Q. A satellite is in a circular orbit around the Earth. If its orbital radius is tripled, how does the gravitational force acting on it change?
A.
It triples
B.
It halves
C.
It becomes one-ninth
D.
It remains the same
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Solution
Gravitational force is inversely proportional to the square of the radius. If radius is tripled, force becomes 1/3² = 1/9.
Correct Answer:
C
— It becomes one-ninth
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Q. Calculate the gravitational potential energy of a 2 kg mass at a height of 5 m. (g = 9.8 m/s²)
A.
98 J
B.
19.6 J
C.
39.2 J
D.
49 J
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Solution
Potential Energy (PE) = m * g * h = 2 kg * 9.8 m/s² * 5 m = 98 J
Correct Answer:
C
— 39.2 J
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Q. Calculate the weight of a 10 kg object on the surface of Mars, where the acceleration due to gravity is 3.7 m/s².
A.
37 N
B.
74 N
C.
10 N
D.
100 N
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Solution
Weight = mass * gravity = 10 kg * 3.7 m/s² = 37 N
Correct Answer:
A
— 37 N
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Q. Calculate the weight of a 10 kg object on the surface of the Earth (g = 9.8 m/s²).
A.
98 N
B.
10 N
C.
9.8 N
D.
100 N
Show solution
Solution
Weight W = m * g = 10 kg * 9.8 m/s² = 98 N.
Correct Answer:
A
— 98 N
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Q. How does gravitational potential energy (U) change when the distance from the center of the Earth increases? (2020)
A.
It increases
B.
It decreases
C.
It remains constant
D.
It becomes zero
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Solution
Gravitational potential energy increases as the distance from the center of the Earth increases.
Correct Answer:
A
— It increases
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Q. How does the gravitational force between two objects change if the mass of one object is halved?
A.
It doubles
B.
It halves
C.
It remains the same
D.
It becomes zero
Show solution
Solution
Gravitational force is directly proportional to the product of the masses. Halving one mass halves the force.
Correct Answer:
B
— It halves
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Q. If the gravitational force between two objects is 20 N and the distance between them is doubled, what will be the new force?
A.
5 N
B.
10 N
C.
20 N
D.
40 N
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Solution
F is inversely proportional to r². If r is doubled, F becomes F/4 = 20 N / 4 = 5 N.
Correct Answer:
A
— 5 N
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Q. If the mass of an object is tripled and the distance from the center of the Earth is halved, how does the gravitational force change?
A.
It triples
B.
It increases by a factor of 6
C.
It increases by a factor of 9
D.
It decreases
Show solution
Solution
F ∝ m/r²; if m is tripled and r is halved, F = 3m/(1/4) = 12m, so it increases by a factor of 9.
Correct Answer:
C
— It increases by a factor of 9
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Q. If the mass of the Earth were to double, what would happen to the gravitational force experienced by an object on its surface?
A.
It doubles
B.
It halves
C.
It quadruples
D.
It remains the same
Show solution
Solution
Gravitational force is directly proportional to mass. If mass doubles, force also doubles.
Correct Answer:
A
— It doubles
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Q. If the radius of the Earth is doubled, what will happen to the gravitational force experienced by an object on its surface?
A.
It will double
B.
It will remain the same
C.
It will be halved
D.
It will be quartered
Show solution
Solution
Gravitational force is inversely proportional to the square of the radius. If radius is doubled, F becomes F/4.
Correct Answer:
D
— It will be quartered
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Q. If the radius of the Earth were to increase by 50%, what would happen to the weight of an object on its surface?
A.
It increases by 50%
B.
It increases by 25%
C.
It decreases by 25%
D.
It remains the same
Show solution
Solution
Weight is inversely proportional to the square of the radius. If radius increases by 50%, weight decreases by 25%.
Correct Answer:
C
— It decreases by 25%
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Q. If the radius of the Earth were to increase while keeping its mass constant, what would happen to the gravitational acceleration at the surface? (2023)
A.
