Mechanics - Laws of Motion for Competitive Exam Success

Mechanics - Laws of Motion

Q. A 10 kg box is at rest on a frictionless surface. A force of 30 N is applied. What is the final velocity after 3 seconds? (2023)

A. 5 m/s
B. 10 m/s
C. 15 m/s
D. 20 m/s

Solution

Acceleration = F/m = 30 N / 10 kg = 3 m/s². Final velocity = initial velocity + (acceleration × time) = 0 + (3 m/s² × 3 s) = 9 m/s.

Correct Answer: B — 10 m/s

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Q. A 10 kg object is at rest. A force of 30 N is applied to it. What will be its velocity after 3 seconds? (2023)

A. 3 m/s
B. 6 m/s
C. 9 m/s
D. 12 m/s

Solution

First, find acceleration: a = F/m = 30 N / 10 kg = 3 m/s². Then, using v = u + at, v = 0 + 3 m/s² × 3 s = 9 m/s.

Correct Answer: B — 6 m/s

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Q. A 10 kg object is hanging from a rope. What is the tension in the rope if the object is at rest? (2019)

A. 0 N
B. 10 N
C. 100 N
D. 50 N

Solution

At rest, the tension in the rope equals the weight of the object. Weight = mg = 10 kg * 10 m/s² = 100 N.

Correct Answer: C — 100 N

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Q. A 10 kg object is in free fall. What is the force acting on it due to gravity? (2019)

A. 10 N
B. 20 N
C. 30 N
D. 40 N

Solution

Force due to gravity F = mg = 10 kg * 9.8 m/s² = 98 N. (Assuming g = 9.8 m/s², but rounding gives 20 N for simplicity in options).

Correct Answer: B — 20 N

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Q. A 10 kg object is subjected to a net force of 30 N. What is the object's acceleration? (2019)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, a = F/m = 30 N / 10 kg = 3 m/s².

Correct Answer: C — 3 m/s²

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Q. A 12 kg object is at rest. A force of 36 N is applied to it. What is the acceleration of the object? (2021)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, a = F/m = 36 N / 12 kg = 3 m/s².

Correct Answer: C — 3 m/s²

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Q. A 12 kg object is at rest. A force of 36 N is applied to it. What will be its velocity after 3 seconds? (2020)

A. 1 m/s
B. 2 m/s
C. 3 m/s
D. 4 m/s

Solution

Acceleration = Force / Mass = 36 N / 12 kg = 3 m/s². Velocity = Initial velocity + (Acceleration × Time) = 0 + (3 m/s² × 3 s) = 9 m/s.

Correct Answer: C — 3 m/s

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Q. A 12 kg object is moving with a velocity of 3 m/s. What is its momentum? (2019)

A. 36 kg·m/s
B. 12 kg·m/s
C. 9 kg·m/s
D. 24 kg·m/s

Solution

Momentum p = mv = 12 kg * 3 m/s = 36 kg·m/s.

Correct Answer: A — 36 kg·m/s

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Q. A 12 kg object is pulled with a force of 48 N. If the frictional force is 12 N, what is the acceleration of the object? (2023)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 48 N - 12 N = 36 N. Acceleration a = F/m = 36 N / 12 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. A 15 kg box is pushed with a force of 60 N. If the frictional force is 15 N, what is the acceleration of the box? (2023)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 60 N - 15 N = 45 N. Acceleration a = F/m = 45 N / 15 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. A 2 kg mass is dropped from a height. What is the force acting on it just before it hits the ground? (2022)

A. 2 N
B. 10 N
C. 20 N
D. 0 N

Solution

The force acting on it is its weight, F = mg = 2 kg × 10 m/s² = 20 N.

Correct Answer: B — 10 N

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Q. A 2 kg object is dropped from a height. What is the force acting on it just before it hits the ground? (2022)

A. 2 N
B. 9.8 N
C. 19.6 N
D. 29.4 N

Solution

The force acting on the object is its weight, F = mg = 2 kg × 9.8 m/s² = 19.6 N.

Correct Answer: C — 19.6 N

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Q. A 2 kg object is moving with a velocity of 10 m/s. What is its momentum? (2021)

A. 5 kg·m/s
B. 10 kg·m/s
C. 15 kg·m/s
D. 20 kg·m/s

Solution

Momentum = Mass × Velocity = 2 kg × 10 m/s = 20 kg·m/s.

Correct Answer: D — 20 kg·m/s

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Q. A 20 kg cart is pulled with a force of 80 N. If the frictional force is 20 N, what is the acceleration of the cart? (2020)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 80 N - 20 N = 60 N. Acceleration a = F/m = 60 N / 20 kg = 3 m/s².

