Heights and Distances Applications for Competitive Exams

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Heights and Distances Applications

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Heights and Distances Applications MCQ & Objective Questions

Heights and Distances Applications is a crucial topic in mathematics that plays a significant role in various exams. Mastering this area not only enhances your problem-solving skills but also boosts your confidence in tackling objective questions. Practicing MCQs and important questions related to Heights and Distances Applications can greatly improve your exam preparation and help you score better.

What You Will Practise Here

Understanding the basic concepts of heights and distances.
Application of trigonometric ratios in solving problems.
Formulas related to angles of elevation and depression.
Real-life applications of heights and distances in various scenarios.
Diagrams and representations to visualize problems effectively.
Common problem-solving techniques and strategies.
Practice questions with detailed solutions for better clarity.

Exam Relevance

The topic of Heights and Distances Applications is frequently included in CBSE, State Boards, NEET, and JEE exams. Students can expect questions that involve calculating heights using angles of elevation and depression. Common patterns include word problems that require you to interpret real-life situations mathematically, making it essential to understand the underlying concepts thoroughly.

Common Mistakes Students Make

Confusing angles of elevation with angles of depression.
Neglecting to draw diagrams, which can lead to misinterpretation of the problem.
Incorrectly applying trigonometric ratios in calculations.
Overlooking the units of measurement, leading to incorrect answers.
Rushing through calculations without verifying the results.

FAQs

Question: What are the key formulas for Heights and Distances Applications?
Answer: The key formulas include the relationships between angles of elevation and depression, and the use of sine, cosine, and tangent ratios to calculate heights and distances.

Question: How can I improve my accuracy in Heights and Distances MCQs?
Answer: Regular practice of MCQs, understanding the concepts, and reviewing common mistakes can significantly enhance your accuracy.

Start solving Heights and Distances Applications MCQ questions today to test your understanding and boost your exam readiness. Remember, practice makes perfect!

Q. A 12-meter tall building casts a shadow of 8 meters. What is the angle of elevation of the sun?

A. 36.87 degrees
B. 45 degrees
C. 53.13 degrees
D. 30 degrees

Solution

Using tan(θ) = height/shadow = 12/8 = 1.5, θ = tan⁻¹(1.5) ≈ 36.87 degrees.

Correct Answer: A — 36.87 degrees

Q. A building is 20 meters tall. If the angle of elevation from a point 10 meters away from the base of the building is θ, what is tan(θ)?

A. 2
B. 0.5
C. 1
D. 1.5

Solution

tan(θ) = height/distance = 20/10 = 2.

Correct Answer: A — 2

Q. A building is 20 meters tall. If the angle of elevation from a point on the ground 10 meters away from the base of the building is θ, what is tan(θ)?

A. 2
B. 0.5
C. 1
D. 1.5

Solution

tan(θ) = opposite/adjacent = 20/10 = 2.

Correct Answer: A — 2

Q. A kite is flying at a height of 40 meters. If the angle of elevation from a point on the ground to the kite is 60 degrees, how far is the point from the base of the kite?

A. 20√3 meters
B. 40 meters
C. 30 meters
D. 50 meters

Solution

Using tan(60) = 40/distance, distance = 40/tan(60) = 40/√3 = 20√3 meters.

Correct Answer: A — 20√3 meters

Q. A ladder 10 meters long leans against a wall. If the foot of the ladder is 6 meters away from the wall, what is the height at which the ladder touches the wall?

A. 8 meters
B. 6 meters
C. 10 meters
D. 4 meters

Solution

Using Pythagorean theorem: height = √(10² - 6²) = √(100 - 36) = √64 = 8 meters.

Correct Answer: A — 8 meters

Q. A ladder 25 meters long leans against a wall. If the foot of the ladder is 7 meters from the wall, what is the angle of elevation of the ladder?

A. 30 degrees
B. 45 degrees
C. 60 degrees
D. 75 degrees

Solution

Using cos(θ) = adjacent/hypotenuse, cos(θ) = 7/25. Therefore, θ = cos⁻¹(7/25) which is approximately 60 degrees.

