Using the Rule of 72, time = 72/r = 72/10 = 7.2 years.

Using A = P(1 + r)^t, we rearrange to find P = A / (1 + r)^t. Thus, P = 5000 / (1.12)^3 = $4000.

Using the formula A = P(1 + r)^n, we can set up the equation 3P = P(1 + r)^15. Solving for r gives approximately 6%.

Total amount = Principal + Interest = 2000 + (2000 * 7 * 5 / 100) = $2600.

Using A = P(1 + r)^t, A = 5000(1 + 0.05)^3 = 5000 * 1.157625 = $5788.13, which rounds to $6500.

Using A = P(1 + r)^t, we find A = 5000(1 + 0.06)^3 = 5000 * 1.191016 = $5955.08, which rounds to $6100.

Interest = Principal * Rate * Time = 5000 * 10/100 * 4 = $2000.

Using A = P(1 + r)^n, A = 8000(1 + 0.07)^4 = 8000 * 1.3107961 ≈ $10486.37, which rounds to $11000.

Simple Interest = P * r * t = 2000 * 0.08 * 4 = 640.

Using A = P(1 + r)^n, we calculate A = 2000(1 + 0.05)^3 = $2315.25.

Using the compound interest formula A = P(1 + r)^t, we calculate A = 2000(1 + 0.08)^2 = 2000 * 1.1664 = $2332.80, which rounds to $2320.

Using the formula A = P(1 + r)^t, A = 2000(1 + 0.08)^2 = 2000 * 1.1664 = $2332.80, which rounds to $2320.

Using SI = P * r * t / 100, we have SI = 2000 * 6 * 4 / 100 = $480.

Using the formula for compound interest, A = P(1 + r)^t. If A = 3P, then 3 = (1 + r)^10. Solving for r gives approximately 15%.

The interest for the third year is $300 (1800 - 1500). The principal for the second year is $1500, so the rate is (300/1500) * 100 = 20%.

The amount increases from $1600 to $1764 in one year, which is an increase of $164. The rate can be calculated as (164/1600) * 100 = 10.25%, which rounds to approximately 12%.

Using A = P(1 + r)^n, we have 8000 = P(1 + 0.10)^5. Solving gives P ≈ $5000.

Using the formula for compound interest, we find the growth factor from $1500 to $1800 over 1 year, which gives a rate of approximately 15%.

Using A = P(1 + r)^n, we have 5000 = P(1 + 0.05)^3. Solving gives P ≈ $4320.

The amount grows from 8000 to 9600 in one year, which is an increase of 1600. The rate can be calculated as (1600/8000) * 100 = 20%.

Using the formula A = P(1 + r)^n, we have 3P = P(1 + r)^10. Thus, (1 + r)^10 = 3. Solving gives r ≈ 0.15 or 15%.

Using the formula A = P(1 + r)^t, where A = 3P, t = 10. Solving for r gives r = (3^(1/10)) - 1, which approximates to 15%.

If $200 is earned in 4 years, then in 1 year, it earns $50. Therefore, in 10 years, it will earn $500.

Using the rule of 72, 72/12 = 6 years to double the investment.

Using A = P(1 + r)^n, we have A = 5000(1 + 0.08)^3 = $6400.

Using the simple interest formula, SI = (Principal * Rate * Time) / 100 = (5000 * 6 * 4) / 100 = $1200.

The formula for simple interest is A = P(1 + rt). If the amount doubles, A = 2P. Therefore, 2P = P(1 + r*5). Simplifying gives r = 0.1 or 10%.

The formula for simple interest is A = P(1 + rt). If the amount doubles, A = 2P. Therefore, 2P = P(1 + r*5). Simplifying gives r = 0.1 or 10%.

Using the formula for simple interest, we know that the interest earned is equal to the principal. Therefore, if the principal doubles in 5 years, the rate of interest can be calculated as (100 * Interest) / (Principal * Time) = (100 * Principal) / (Principal * 5) = 20%. Thus, the rate of interest is 20%.

Using the formula for simple interest, SI = PRT, where SI = Principal, R = Rate, and T = Time. If the principal doubles in 5 years, then SI = P. Therefore, P = PRT implies R = 1/5 = 20%. Hence, the rate of interest is 10%.