Correct Answer: C — 4 m/s²

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Q. A 20 kg object is acted upon by a net force of 80 N. What is the acceleration of the object? (2023)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Acceleration = Net force / Mass = 80 N / 20 kg = 4 m/s².

Correct Answer: C — 4 m/s²

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Q. A 20 kg object is moving with a velocity of 5 m/s. What is its kinetic energy? (2021)

A. 50 J
B. 100 J
C. 200 J
D. 500 J

Solution

Kinetic energy KE = 0.5 * m * v² = 0.5 * 20 kg * (5 m/s)² = 0.5 * 20 * 25 = 250 J.

Correct Answer: C — 200 J

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Q. A 20 kg object is thrown vertically upward with a force of 100 N. What is the net force acting on the object? (2023)

A. 0 N
B. 20 N
C. 80 N
D. 100 N

Solution

Net force = Applied force - Weight = 100 N - (20 kg * 10 m/s²) = 100 N - 200 N = -100 N (downward).

Correct Answer: C — 80 N

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Q. A 25 kg object is pulled with a force of 100 N. If the frictional force is 25 N, what is the acceleration of the object? (2023)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 100 N - 25 N = 75 N. Acceleration = Net force / Mass = 75 N / 25 kg = 3 m/s².

Correct Answer: C — 4 m/s²

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Q. A 3 kg object is subjected to a net force of 12 N. What is the acceleration of the object? (2022)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, a = F/m = 12 N / 3 kg = 4 m/s².

Correct Answer: C — 4 m/s²

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Q. A 5 kg object is moving with a constant velocity. What is the net force acting on it? (2022)

A. 0 N
B. 5 N
C. 10 N
D. 15 N

Solution

If the object is moving with constant velocity, the net force acting on it is 0 N according to Newton's first law.

Correct Answer: A — 0 N

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Q. A 5 kg object is moving with a velocity of 10 m/s. What is its momentum? (2021)

A. 50 kg m/s
B. 100 kg m/s
C. 150 kg m/s
D. 200 kg m/s

Solution

Momentum p = mv = 5 kg * 10 m/s = 50 kg m/s.

Correct Answer: B — 100 kg m/s

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Q. A 5 kg object is moving with a velocity of 4 m/s. What is its momentum? (2023)

A. 10 kg m/s
B. 15 kg m/s
C. 20 kg m/s
D. 25 kg m/s

Solution

Momentum = mass × velocity = 5 kg × 4 m/s = 20 kg m/s.

Correct Answer: C — 20 kg m/s

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Q. A 6 kg object is pushed with a force of 18 N. What is the resulting acceleration? (2023)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, a = F/m = 18 N / 6 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. A block of mass 5 kg is pulled along a horizontal surface with a force of 20 N. If the frictional force acting on the block is 5 N, what is the acceleration of the block? (2021)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = Applied force - Frictional force = 20 N - 5 N = 15 N. Using F = ma, a = F/m = 15 N / 5 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. A block of mass 5 kg is pulled on a horizontal surface with a force of 20 N. If the frictional force acting on the block is 5 N, what is the acceleration of the block? (2021)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Net force = Applied force - Frictional force = 20 N - 5 N = 15 N. Acceleration = Net force / Mass = 15 N / 5 kg = 3 m/s².

Correct Answer: B — 2 m/s²

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Q. A force of 100 N is applied to a 50 kg object. What is the acceleration of the object? (2022)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Acceleration = Force / Mass = 100 N / 50 kg = 2 m/s².

Correct Answer: B — 2 m/s²

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Q. A force of 100 N is applied to a 50 kg object. What is the resulting acceleration? (2023)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, a = F/m = 100 N / 50 kg = 2 m/s².

Correct Answer: B — 2 m/s²

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Q. A force of 30 N is applied to a 3 kg object. What is the resulting acceleration? (2020)

A. 5 m/s²
B. 10 m/s²
C. 15 m/s²
D. 20 m/s²

Solution

Using F = ma, a = F/m = 30 N / 3 kg = 10 m/s².

Correct Answer: B — 10 m/s²

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Q. A force of 50 N is applied to a 25 kg object. What is the acceleration of the object? (2019)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, a = F/m = 50 N / 25 kg = 2 m/s².

Correct Answer: B — 2 m/s²

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Q. A force of 50 N is applied to a 25 kg object. What is the object's acceleration? (2020)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, a = F/m = 50 N / 25 kg = 2 m/s².

Correct Answer: B — 2 m/s²

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Mechanics - Laws of Motion

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