Correct Answer: C — 60 degrees

Q. A person is standing 12 meters away from a vertical pole. If the angle of elevation to the top of the pole is 45 degrees, what is the height of the pole?

A. 12 meters
B. 6 meters
C. 8 meters
D. 10 meters

Solution

Using tan(45) = height / 12, height = 12 * tan(45) = 12 * 1 = 12 meters.

Correct Answer: A — 12 meters

Q. A person is standing 25 meters away from a vertical pole. If the angle of elevation to the top of the pole is 60 degrees, what is the height of the pole?

A. 25√3 meters
B. 15 meters
C. 20 meters
D. 30 meters

Solution

Using tan(60°) = height/25, height = 25 * √3 = 25√3 meters.

Correct Answer: A — 25√3 meters

Q. A person standing 30 meters away from a building observes the top of the building at an angle of elevation of 60 degrees. How tall is the building?

A. 15√3 meters
B. 30 meters
C. 20 meters
D. 25 meters

Solution

Using tan(60°) = height/30, height = 30 * √3 = 30√3 meters.

Correct Answer: A — 15√3 meters

Q. A person standing 50 meters away from a building observes the top of the building at an angle of elevation of 60 degrees. How tall is the building?

A. 25√3 meters
B. 50 meters
C. 30 meters
D. 40 meters

Solution

Using tan(60) = height / 50, height = 50 * tan(60) = 50 * √3 = 25√3 meters.

Correct Answer: A — 25√3 meters

Q. A tree casts a shadow of 15 meters when the angle of elevation of the sun is 30 degrees. How tall is the tree?

A. 5√3 meters
B. 15 meters
C. 10 meters
D. 7.5 meters

Solution

Using the tangent function, tan(30) = height / 15. Therefore, height = 15 * tan(30) = 15 * (1/√3) = 5√3 meters.

Correct Answer: A — 5√3 meters

Q. From a point 25 meters away from the base of a building, the angle of elevation to the top of the building is 30 degrees. What is the height of the building?

A. 25/√3 meters
B. 15 meters
C. 20 meters
D. 10 meters

Solution

Using tan(30) = height / 25, height = 25 * tan(30) = 25 * (1/√3) = 25/√3 meters.

Correct Answer: A — 25/√3 meters

Q. From a point 30 meters away from the base of a tower, the angle of elevation to the top of the tower is 45 degrees. What is the height of the tower?

A. 30 meters
B. 45 meters
C. 60 meters
D. 15 meters

Solution

Using tan(45) = height / 30, we have height = 30 * tan(45) = 30 * 1 = 30 meters.

Correct Answer: A — 30 meters

Q. From a point on the ground, the angle of elevation to the top of a 15-meter tall building is 45 degrees. How far is the point from the base of the building?

A. 15 meters
B. 30 meters
C. 10 meters
D. 20 meters

Solution

Using tan(45°) = height/distance, distance = height/tan(45°) = 15/1 = 15 meters.

Correct Answer: A — 15 meters

Q. From a point on the ground, the angle of elevation to the top of a hill is 45 degrees. If the point is 50 meters away from the base of the hill, what is the height of the hill?

A. 50 meters
B. 25 meters
C. 70 meters
D. 45 meters

Solution

Using tan(45°) = height/50, height = 50 * tan(45°) = 50 meters.

Correct Answer: A — 50 meters

Q. If the angle of elevation from a point on the ground to the top of a hill is 30 degrees and the distance from the point to the base of the hill is 20 meters, what is the height of the hill?

A. 10√3 meters
B. 20 meters
C. 15 meters
D. 5√3 meters

Solution

Using tan(30) = height / 20, height = 20 * tan(30) = 20 * (1/√3) = 20/√3 = 10√3 meters.

Correct Answer: A — 10√3 meters

Q. If the angle of elevation to the top of a tower from a point 40 meters away is 30 degrees, what is the height of the tower?

A. 20√3 meters
B. 40 meters
C. 30 meters
D. 10√3 meters

Solution

Using tan(30°) = height/40, height = 40 * (1/√3) = 40/√3 = 20√3 meters.

Correct Answer: A — 20√3 meters

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