Increase/Decrease & Applications MCQ & Objective Questions
The concepts of "Increase/Decrease & Applications" are crucial in various academic examinations, especially for students preparing for school and competitive exams. Mastering these topics through MCQs and objective questions not only enhances conceptual clarity but also boosts your confidence in tackling exam challenges. Regular practice with these important questions can significantly improve your performance and help you score better in your exams.
What You Will Practise Here
Understanding the principles of increase and decrease in various contexts
Application of formulas related to increase and decrease
Identifying key concepts and definitions relevant to the topic
Solving real-life problems using increase and decrease scenarios
Interpreting graphs and diagrams that illustrate increase and decrease
Working through practice questions that mimic exam patterns
Reviewing important theorems and their applications in problems
Exam Relevance
The topic of "Increase/Decrease & Applications" is frequently featured in CBSE, State Boards, NEET, and JEE examinations. Students can expect questions that test their understanding of the concepts through various formats, including direct application problems, theoretical questions, and graphical interpretations. Familiarity with common question patterns will help you navigate these exams with ease.
Common Mistakes Students Make
Misinterpreting the context of increase and decrease in word problems
Confusing the application of formulas, leading to incorrect calculations
Overlooking the significance of units in increase/decrease problems
Failing to analyze graphs correctly, which can lead to wrong conclusions
Neglecting to review basic definitions, resulting in conceptual gaps
FAQs
Question: What are some effective strategies for solving Increase/Decrease MCQs?Answer: Focus on understanding the underlying concepts, practice regularly, and review your mistakes to avoid repeating them.
Question: How can I improve my speed in answering objective questions on this topic?Answer: Regular practice with timed quizzes can help you enhance your speed and accuracy.
Now is the time to take charge of your exam preparation! Dive into our collection of practice MCQs on "Increase/Decrease & Applications" and test your understanding. Remember, consistent practice is the key to success!
Q. A bank offers a 5% increase on a deposit. If the deposit amount is $1,000, what will be the total amount after the increase?
A.
$1,050
B.
$1,100
C.
$1,200
D.
$1,150
Show solution
Solution
Total Amount = Deposit + (5% of Deposit) = 1000 + (0.05 * 1000) = 1000 + 50 = $1,050.
Correct Answer:
A
— $1,050
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Q. A bank offers a 5% increase on a deposit. If the deposit amount is $2,000, what will be the total amount after the increase?
A.
$2,100
B.
$2,200
C.
$2,050
D.
$2,300
Show solution
Solution
Total amount after increase = Deposit + (5% of Deposit) = 2000 + (0.05 * 2000) = 2000 + 100 = $2,100.
Correct Answer:
A
— $2,100
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Q. A bank offers a 5% increase on deposits. If you deposit $1,000, how much will you have after one year?
A.
$1,050
B.
$1,100
C.
$1,200
D.
$1,150
Show solution
Solution
Amount after one year = Deposit + (5% of Deposit) = 1000 + (0.05 * 1000) = 1000 + 50 = $1,050.
Correct Answer:
A
— $1,050
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Q. A bank offers a 5% increase on savings. If you deposit $1,000, how much will you have after one year?
A.
$1,050
B.
$1,100
C.
$1,200
D.
$1,150
Show solution
Solution
Amount after one year = Original Amount + (5% of Original Amount) = 1000 + (0.05 * 1000) = 1000 + 50 = $1,050.
Correct Answer:
A
— $1,050
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Q. A bicycle's price is decreased by 15% and the new price is $85. What was the original price?
A.
$100
B.
$90
C.
$80
D.
$70
Show solution
Solution
Let the original price be x. Then, x - (15% of x) = 85. This means 0.85x = 85, so x = 85 / 0.85 = $100.
Correct Answer:
A
— $100
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Q. A bicycle's price is increased by 15% to $230. What was the original price?
A.
$200
B.
$210
C.
$220
D.
$190
Show solution
Solution
Let the original price be x. Then, x + 0.15x = 230 => 1.15x = 230 => x = 230 / 1.15 = $200.
Correct Answer:
A
— $200
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Q. A book's price is decreased by 10% and the new price is $18. What was the original price?
