Calendar MCQ & Objective Questions
The topic of "Calendar" is crucial for students preparing for various school and competitive exams in India. Understanding calendars not only helps in solving objective questions but also enhances your overall exam preparation. Practicing Calendar MCQs and objective questions can significantly improve your ability to tackle important questions effectively, ensuring you score better in your exams.
What You Will Practise Here
Types of calendars: Gregorian, lunar, and fiscal calendars
Leap years and their significance
Calculating days of the week for given dates
Understanding the concept of months and their lengths
Important festivals and their corresponding dates
Calendar-related problems and their solutions
Diagrammatic representations of calendars
Exam Relevance
The Calendar topic is frequently included in the syllabus of CBSE, State Boards, NEET, and JEE exams. Students can expect questions that require them to calculate the day of the week for specific dates or identify leap years. Common question patterns include direct MCQs, fill-in-the-blanks, and scenario-based questions that test your understanding of calendar concepts.
Common Mistakes Students Make
Confusing leap years with regular years
Incorrectly calculating the day of the week for a given date
Overlooking the number of days in each month
Misunderstanding the significance of different types of calendars
FAQs
Question: What is a leap year?Answer: A leap year is a year that has one extra day added to keep the calendar year synchronized with the astronomical year. It occurs every four years.
Question: How do I calculate the day of the week for any date?Answer: You can use various methods, such as the Zeller's Congruence formula or counting backward from a known date.
Now is the time to enhance your understanding of the Calendar topic! Dive into our practice MCQs and test your knowledge to ensure you are well-prepared for your upcoming exams. Remember, consistent practice is the key to success!
Q. A bicycle covers a distance of 90 km in 3 hours. What is its average speed?
A.
25 km/h
B.
30 km/h
C.
35 km/h
D.
40 km/h
Show solution
Solution
Average speed = Total distance / Total time = 90 km / 3 h = 30 km/h.
Correct Answer:
B
— 30 km/h
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Q. A calendar is printed every year. If 5 calendars are printed in 5 years, how many are printed in 10 years?
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Solution
If 5 calendars are printed in 5 years, then in 10 years, 10 calendars will be printed.
Correct Answer:
A
— 10
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Q. A calendar is printed in 2023. How many days until the next leap year?
A.
365
B.
366
C.
730
D.
731
Show solution
Solution
The next leap year after 2023 is 2024, which is 1 year away, so 365 days.
Correct Answer:
A
— 365
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Q. A calendar is printed in 2023. How many Sundays will there be in the month of March 2023?
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Solution
March 2023 has 31 days, starting from Wednesday. There are 5 Sundays in March 2023.
Correct Answer:
B
— 5
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Q. A calendar is sold for $30 after a discount of 10%. What was the original price?
A.
$27
B.
$33
C.
$30
D.
$25
Show solution
Solution
Let the original price be x. Then, 90% of x = 30. So, x = 30 / 0.9 = $33.33
Correct Answer:
B
— $33
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Q. A calendar is sold for $45 after a 10% discount. What was the marked price?
A.
$50
B.
$55
C.
$60
D.
$45
Show solution
Solution
Let the marked price be x. Then, 90% of x = 45. So, x = 45 / 0.9 = $50
Correct Answer:
A
— $50
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Q. A calendar is sold for $45 after a 10% increase in price. What was the original price?
A.
$40
B.
$41
C.
$42
D.
$43
Show solution
Solution
Let the original price be x. Then, x + (10/100 * x) = 45. Solving gives x = $40.
Correct Answer:
A
— $40
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Q. A calendar is sold for $75 after a discount of 25%. What was the original price?
A.
$90
B.
$95
C.
$100
D.
$80
Show solution
Solution
Let the original price be x. Then, x - (25/100 * x) = 75. Solving gives x = $100.
Correct Answer:
A
— $90
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Q. A car travels 120 km in 2 hours. What is its average speed in km/h?
A.
50 km/h
B.
60 km/h
C.
70 km/h
D.
80 km/h
Show solution
Solution
Average speed = Total distance / Total time = 120 km / 2 h = 60 km/h.
Correct Answer:
B
— 60 km/h
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Q. A car travels 60 km in 1 hour. How long will it take to travel 180 km at the same speed?
A.
2 hours
B.
3 hours
C.
4 hours
D.
5 hours
Show solution
Solution
Time = Distance/Speed = 180 km / 60 km/h = 3 hours.
Correct Answer:
B
— 3 hours
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Q. A man can complete a work in 15 days. If he works for 3 days, how much work is left?
A.
1/5
B.
1/4
C.
1/3
D.
1/2
Show solution
Solution
Work done in 3 days = 3/15 = 1/5. Work left = 1 - 1/5 = 4/5.
Correct Answer:
C
— 1/3
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Q. A man can do a piece of work in 12 days. If he works for 4 days, what part of the work is left?
A.
1/3
B.
1/4
C.
2/3
D.
1/2
Show solution
Solution
In 4 days, he completes 4/12 = 1/3 of the work. Therefore, work left = 1 - 1/3 = 2/3.
Correct Answer:
C
— 2/3
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Q. A man invests $1000 at a compound interest rate of 5% per annum. What will be the amount after 2 years?
A.
$1100
B.
$1025
C.
$1050
D.
$1102.50
Show solution
Solution
Amount = P(1 + r)^n = 1000(1 + 0.05)^2 = 1000(1.1025) = $1102.50.
