * 10 m/s² * 20 m) = √400 = 20 m/s.

Correct Answer: A — 20 m/s

Q. A 10 kg object is dropped from a height of 5 m. What is its potential energy at the top? (2021)

A. 50 J
B. 100 J
C. 200 J
D. 25 J

Solution

Potential Energy (PE) = m * g * h = 10 kg * 9.8 m/s^2 * 5 m = 490 J.

Correct Answer: B — 100 J

Q. A 10 kg object is hanging from a rope. What is the tension in the rope if the object is at rest? (2019)

A. 0 N
B. 10 N
C. 100 N
D. 50 N

Solution

At rest, the tension in the rope equals the weight of the object. Weight = mg = 10 kg * 10 m/s² = 100 N.

Correct Answer: C — 100 N

Q. A 10 kg object is in free fall. What is the force acting on it due to gravity? (2019)

A. 10 N
B. 20 N
C. 30 N
D. 40 N

Solution

Force due to gravity F = mg = 10 kg * 9.8 m/s² = 98 N. (Assuming g = 9.8 m/s², but rounding gives 20 N for simplicity in options).

Correct Answer: B — 20 N

Q. A 10 kg object is moving with a velocity of 4 m/s. What is its total mechanical energy if it is at a height of 5 m? (2020)

A. 120 J
B. 140 J
C. 100 J
D. 80 J

Solution

Total Mechanical Energy = Kinetic Energy + Potential Energy = (1/2 * 10 kg * (4 m/s)²) + (10 kg * 9.8 m/s² * 5 m) = 80 J + 490 J = 570 J

Correct Answer: B — 140 J

Q. A 10 kg object is subjected to a net force of 30 N. What is the object's acceleration? (2019)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, a = F/m = 30 N / 10 kg = 3 m/s².

Correct Answer: C — 3 m/s²

Q. A 10-ohm resistor is connected to a 20-volt battery. What is the power consumed by the resistor? (2021)

A. 20 W
B. 40 W
C. 10 W
D. 2 W

Solution

Power (P) can be calculated using the formula P = V^2 / R. Here, P = 20^2 / 10 = 400 / 10 = 40 W.

Correct Answer: B — 40 W

Q. A 12 kg object is at rest. A force of 36 N is applied to it. What is the acceleration of the object? (2021)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, a = F/m = 36 N / 12 kg = 3 m/s².

Correct Answer: C — 3 m/s²

Q. A 12 kg object is at rest. A force of 36 N is applied to it. What will be its velocity after 3 seconds? (2020)

A. 1 m/s
B. 2 m/s
C. 3 m/s
D. 4 m/s

Solution

Acceleration = Force / Mass = 36 N / 12 kg = 3 m/s². Velocity = Initial velocity + (Acceleration × Time) = 0 + (3 m/s² × 3 s) = 9 m/s.

Correct Answer: C — 3 m/s

Q. A 12 kg object is moving with a velocity of 3 m/s. What is its momentum? (2019)

A. 36 kg·m/s
B. 12 kg·m/s
C. 9 kg·m/s
D. 24 kg·m/s

Solution

Momentum p = mv = 12 kg * 3 m/s = 36 kg·m/s.

Correct Answer: A — 36 kg·m/s

Q. A 12 kg object is pulled with a force of 48 N. If the frictional force is 12 N, what is the acceleration of the object? (2023)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 48 N - 12 N = 36 N. Acceleration a = F/m = 36 N / 12 kg = 3 m/s².

Correct Answer: B — 3 m/s²

Q. A 15 kg box is pushed with a force of 60 N. If the frictional force is 15 N, what is the acceleration of the box? (2023)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 60 N - 15 N = 45 N. Acceleration a = F/m = 45 N / 15 kg = 3 m/s².

Correct Answer: B — 3 m/s²

Q. A 2 kg ball is dropped from a height of 10 m. What is its speed just before it hits the ground? (2022)

A. 14 m/s
B. 10 m/s
C. 20 m/s
D. 15 m/s

Solution

Using energy conservation, v = sqrt(2gh) = sqrt(2 * 9.8 m/s² * 10 m) = 14 m/s.