A.
$20
B.
$22
C.
$19
D.
$21
Show solution
Solution
Let the original price be x. Then, x - 0.1x = 18 => 0.9x = 18 => x = 18 / 0.9 = $20.
Correct Answer:
A
— $20
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Q. A book's price is decreased by 20% and the new price is $24. What was the original price?
A.
$30
B.
$28
C.
$26
D.
$25
Show solution
Solution
Let original price be x. Then, x - 0.2x = 24 => 0.8x = 24 => x = 24 / 0.8 = $30.
Correct Answer:
A
— $30
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Q. A book's price is increased by 10% and then decreased by 10%. If the original price was $100, what is the final price?
A.
$100
B.
$99
C.
$90
D.
$95
Show solution
Solution
New Price after increase = 100 + (10% of 100) = 100 + 10 = $110. Final Price after decrease = 110 - (10% of 110) = 110 - 11 = $99.
Correct Answer:
A
— $100
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Q. A book's price is increased by 15% to $23. What was the original price of the book?
A.
$20
B.
$21
C.
$22
D.
$19
Show solution
Solution
Original Price = New Price / (1 + 0.15) = 23 / 1.15 = $20.
Correct Answer:
A
— $20
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Q. A book's price is increased from $15 to $18. What is the percentage increase in the price?
A.
20%
B.
15%
C.
25%
D.
10%
Show solution
Solution
Percentage Increase = ((New Price - Original Price) / Original Price) * 100 = ((18 - 15) / 15) * 100 = (3 / 15) * 100 = 20%.
Correct Answer:
A
— 20%
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Q. A car's value decreases by 10% each year. If the current value is $20,000, what will be its value after one year?
A.
$18,000
B.
$19,000
C.
$17,500
D.
$16,000
Show solution
Solution
New Value = Current Value - (10% of Current Value) = 20000 - (0.1 * 20000) = 20000 - 2000 = $18,000.
Correct Answer:
A
— $18,000
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Q. A company's profit decreased by 20% this year. If the profit last year was $500,000, what is the profit this year?
A.
$400,000
B.
$450,000
C.
$480,000
D.
$500,000
Show solution
Solution
Profit this year = Last Year Profit - (20% of Last Year Profit) = 500000 - (0.2 * 500000) = 500000 - 100000 = $400,000.
Correct Answer:
A
— $400,000
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Q. A company's profit increased by 50% this year. If last year's profit was $10,000, what is this year's profit?
A.
$15,000
B.
$12,000
C.
$14,000
D.
$16,000
Show solution
Solution
This Year's Profit = Last Year's Profit + (50% of Last Year's Profit) = 10000 + (0.5 * 10000) = 10000 + 5000 = $15,000.
Correct Answer:
A
— $15,000
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Q. A company's revenue increased from $1,000,000 to $1,200,000. What is the percentage increase in revenue?
A.
20%
B.
15%
C.
25%
D.
30%
Show solution
Solution
Percentage Increase = ((New Revenue - Original Revenue) / Original Revenue) * 100 = ((1200000 - 1000000) / 1000000) * 100 = (200000 / 1000000) * 100 = 20%.
Correct Answer:
A
— 20%
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Q. A discount of 10% is offered on a product priced at $150. What is the sale price after the discount?
A.
$135
B.
$140
C.
$145
D.
$130
Show solution
Solution
Sale Price = Original Price - (10% of Original Price) = 150 - (0.1 * 150) = 150 - 15 = $135.
Correct Answer:
A
— $135
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Q. A factory produces 500 units of a product. If production increases by 25%, how many units will be produced?
A.
600
B.
625
C.
550
D.
500
Show solution
Solution
New Production = Original Production + (25% of Original Production) = 500 + (0.25 * 500) = 500 + 125 = 625.
Correct Answer:
B
— 625
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Q. A factory reduces its production by 25%. If the original production was 800 units, what is the new production?
A.
600
B.
700
C.
500
D.
400
Show solution
Solution
New Production = Original Production - (25% of Original Production) = 800 - (0.25 * 800) = 800 - 200 = 600.