It increases
B.
It decreases
C.
It remains the same
D.
It becomes zero
Show solution
Solution
Gravitational acceleration is inversely proportional to the square of the radius. If radius increases, g decreases.
Correct Answer:
B
— It decreases
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Q. If the radius of the Earth were to increase while keeping its mass constant, what would happen to the gravitational acceleration at its surface?
A.
It increases
B.
It decreases
C.
It remains the same
D.
It becomes zero
Show solution
Solution
Gravitational acceleration g = GM/R². If R increases, g decreases.
Correct Answer:
B
— It decreases
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Q. If the radius of the Earth were to increase while keeping its mass constant, what would happen to the value of g? (2023)
A.
g increases
B.
g decreases
C.
g remains the same
D.
g becomes zero
Show solution
Solution
If the radius increases while mass remains constant, g decreases because g = G * M / r^2.
Correct Answer:
B
— g decreases
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Q. What is the escape velocity from the surface of a planet with a radius of 4,000 km and a mass of 6 × 10^24 kg? (G = 6.67 × 10^-11 N m²/kg²)
A.
10,000 m/s
B.
11,200 m/s
C.
12,000 m/s
D.
13,000 m/s
Show solution
Solution
Escape velocity = √(2GM/R) = √(2 * 6.67 × 10^-11 * 6 × 10^24 / 4 × 10^6) = 11,200 m/s
Correct Answer:
B
— 11,200 m/s
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Q. What is the escape velocity from the surface of the Earth? (g = 9.8 m/s², R = 6.4 × 10^6 m)
A.
11.2 km/s
B.
9.8 km/s
C.
7.9 km/s
D.
15 km/s
Show solution
Solution
Escape velocity (v) = √(2gR) = √(2 * 9.8 * 6.4 × 10^6) ≈ 11.2 km/s
Correct Answer:
A
— 11.2 km/s
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Q. What is the escape velocity from the surface of the Earth? (R = 6.4 × 10^6 m, g = 9.8 m/s²)
A.
11.2 km/s
B.
9.8 km/s
C.
7.9 km/s
D.
12.0 km/s
Show solution
Solution
Escape velocity v = √(2gR) = √(2 * 9.8 * 6.4 × 10^6) ≈ 11.2 km/s.
Correct Answer:
A
— 11.2 km/s
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Q. What is the gravitational field strength at a distance of 10 m from a mass of 100 kg? (G = 6.67 × 10^-11 N m²/kg²)
A.
6.67 × 10^-10 N/kg
B.
6.67 × 10^-9 N/kg
C.
6.67 × 10^-8 N/kg
D.
6.67 × 10^-7 N/kg
Show solution
Solution
g = G * M / r² = (6.67 × 10^-11) * (100) / (10²) = 6.67 × 10^-10 N/kg
Correct Answer:
A
— 6.67 × 10^-10 N/kg
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Q. What is the gravitational field strength at a distance of 3R from the center of the Earth? (R = radius of the Earth) (2022)
A.
g/3
B.
g/9
C.
g/6
D.
g/12
Show solution
Solution
Gravitational field strength decreases with the square of the distance. At 3R, it is g/9.
Correct Answer:
B
— g/9
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Q. What is the gravitational force acting on a 50 kg object at the surface of the Earth?
A.
490 N
B.
500 N
C.
510 N
D.
520 N
Show solution
Solution
Weight = mass * g = 50 kg * 9.8 m/s² = 490 N
Correct Answer:
A
— 490 N
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Q. What is the gravitational force acting on a 50 kg object on the surface of the Earth?
A.
490 N
B.
50 N
C.
5 N
D.
500 N
Show solution
Solution
Weight W = m * g = 50 kg * 9.8 m/s² = 490 N.
Correct Answer:
A
— 490 N
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Q. What is the gravitational force between two 1 kg masses placed 1 meter apart? (G = 6.67 × 10^-11 N m²/kg²)
A.
