Averages are a fundamental concept in mathematics that play a crucial role in various exams. Understanding averages not only helps in solving problems efficiently but also boosts your confidence in tackling objective questions. Practicing Averages MCQs and objective questions is essential for mastering this topic and scoring better in your exams. With a focus on important questions and practice questions, you can enhance your exam preparation and achieve your academic goals.
What You Will Practise Here
Definition and types of averages: mean, median, and mode
Formulas for calculating averages and their applications
Solving problems involving weighted averages
Understanding the impact of outliers on averages
Real-life applications of averages in data interpretation
Practice with Averages MCQ questions to reinforce learning
Analyzing graphical representations of averages
Exam Relevance
The topic of averages is frequently tested in CBSE, State Boards, NEET, and JEE exams. Students can expect to encounter questions that require them to calculate averages, interpret data sets, and apply the concept in various scenarios. Common question patterns include direct calculations, word problems, and data interpretation tasks that assess a student's understanding of averages in different contexts.
Common Mistakes Students Make
Confusing mean, median, and mode, and their appropriate applications
Neglecting the effect of outliers on the average value
Misinterpreting questions that involve weighted averages
Overlooking the importance of units when calculating averages
Rushing through calculations, leading to simple arithmetic errors
FAQs
Question: What is the difference between mean, median, and mode? Answer: Mean is the average of all values, median is the middle value when data is sorted, and mode is the most frequently occurring value in a data set.
Question: How do outliers affect the average? Answer: Outliers can skew the mean significantly, making it unrepresentative of the data set, while the median remains unaffected.
Question: Why are averages important in competitive exams? Answer: Averages are essential for data analysis and interpretation, which are common in various competitive exam questions.
Now is the time to sharpen your skills! Dive into our Averages MCQs and practice questions to test your understanding and prepare effectively for your exams. Every question you solve brings you one step closer to success!
Q. A class has 10 boys and 15 girls. If the average height of boys is 150 cm and that of girls is 145 cm, what is the average height of the class?
A.
147 cm
B.
148 cm
C.
149 cm
D.
150 cm
Solution
Total height of boys = 10 * 150 = 1500 cm. Total height of girls = 15 * 145 = 2175 cm. Total height = 1500 + 2175 = 3675 cm. Average height = 3675 / 25 = 147 cm.
Q. A class has 10 students with an average height of 150 cm. If 5 new students with an average height of 160 cm join, what is the new average height of the class?
A.
154
B.
155
C.
156
D.
157
Solution
Total height of 10 students = 10 * 150 = 1500 cm. Total height of 5 new students = 5 * 160 = 800 cm. New total height = 1500 + 800 = 2300 cm. New average = 2300 / 15 = 153.33 cm.
Q. A class has 30 students with an average score of 75. If 5 new students join with an average score of 80, what will be the new average?
A.
76
B.
77
C.
78
D.
79
Solution
Total score of 30 students = 30 * 75 = 2250. Total score of 5 new students = 5 * 80 = 400. New total = 2250 + 400 = 2650. New average = 2650 / 35 = 76.43.
Q. A class has 30 students with an average score of 75. If 5 new students join with an average score of 80, what is the new average score of the class?
A.
76
B.
77
C.
78
D.
79
Solution
Total score of 30 students = 30 * 75 = 2250. Total score of 5 new students = 5 * 80 = 400. New total = 2250 + 400 = 2650. New average = 2650 / 35 = 76.43.
Q. A class has 30 students. If the average score of the class is 75 and the average score of the top 10 students is 90, what is the average score of the bottom 20 students?
A.
60
B.
70
C.
75
D.
80
Solution
Total score of 30 students = 30 * 75 = 2250. Total score of top 10 students = 10 * 90 = 900. Total score of bottom 20 students = 2250 - 900 = 1350. Average score of bottom 20 = 1350 / 20 = 67.5.
Q. A company has 3 departments with average salaries of $4000, $5000, and $6000. If the number of employees in each department is 10, 15, and 20 respectively, what is the overall average salary?
Q. A group of 4 friends has an average age of 25 years. If one friend leaves and the average age becomes 26 years, what is the age of the friend who left?
A.
24
B.
25
C.
26
D.
27
Solution
Total age of 4 friends = 4 * 25 = 100. New total age for 3 friends = 3 * 26 = 78. Age of friend who left = 100 - 78 = 22.
Q. A group of 8 friends has an average age of 25 years. If one friend leaves and the average age becomes 26 years, what is the age of the friend who left?
A.
24
B.
25
C.
26
D.
27
Solution
Total age of 8 friends = 8 * 25 = 200. New total age for 7 friends = 7 * 26 = 182. Age of friend who left = 200 - 182 = 18.
Q. A group of friends has an average age of 25 years. If one friend aged 30 leaves the group, what will be the new average age if the group originally had 5 members?
A.
24
B.
25
C.
26
D.
27
Solution
Total age = 25 * 5 = 125. New total age = 125 - 30 = 95. New average = 95 / 4 = 23.75.
Q. A group of friends has an average age of 25 years. If one friend aged 30 leaves the group, what will be the new average age if the group originally had 5 friends?
A.
24
B.
25
C.
26
D.
27
Solution
Total age = 5 * 25 = 125. New total age = 125 - 30 = 95. New average = 95 / 4 = 23.75.
Q. A group of friends has an average age of 25 years. If one friend who is 30 years old leaves the group, what will be the new average age if there were originally 5 friends?
A.
24
B.
25
C.
26
D.
27
Solution
Total age of 5 friends = 5 * 25 = 125. New total age = 125 - 30 = 95. New average = 95 / 4 = 23.75.
Q. A student scores 70, 80, and 90 in three subjects. If he wants to achieve an average of 85 after the fourth subject, what score does he need in the fourth subject?
A.
85
B.
90
C.
95
D.
100
Solution
Total score needed for average of 85 = 4 * 85 = 340. Current total = 70 + 80 + 90 = 240. Score needed in fourth subject = 340 - 240 = 100.
