Understanding the concept of mixtures is crucial for students preparing for various exams. Mixtures form a significant part of the syllabus, and practicing MCQs can enhance your grasp of this topic. By solving objective questions, you can identify important questions and improve your exam preparation, leading to better scores.
What You Will Practise Here
Definition and types of mixtures
Concentration and its calculations
Properties of mixtures vs. pure substances
Applications of mixtures in real-life scenarios
Key formulas related to mixtures
Separation techniques for mixtures
Common examples of mixtures in chemistry
Exam Relevance
The topic of mixtures is frequently tested in CBSE, State Boards, NEET, and JEE exams. Students can expect questions that require them to apply concepts to solve numerical problems or analyze scenarios involving mixtures. Common question patterns include calculating concentrations, identifying types of mixtures, and applying separation techniques.
Common Mistakes Students Make
Confusing mixtures with compounds and elements
Incorrectly calculating concentrations and ratios
Overlooking the importance of physical properties in mixtures
Misunderstanding separation techniques and their applications
FAQs
Question: What are the different types of mixtures? Answer: Mixtures can be classified into homogeneous and heterogeneous mixtures based on their composition.
Question: How do I calculate the concentration of a mixture? Answer: Concentration can be calculated using the formula: Concentration = (Amount of solute / Total amount of solution) x 100.
Now is the time to strengthen your understanding of mixtures! Dive into our practice MCQs and test your knowledge to excel in your exams. Remember, consistent practice is key to mastering this important topic!
Q. A container has 30 liters of a mixture of milk and water in the ratio 2:1. How much water is in the mixture?
A.
10 liters
B.
15 liters
C.
20 liters
D.
5 liters
Solution
In a 2:1 ratio, for every 3 parts, 1 part is water. Therefore, water = (1/3) * 30 = 10 liters.
Q. A container has 60 liters of a mixture of milk and water in the ratio of 2:1. If 12 liters of the mixture is replaced with water, what is the new ratio of milk to water?
A.
2:1
B.
1:2
C.
1:1
D.
3:2
Solution
Initially, milk = 40 liters, water = 20 liters. After removing 12 liters (8 liters milk and 4 liters water), we have 32 liters milk and 16 liters water. Adding 12 liters of water gives 32 liters milk and 28 liters water, resulting in a ratio of 32:28 or 8:7.
Q. A container has 60 liters of a solution that is 15% acid. If 10 liters of this solution is replaced with water, what is the new percentage of acid in the solution?
A.
10%
B.
12%
C.
15%
D.
18%
Solution
Initial acid = 0.15 * 60 = 9 liters. After removing 10 liters, acid left = 9 - 0.15 * 10 = 7.5 liters. New volume = 60 liters. New percentage = (7.5/60) * 100 = 12.5%.
Q. A container has 80 liters of a mixture of milk and water in the ratio 3:1. If 20 liters of the mixture is replaced with water, what is the new ratio of milk to water?
A.
2:1
B.
3:2
C.
5:3
D.
4:1
Solution
Initially, there are 60 liters of milk and 20 liters of water. After removing 20 liters, 15 liters of milk and 5 liters of water are removed. Adding 20 liters of water gives 60 liters of milk and 25 liters of water. New ratio = 60:25 = 12:5.
Q. A container has 80 liters of a solution that is 10% acid. If 20 liters of this solution is replaced with pure acid, what will be the new concentration of acid in the solution?
A.
15%
B.
20%
C.
25%
D.
30%
Solution
Initial acid = 10% of 80 = 8 liters. After removing 20 liters, acid left = 8 - 2 = 6 liters. Adding 20 liters of pure acid gives 6 + 20 = 26 liters of acid in 80 liters. New concentration = (26/80) * 100 = 32.5%.
Q. A mixture contains 30% alcohol and 70% water. If 10 liters of the mixture is taken out, how much alcohol is left in the mixture?
A.
3 liters
B.
4 liters
C.
5 liters
D.
6 liters
Solution
In 10 liters of the mixture, alcohol = 30% of 10 = 3 liters. If the original mixture was 10 liters, the remaining alcohol = 30% of (original volume - 10) = 30% of (10 - 10) = 0 liters. Thus, 3 liters of alcohol is removed, leaving 0 liters.
Q. A mixture contains 30% sugar and 70% water. If 5 liters of the mixture is taken out, how much sugar is left in the mixture?
A.
1.5 liters
B.
2 liters
C.
2.5 liters
D.
3 liters
Solution
In 5 liters of the mixture, sugar = 30% of 5 = 1.5 liters. If the original mixture was 5 liters, the remaining sugar = 30% of (original volume - 5) = 30% of (5 - 5) = 0 liters. Thus, 1.5 liters of sugar is removed, leaving 0 liters.
Q. A mixture of two grades of rice costs $20 per kg and $30 per kg. If a mixture is made with equal quantities of both, what is the cost per kg of the mixture?
Q. A mixture of two grades of rice costs $20 per kg and $30 per kg. If the mixture is sold at $25 per kg, what is the ratio of the two grades in the mixture?
A.
1:1
B.
1:2
C.
2:1
D.
3:2
Solution
Using alligation, (30-25)/(25-20) = 1/1. Ratio = 1:1.
Q. A mixture of two grades of rice costs $30 and $40 per kg. If a mixture of 10 kg is made with equal quantities, what is the cost per kg of the mixture?