6.67 × 10^-11 N
B.
1.67 × 10^-10 N
C.
6.67 × 10^-10 N
D.
0 N
Show solution
Solution
F = G * (m1 * m2) / r² = (6.67 × 10^-11) * (1 * 1) / (1²) = 6.67 × 10^-11 N
Correct Answer:
A
— 6.67 × 10^-11 N
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Q. What is the gravitational force between two objects of mass 5 kg and 10 kg separated by a distance of 2 m? (G = 6.67 × 10^-11 N m²/kg²)
A.
1.67 × 10^-10 N
B.
1.25 × 10^-10 N
C.
1.00 × 10^-10 N
D.
2.00 × 10^-10 N
Show solution
Solution
Using the formula F = G * (m1 * m2) / r², we have F = (6.67 × 10^-11) * (5 * 10) / (2²) = 1.67 × 10^-10 N.
Correct Answer:
A
— 1.67 × 10^-10 N
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Q. What is the gravitational force between two objects of mass m1 and m2 separated by a distance r? (2021)
A.
G * (m1 * m2) / r^2
B.
G * (m1 + m2) / r^2
C.
G * (m1 - m2) / r^2
D.
G * (m1 * m2) * r^2
Show solution
Solution
The gravitational force is given by Newton's law of gravitation: F = G * (m1 * m2) / r^2.
Correct Answer:
A
— G * (m1 * m2) / r^2
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Q. Which of the following correctly describes the relationship between gravitational force and distance?
A.
Directly proportional
B.
Inversely proportional
C.
Exponential
D.
Linear
Show solution
Solution
Gravitational force is inversely proportional to the square of the distance between the centers of two masses.
Correct Answer:
B
— Inversely proportional
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Q. Which of the following statements is true regarding gravitational fields? (2022)
A.
Gravitational fields are always attractive
B.
Gravitational fields can be repulsive
C.
Gravitational fields are independent of mass
D.
Gravitational fields do not exist in space
Show solution
Solution
Gravitational fields are always attractive, pulling masses towards each other.
Correct Answer:
A
— Gravitational fields are always attractive
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Showing 1 to 26 of 26 (1 Pages)
Gravitation MCQ & Objective Questions
Gravitation is a fundamental concept in physics that plays a crucial role in various examinations. Understanding this topic is essential for students preparing for school exams and competitive tests. Practicing Gravitation MCQs and objective questions not only enhances conceptual clarity but also boosts confidence, helping students score better in their exams. By solving practice questions, students can identify important questions and familiarize themselves with the exam pattern.
What You Will Practise Here
Newton's Law of Gravitation
Gravitational Force and its Calculation
Acceleration due to Gravity
Gravitational Potential Energy
Orbital Motion and Satellites
Kepler's Laws of Planetary Motion
Escape Velocity and Related Concepts
Exam Relevance
The topic of Gravitation is frequently featured in CBSE, State Boards, NEET, and JEE examinations. Students can expect questions that test their understanding of key concepts, calculations involving gravitational force, and applications of gravitational laws. Common question patterns include numerical problems, conceptual questions, and theoretical explanations, making it essential to master this topic for effective exam preparation.
Common Mistakes Students Make
Confusing the concepts of mass and weight.
Misapplying the formula for gravitational force.
Overlooking the significance of the distance between two masses.
Failing to differentiate between gravitational potential energy and kinetic energy.
FAQs
Question: What is the formula for gravitational force?Answer: The formula for gravitational force is F = G(m1*m2)/r², where G is the gravitational constant, m1 and m2 are the masses, and r is the distance between their centers.
Question: How does gravity affect satellite motion?Answer: Gravity provides the necessary centripetal force for satellites to maintain their orbits around Earth, balancing the gravitational pull and the satellite's inertia.
Now is the perfect time to enhance your understanding of Gravitation. Dive into our practice MCQs and test your knowledge to excel in your upcoming exams!
