Nickel in [Ni(CO)4] undergoes sp3 hybridization as it forms four sigma bonds with CO ligands.

[Cu(H2O)6]2+ is known to exhibit a blue color due to d-d transitions in the presence of water ligands.

The coordination number is determined by the number of ligands attached to the central metal ion. In [Co(NH3)6]Cl3, there are six NH3 ligands, so the coordination number is 6.

The complex formed is Ag(NH3)2+, which is known as the diamminesilver(I) ion.

The geometry of [Ag(NH3)2]+ is linear due to the coordination number of 2.

In [Ni(CN)4]2-, nickel is in the +2 oxidation state and undergoes dsp2 hybridization to accommodate the four cyanide ligands.

In [Cu(NH3)4]2+, the copper ion undergoes dsp2 hybridization to accommodate four ligands.

In [Ni(CO)4], the nickel ion undergoes sp3 hybridization to accommodate four CO ligands.

In K2[Cr2O7], the overall charge is 0. Each potassium (K) has a +1 charge, and each oxygen (O) has a -2 charge. Solving for chromium gives an oxidation state of +6.

Let the oxidation state of Cr be x. The equation is x + 4(0) + 2(-1) = +1 (from Cl). Solving gives x = +3.

Let the oxidation state of Cr be x. The equation is x + 4(0) + 2(-1) = +1. Solving gives x = +3.

Let the oxidation state of Cr be x. The equation is x + 4(0) + 2(-1) = +1. Solving gives x = +3.

The complex is neutral, and the three chloride ions contribute -3 charge. Therefore, the oxidation state of Cr must be +3.

The color of coordination compounds is influenced by the metal ion, ligands, and geometry, affecting d-d transitions.

In [Ni(CN)4]2-, nickel has a coordination number of 4 and uses dsp2 hybridization.

[Ni(CO)4] has a tetrahedral geometry, which corresponds to sp3 hybridization.

[Ni(CN)4]2- has a square planar geometry, which corresponds to dsp2 hybridization.

[Co(en)3]Cl3 shows optical isomerism because it has chiral centers due to the bidentate ligand ethylenediamine (en).

Geometric isomerism occurs due to different arrangements of ligands around the central metal ion.

[Co(en)3]3+ exhibits optical isomerism because it has chiral centers due to the bidentate ligand ethylenediamine (en).

The isomerism shown by [Co(NH3)5Cl]Br is coordination isomerism, where the composition of the complex changes.

[Cr(en)3]3+ shows optical isomerism because it has chiral centers due to the bidentate nature of the ethylenediamine (en) ligands.

Coordination isomerism occurs when the composition of the coordination sphere differs, as seen in this complex.

[Co(NH3)3Cl3] can exhibit geometrical isomerism due to the presence of different ligands in a square planar geometry.

The complex [Cr(en)3]3+ exhibits optical isomerism due to its chiral nature.

Ethylenediamine (en) is a bidentate ligand as it can form two bonds with the metal ion.

[Ni(CO)4] is diamagnetic because all electrons are paired in the presence of the strong field ligand CO.

[Co(NH3)6]3+ has unpaired electrons and is therefore paramagnetic.

EDTA is a bidentate ligand because it can form two bonds with a metal ion due to its two donor atoms.

CN- is a strong field ligand and causes a large splitting of d-orbitals, leading to low-spin complexes.