Correct Answer:
D
— $1102.50
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Q. A person invests $1000 at a simple interest rate of 5% per annum. How much interest will he earn in 3 years?
A.
$100
B.
$150
C.
$200
D.
$250
Show solution
Solution
Simple Interest = Principal * Rate * Time = $1000 * 5% * 3 = $1000 * 0.05 * 3 = $150.
Correct Answer:
A
— $100
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Q. A person spends 25% of his salary on rent and 15% on groceries. What percentage of his salary is left?
A.
60%
B.
70%
C.
75%
D.
80%
Show solution
Solution
Total spent = 25% + 15% = 40%. Salary left = 100% - 40% = 60%.
Correct Answer:
B
— 70%
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Q. A shopkeeper bought a watch for $200 and sold it for $250. What is the profit percentage?
A.
20%
B.
25%
C.
30%
D.
35%
Show solution
Solution
Profit = Selling Price - Cost Price = $250 - $200 = $50. Profit Percentage = (Profit / Cost Price) * 100 = ($50 / $200) * 100 = 25%.
Correct Answer:
B
— 25%
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Q. A shopkeeper sells an article for $240 after allowing a discount of 20%. What is the marked price?
A.
$300
B.
$250
C.
$280
D.
$320
Show solution
Solution
Let the marked price be x. Then, 240 = x - 0.2x => 240 = 0.8x => x = 240/0.8 = $300.
Correct Answer:
A
— $300
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Q. A shopkeeper sells an article for $240 after allowing a discount of 20%. What was the marked price?
A.
$300
B.
$280
C.
$250
D.
$320
Show solution
Solution
Let the marked price be x. Then, 240 = x - 0.2x => 240 = 0.8x => x = 240/0.8 = $300.
Correct Answer:
A
— $300
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Q. A train travels 300 km at a speed of 60 km/h. How long does it take to complete the journey?
A.
4 hours
B.
5 hours
C.
6 hours
D.
7 hours
Show solution
Solution
Time = Distance/Speed = 300 km / 60 km/h = 5 hours.
Correct Answer:
B
— 5 hours
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Q. How many days are there from January 1, 2020 to December 31, 2020?
A.
364
B.
365
C.
366
D.
367
Show solution
Solution
2020 is a leap year, so there are 366 days from January 1, 2020 to December 31, 2020.
Correct Answer:
C
— 366
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Q. How many days are there in the year 2024?
A.
365
B.
366
C.
367
D.
368
Show solution
Solution
2024 is a leap year, so it has 366 days.
Correct Answer:
B
— 366
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Q. How many leap years are there between 2000 and 2020, inclusive?
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Solution
The leap years between 2000 and 2020 are 2000, 2004, 2008, 2012, 2016, and 2020. That makes a total of 6 leap years.
Correct Answer:
A
— 5
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Q. How many leap years are there between 2000 and 2020?
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Solution
Leap years between 2000 and 2020 are 2000, 2004, 2008, 2012, 2016, and 2020. Total = 5 leap years.
Correct Answer:
B
— 5
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Q. If a calendar costs $120 and is sold at a loss of 15%, what is the selling price?
A.
$102
B.
$105
C.
$110
D.
$115
Show solution
Solution
Selling Price = Cost Price - Loss = 120 - (15/100 * 120) = 120 - 18 = $102.
Correct Answer:
A
— $102
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Q. If a calendar costs $15 and the seller wants a 30% profit, what should be the selling price?
A.
$19.50
B.
$20
C.
$18
D.
$17
Show solution
Solution
Profit = 30% of 15 = 4.5. Selling Price = Cost Price + Profit = 15 + 4.5 = $19.50
Correct Answer:
A
— $19.50
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Q. If a calendar costs $24 and is sold at a loss of 20%, what is the selling price?
A.
$20
B.
$22
C.
$18
D.
$24
Show solution
Solution
Loss = 20% of 24 = 4. Selling Price = Cost Price - Loss = 24 - 4 = $20
Correct Answer:
A
— $20
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Q. If a calendar is bought for $40 and sold for $50, what is the percentage profit?
A.
25%
B.
20%
C.
15%
D.
30%
Show solution
Solution
Profit = Selling Price - Cost Price = 50 - 40 = 10. Percentage Profit = (10/40) * 100 = 25%
Correct Answer:
A
— 25%
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Q. If a calendar is bought for $60 and sold for $72, what is the percentage gain?
A.
15%
B.
20%
C.
25%
D.
30%
Show solution
Solution
Gain = Selling Price - Cost Price = 72 - 60 = 12. Percentage Gain = (12/60) * 100 = 20%.
Correct Answer:
B
— 20%
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Q. If a calendar is bought for $80 and sold for $100, what is the percentage profit?
A.
20%
B.
25%
C.
30%
D.
15%
Show solution
Solution
Profit = Selling Price - Cost Price = 100 - 80 = 20. Percentage Profit = (20/80) * 100 = 25%.
Correct Answer:
B
— 25%
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Q. If a calendar is bought for $80 and sold for $100, what is the profit percentage?
A.
25%
B.
20%
C.
15%
D.
30%
Show solution
Solution
Profit = Selling Price - Cost Price = 100 - 80 = 20. Profit Percentage = (20/80) * 100 = 25%
Correct Answer:
B
— 20%
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