The slopes are m1 = 2 and m2 = -1/2. The angle θ = tan^(-1) |(m1 - m2)/(1 + m1*m2)| = tan^(-1)(5/4) which is approximately 60 degrees.

Using the distance formula, d = √((5 - 2)² + (7 - 3)²) = √(9 + 16) = √25 = 5.

Using the formula for distance from a point to a line, d = |Ax1 + By1 + C| / sqrt(A^2 + B^2), we find d = |2(3) + 3(4) - 12| / sqrt(2^2 + 3^2) = 3.

Since the line is parallel, it has the same slope. Using point-slope form: y - 5 = 3(x - 4) gives y = 3x - 7.

Since the line is parallel, it has the same slope (3). Using point-slope form: y - 1 = 3(x - 4) gives y = 3x - 11.

Since the slope is the same (5), using point-slope form: y - 3 = 5(x - 2) gives y = 5x - 7.

Since the slope is the same (5), using point-slope form: y - 1 = 5(x - 2) gives y = 5x - 9.

Using the slope-intercept form y = mx + b, with m = 5 and b = 0, we get y = 5x.

The slope of the given line is 4, so the perpendicular slope is -1/4. Using point-slope form, we get y - 3 = -1/4(x - 2) which simplifies to y = -1/4x + 11/4.

The slope of the given line is 1/3, so the perpendicular slope is -3. Using point-slope form, y - 3 = -3(x - 2) gives y = -3x + 9.

Using the slope-intercept form, the equation is y = -3x.

Using point-slope form, y + 3 = 4(x - 2) simplifies to y = 4x - 11.

The slope of the given line is 3, so the slope of the perpendicular line is -1/3. Using point-slope form, we get y + 1 = -1/3(x - 4), which simplifies to y = -1/3x + 11/3.

The slope of the given line is 1/3, so the slope of the perpendicular line is -3. Using point-slope form, we get y - 5 = -3(x - 4), which simplifies to y = -3x + 17.

The slope m = (7 - 3) / (4 - 2) = 2. Using point-slope form: y - 3 = 2(x - 2) gives y = 2x + 1.

Setting x + 2 = -x + 4 gives 2x = 2, so x = 1. Substituting x back gives y = 3. Thus, the point is (1, 3).

Setting y = 0 in the equation gives 5x + 10 = 0, thus x = -2. The x-intercept is -2.

Setting x = 0 in the equation gives y = 8. Therefore, the y-intercept is 8.

Rearranging gives y = (7/3)x + 7. The slope is -7/3.

Rearranging to slope-intercept form gives y = (7/3)x - 7. The slope is -7/3.

The equation is in point-slope form, where the slope m = 4.

Substituting x = 2 into the equation gives y = -3(2) + 7 = 1.

Setting y = 0 gives 2x = 6, thus x = 3. The point of intersection is (3, 0).

Setting y = 0 gives 2x = 6, thus x = 3. The x-coordinate of the intersection point is 3.

Setting x = 0 gives 4y = 12, thus y = 3. The point of intersection is (0, 3).

Setting y = 0 in the equation gives 3x + 12 = 0, thus x = -4.

Setting x = 0 gives -4y + 12 = 0, thus y = -3. The point of intersection is (0, -3).

Rearranging gives y = (3/4)x + 3. The slope of the line is 3/4, so the slope of the parallel line is -3/4.

Parallel lines have the same slope. The slope of the given line is 3/4, which is the same as the slope of 6x - 8y + 24 = 0.

Rearranging to y = -7/2x + 7 shows that the slope is -7/2.