Correct Answer:
A
— 600
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Q. A factory's production decreased by 25% this month. If the production last month was 400 units, what is the production this month?
A.
300
B.
350
C.
320
D.
280
Show solution
Solution
Production this month = Last Month's Production - (25% of Last Month's Production) = 400 - (0.25 * 400) = 400 - 100 = 300.
Correct Answer:
A
— 300
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Q. A factory's production decreases by 20% in a month. If the original production was 500 units, what is the new production?
A.
400
B.
450
C.
350
D.
300
Show solution
Solution
New Production = Original Production - (20% of Original Production) = 500 - (0.2 * 500) = 500 - 100 = 400.
Correct Answer:
A
— 400
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Q. A factory's production decreases by 25% in a month. If the initial production was 800 units, what is the production after the decrease?
A.
600
B.
700
C.
500
D.
400
Show solution
Solution
Production after decrease = Initial Production - (25% of Initial Production) = 800 - (0.25 * 800) = 800 - 200 = 600.
Correct Answer:
A
— 600
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Q. A house's value decreased by 12% over a year. If the current value is $250,000, what was the value a year ago?
A.
$280,000
B.
$275,000
C.
$300,000
D.
$270,000
Show solution
Solution
Value a year ago = Current Value / (1 - 0.12) = 250000 / 0.88 = $284,090.91 (approximately $280,000).
Correct Answer:
A
— $280,000
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Q. A house's value decreases by 12% over a year. If the original value was $300,000, what is the value after the decrease?
A.
$264,000
B.
$270,000
C.
$280,000
D.
$290,000
Show solution
Solution
Value after decrease = Original Value - (12% of Original Value) = 300000 - (0.12 * 300000) = 300000 - 36000 = $264,000.
Correct Answer:
A
— $264,000
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Q. A house's value increases by 12% annually. If its current value is $300,000, what will be its value after one year?
A.
$336,000
B.
$330,000
C.
$300,000
D.
$320,000
Show solution
Solution
Value after one year = Current Value + (12% of Current Value) = 300000 + (0.12 * 300000) = 300000 + 36000 = $336,000.
Correct Answer:
A
— $336,000
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Q. A population of a town decreases by 15% in one year. If the initial population was 2000, what is the population after one year?
A.
1700
B.
1800
C.
1900
D.
2000
Show solution
Solution
Population after decrease = Initial Population - (15% of Initial Population) = 2000 - (0.15 * 2000) = 2000 - 300 = 1700.
Correct Answer:
A
— 1700
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Q. A population of a town decreases by 15% in one year. If the population was 2000, what is the population after the decrease?
A.
1700
B.
1800
C.
1900
D.
1600
Show solution
Solution
New Population = Original Population - (15% of Original Population) = 2000 - (0.15 * 2000) = 2000 - 300 = 1700.
Correct Answer:
B
— 1800
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Q. A population of a town increases by 15% every year. If the current population is 2000, what will be the population after one year?
A.
2300
B.
2200
C.
2150
D.
2100
Show solution
Solution
Population after one year = Current Population + (15% of Current Population) = 2000 + (0.15 * 2000) = 2000 + 300 = 2300.
Correct Answer:
B
— 2200
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Q. A product's price is decreased by 30% and the new price is $70. What was the original price?
A.
$100
B.
$90
C.
$80
D.
$70
Show solution
Solution
Let the original price be x. Then, x - 0.3x = 70 => 0.7x = 70 => x = 70 / 0.7 = $100.
Correct Answer:
A
— $100
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Q. A product's price is decreased by 30%. If the original price is $80, what is the new price?
A.
$56
B.
$54
C.
$60
D.
$58
Show solution
Solution
New Price = Original Price - (30% of Original Price) = 80 - (0.3 * 80) = 80 - 24 = $56.
Correct Answer:
A
— $56
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Q. A product's price is reduced by 30% and the sale price is $70. What was the original price?
A.
$90
B.
$100
C.
$80
D.
$70
Show solution
Solution
Let the original price be x. Then, x - (30% of x) = 70. This means 0.7x = 70, so x = 70 / 0.7 = $100.
Correct Answer:
A
— $90
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