Vector & 3D Geometry for Competitive Exam Preparation

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Vector & 3D Geometry

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Vector & 3D Geometry MCQ & Objective Questions

Understanding Vector & 3D Geometry is crucial for students preparing for various school and competitive exams. This topic not only enhances spatial reasoning but also forms the backbone of many important concepts in mathematics and physics. Practicing MCQs and objective questions in this area can significantly improve your exam scores and boost your confidence. Engaging with practice questions helps solidify your grasp of key concepts and prepares you for tackling important questions effectively.

What You Will Practise Here

Basics of vectors: definitions, types, and operations
Vector addition and subtraction: graphical and algebraic methods
Dot product and cross product: properties and applications
Equations of lines and planes in 3D space
Distance between points, lines, and planes
Applications of vectors in physics: force, velocity, and acceleration
Common theorems and formulas related to 3D geometry

Exam Relevance

Vector & 3D Geometry is a significant topic in CBSE, State Boards, NEET, and JEE exams. Students can expect questions that assess their understanding of vector operations, geometric interpretations, and problem-solving skills. Common question patterns include multiple-choice questions that require students to apply concepts to real-world scenarios, as well as numerical problems that test their computational abilities.

Common Mistakes Students Make

Confusing the dot product and cross product, leading to incorrect applications.
Misinterpreting the geometric representation of vectors, especially in 3D space.
Overlooking the significance of direction in vector addition and subtraction.
Failing to apply the correct formulas for distance calculations between geometric entities.

FAQs

Question: What are the key formulas I should remember for Vector & 3D Geometry?
Answer: Important formulas include the dot product formula, cross product formula, and distance formulas between points, lines, and planes.

Question: How can I improve my understanding of Vector & 3D Geometry concepts?
Answer: Regular practice of MCQs and solving objective questions will help reinforce your understanding and application of these concepts.

Start your journey towards mastering Vector & 3D Geometry today! Solve practice MCQs to test your understanding and enhance your exam preparation. Your success is just a question away!

3D Lines 3D Planes Scalar Product Vector Algebra Basics Vector Product

Q. Calculate the scalar product of A = (1, 1, 1) and B = (2, 2, 2).

A. 3
B. 4
C. 5
D. 6

Solution

A · B = 1*2 + 1*2 + 1*2 = 2 + 2 + 2 = 6.

Correct Answer: D — 6

Q. Calculate the scalar product of the vectors (1, 0, 0) and (0, 1, 0).

A. 0
B. 1
C. 2
D. 3

Solution

Scalar product = 1*0 + 0*1 + 0*0 = 0.

Correct Answer: A — 0

Q. Calculate the scalar product of the vectors (1, 2, 3) and (4, 5, 6).

A. 32
B. 33
C. 34
D. 35

Solution

Scalar product = 1*4 + 2*5 + 3*6 = 4 + 10 + 18 = 32.

Correct Answer: A — 32

Q. Calculate the scalar product of the vectors (2, 3, 4) and (4, 3, 2).

A. 28
B. 29
C. 30
D. 31

Solution

Scalar product = 2*4 + 3*3 + 4*2 = 8 + 9 + 8 = 25.

Correct Answer: A — 28

Q. Calculate the scalar product of the vectors (3, 0, -3) and (1, 2, 1).

A. 0
B. 1
C. 2
D. 3

Solution

Scalar product = 3*1 + 0*2 + (-3)*1 = 3 + 0 - 3 = 0.

Correct Answer: A — 0

Q. Calculate the scalar product of the vectors A = (1, 2, 3) and B = (4, 5, 6).

A. 32
B. 30
C. 28
D. 26

Solution

A · B = 1*4 + 2*5 + 3*6 = 4 + 10 + 18 = 32.

Correct Answer: B — 30

Q. Calculate the scalar product of the vectors A = (4, -1, 2) and B = (2, 3, 1).

A. 10
B. 8
C. 6
D. 12

Solution

A · B = 4*2 + (-1)*3 + 2*1 = 8 - 3 + 2 = 7.

