The correct IUPAC name for C6H5CH2Br is Benzyl bromide, as it consists of a benzyl group with a bromine substituent.

The correct IUPAC name for CH3CH2Br is Bromoethane, as it consists of a two-carbon chain with a bromine substituent.

The major product is 1-Propanol, as the reaction proceeds via an SN2 mechanism leading to the formation of an alcohol.

The major product is 2-butene, as potassium tert-butoxide promotes elimination (E2) leading to the formation of an alkene.

The reaction proceeds via an SN2 mechanism, as 2-bromobutane is a secondary haloalkane and the nucleophile attacks from the opposite side.

The hydrolysis of chlorobenzene primarily yields phenol, as the chlorine atom is replaced by a hydroxyl group.

The product is Bromobenzene, as the reaction involves electrophilic aromatic substitution.

The reaction leads to inversion of configuration, resulting in the formation of (S)-2-iodobutane.

The reaction of a haloalkane with a nucleophile typically results in a substitution reaction, where the nucleophile replaces the halogen.

1,2-Dibromopropane exhibits optical isomerism due to the presence of a chiral center.

Haloalkanes contain a halogen functional group, which is responsible for their reactivity and properties.

C2H5Br is a haloalkane, as it contains a carbon chain with a bromine atom attached.

C4H9Cl has the highest boiling point due to increased molecular weight and surface area leading to stronger van der Waals forces.

Haloarenes are characterized by the presence of a benzene ring, which affects their reactivity and properties.

The reaction of 1-bromopropane with sodium hydroxide proceeds via an S2 mechanism, which is a bimolecular nucleophilic substitution.