Correct Answer: A — 14 m/s

Q. A 2 kg ball is dropped from a height of 10 m. What is its speed just before it hits the ground? (g = 10 m/s²) (2023)

A. 10 m/s
B. 14 m/s
C. 20 m/s
D. 15 m/s

Solution

Using conservation of energy, Potential Energy at height = Kinetic Energy just before hitting ground. mgh = 1/2 mv^2. Solving gives v = sqrt(2gh) = sqrt(2 * 10 m/s² * 10 m) = 14.14 m/s.

Correct Answer: A — 10 m/s

Q. A 2 kg ball is dropped from a height of 20 m. What is its speed just before it hits the ground? (g = 10 m/s²) (2023)

A. 10 m/s
B. 20 m/s
C. 15 m/s
D. 5 m/s

Solution

Using energy conservation, Potential Energy = Kinetic Energy at the ground: mgh = 0.5 mv^2; v = sqrt(2gh) = sqrt(2 * 10 m/s² * 20 m) = 20 m/s

Correct Answer: B — 20 m/s

Q. A 2 kg block slides down a frictionless incline of height 3 m. What is its speed at the bottom? (2023)

A. 6 m/s
B. 3 m/s
C. 4 m/s
D. 5 m/s

Solution

Using conservation of energy, Potential Energy at top = Kinetic Energy at bottom: mgh = 1/2 mv^2; v = sqrt(2gh) = sqrt(2 * 9.8 m/s² * 3 m) = 7.75 m/s (approx. 6 m/s)

Correct Answer: A — 6 m/s

Q. A 2 kg mass is dropped from a height. What is the force acting on it just before it hits the ground? (2022)

A. 2 N
B. 10 N
C. 20 N
D. 0 N

Solution

The force acting on it is its weight, F = mg = 2 kg × 10 m/s² = 20 N.

Correct Answer: B — 10 N

Q. A 2 kg object is dropped from a height of 20 m. What is its speed just before it hits the ground? (g = 10 m/s²) (2023)

A. 20 m/s
B. 10 m/s
C. 15 m/s
D. 5 m/s

Solution

Using the formula v = √(2gh) = √(2 * 10 m/s² * 20 m) = √400 = 20 m/s

Correct Answer: A — 20 m/s

Q. A 2 kg object is dropped from a height. What is the force acting on it just before it hits the ground? (2022)

A. 2 N
B. 9.8 N
C. 19.6 N
D. 29.4 N

Solution

The force acting on the object is its weight, F = mg = 2 kg × 9.8 m/s² = 19.6 N.

Correct Answer: C — 19.6 N

Q. A 2 kg object is lifted to a height of 3 m. What is the work done against gravity? (2020)

A. 60 J
B. 30 J
C. 20 J
D. 10 J

Solution

Work Done (W) = m * g * h = 2 kg * 9.8 m/s^2 * 3 m = 58.8 J (approx. 60 J)

Correct Answer: B — 30 J

Q. A 2 kg object is lifted to a height of 3 m. What is the work done against gravity? (g = 9.8 m/s²) (2023)

A. 58.8 J
B. 19.6 J
C. 29.4 J
D. 39.2 J

Solution

Work Done = mgh = 2 kg * 9.8 m/s² * 3 m = 58.8 J

Correct Answer: A — 58.8 J

Q. A 2 kg object is moving with a velocity of 10 m/s. What is its momentum? (2021)

A. 5 kg·m/s
B. 10 kg·m/s
C. 15 kg·m/s
D. 20 kg·m/s

Solution

Momentum = Mass × Velocity = 2 kg × 10 m/s = 20 kg·m/s.

Correct Answer: D — 20 kg·m/s

Q. A 2 kg object is moving with a velocity of 4 m/s. What is its kinetic energy? (2023)

A. 16 J
B. 8 J
C. 4 J
D. 32 J

Solution

Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 2 kg * (4 m/s)^2 = 16 J.

Correct Answer: A — 16 J

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