Correct Answer: A — 10

Q. Calculate the scalar product of the vectors K = (0, 1, 2) and L = (3, 4, 5).

A. 10
B. 11
C. 12
D. 13

Solution

K · L = 0*3 + 1*4 + 2*5 = 0 + 4 + 10 = 14.

Correct Answer: A — 10

Q. Calculate the vector product of A = (3, 2, 1) and B = (1, 0, 2).

A. (4, 5, -2)
B. (2, 5, -3)
C. (2, -5, 3)
D. (5, -2, 3)

Solution

A × B = |i  j  k|\n|3  2  1|\n|1  0  2| = (4, 5, -2)

Correct Answer: A — (4, 5, -2)

Q. Determine the scalar product of the vectors (0, 1, 2) and (3, 4, 5).

A. 10
B. 11
C. 12
D. 13

Solution

Scalar product = 0*3 + 1*4 + 2*5 = 0 + 4 + 10 = 14.

Correct Answer: B — 11

Q. Determine the scalar product of the vectors A = (1, 1, 1) and B = (2, 2, 2).

A. 3
B. 4
C. 6
D. 8

Solution

A · B = 1*2 + 1*2 + 1*2 = 2 + 2 + 2 = 6.

Correct Answer: C — 6

Q. Determine the scalar product of the vectors A = (2, 2, 2) and B = (3, 3, 3).

A. 12
B. 18
C. 6
D. 9

Solution

A · B = 2*3 + 2*3 + 2*3 = 6 + 6 + 6 = 18.

Correct Answer: A — 12

Q. Find the angle between the vectors (1, 0, 0) and (0, 1, 0).

A. 0 degrees
B. 90 degrees
C. 45 degrees
D. 180 degrees

Solution

The angle θ = cos⁻¹((u · v) / (|u| |v|)) = cos⁻¹(0) = 90 degrees.

Correct Answer: B — 90 degrees

Q. Find the angle between the vectors A = (1, 2, 2) and B = (2, 0, 2).

A. 0°
B. 45°
C. 60°
D. 90°

Solution

cos(θ) = (A · B) / (|A| |B|). A · B = 1*2 + 2*0 + 2*2 = 6. |A| = √(1^2 + 2^2 + 2^2) = 3, |B| = √(2^2 + 0^2 + 2^2) = 2√2. cos(θ) = 6 / (3 * 2√2) = 1/√2, θ = 45°.

Correct Answer: C — 60°

Q. Find the angle between the vectors A = (1, 2, 2) and B = (2, 1, 1).

A. 60°
B. 45°
C. 30°
D. 90°

Solution

cos(θ) = (A · B) / (|A| |B|). A · B = 1*2 + 2*1 + 2*1 = 6; |A| = √(1^2 + 2^2 + 2^2) = 3; |B| = √(2^2 + 1^2 + 1^2) = √6. Thus, cos(θ) = 6 / (3√6) = 1/√6, θ = 45°.

Correct Answer: B — 45°

Q. Find the angle between the vectors A = (3, -2, 1) and B = (1, 1, 1) if A · B = |A||B|cos(θ).

A. 60°
B. 45°
C. 90°
D. 30°

Solution

A · B = 3*1 + (-2)*1 + 1*1 = 3 - 2 + 1 = 2. |A| = √(3^2 + (-2)^2 + 1^2) = √14, |B| = √3. cos(θ) = 2/(√14 * √3). θ = 60°.

Correct Answer: A — 60°

Q. Find the angle between the vectors A = (3, -2, 1) and B = (1, 1, 1).

A. 60°
B. 45°
C. 90°
D. 30°

Solution

cos(θ) = (A · B) / (|A| |B|). A · B = 3*1 + (-2)*1 + 1*1 = 2. |A| = √(3^2 + (-2)^2 + 1^2) = √14, |B| = √3. θ = cos^(-1)(2/(√14 * √3)).

Correct Answer: A — 60°

Q. Find the area of the triangle formed by the points A(1, 2, 3), B(4, 5, 6), and C(7, 8, 9) using the vector product.

A. 0
B. 1
C. 2
D. 3

Solution

Area = 0.5 * |AB × AC| = 0, as points are collinear.

Correct Answer: A — 0

Q. Find the cross product of vectors A = (1, 2, 3) and B = (4, 5, 6).

A. (-3, 6, -3)
B. (0, 0, 0)
C. (3, -6, 3)
D. (1, -2, 1)

Solution

Cross product A × B = |i  j  k| |1  2  3| |4  5  6| = (-3, 6, -3).

Correct Answer: A — (-3, 6, -3)

Q. Find the magnitude of the vector (3, 4).

A. 5
B. 7
C. 6
D. 4

Solution

Magnitude = √(3^2 + 4^2) = √(9 + 16) = √25 = 5.

Correct Answer: A — 5

Q. Find the magnitude of the vector v = (3, -4, 12).

A. 13
B. 14
C. 15
D. 12

Solution

Magnitude |v| = √(3^2 + (-4)^2 + 12^2) = √(9 + 16 + 144) = √169 = 13.

Correct Answer: B — 14

Q. Find the projection of vector A = (2, 3) onto vector B = (1, 1).

A. 1
B. 2
C. 3
D. 4

Solution

Projection of A onto B = (A · B) / |B|^2 * B; A · B = 2*1 + 3*1 = 5; |B|^2 = 1^2 + 1^2 = 2; Projection = (5/2)(1, 1) = (2.5, 2.5).

Correct Answer: A — 1

Q. Find the projection of vector A = (3, 4) onto vector B = (1, 2).

A. 1
B. 2
C. 3
D. 4

Solution

Projection of A onto B = (A · B) / |B|^2 * B. A · B = 3*1 + 4*2 = 11, |B|^2 = 1^2 + 2^2 = 5. Thus, projection = (11/5) * (1, 2) = (11/5, 22/5).

Correct Answer: B — 2

Q. Find the scalar product of A = (1, 2, 3) and B = (4, 5, 6).

A. 32
B. 30
C. 28
D. 26

Solution

A · B = 1*4 + 2*5 + 3*6 = 4 + 10 + 18 = 32.

Correct Answer: B — 30

Q. Find the scalar product of the vectors (3, -2, 5) and (1, 4, -1).

A. -1
B. 0
C. 1
D. 2

Solution

Scalar product = 3*1 + (-2)*4 + 5*(-1) = 3 - 8 - 5 = -10.

Correct Answer: A — -1

Q. Find the scalar product of the vectors (4, 5) and (1, 2).

A. 14
B. 13
C. 12
D. 11

Solution

Scalar product = 4*1 + 5*2 = 4 + 10 = 14.

Correct Answer: A — 14

Q. Find the scalar product of the vectors (7, 8, 9) and (0, 1, 2).

A. 26
B. 27
C. 28
D. 29

Solution

Scalar product = 7*0 + 8*1 + 9*2 = 0 + 8 + 18 = 26.

Correct Answer: A — 26

Q. Find the scalar product of the vectors A = (2, 3) and B = (4, -1).

A. -1
B. 5
C. 10
D. 11

Solution

A · B = 2*4 + 3*(-1) = 8 - 3 = 5.

Correct Answer: C — 10

Q. Find the scalar product of the vectors A = 5i + 12j and B = 3i - 4j.

A. -33
B. 33
C. 39
D. 45

Solution

A · B = (5)(3) + (12)(-4) = 15 - 48 = -33.

Correct Answer: A — -33

Q. Find the scalar product of the vectors G = (2, -3, 1) and H = (4, 0, -2).

A. -2
B. 0
C. 2
D. 8

Solution

G · H = 2*4 + (-3)*0 + 1*(-2) = 8 + 0 - 2 = 6.

Correct Answer: A — -2

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