Q. A satellite is in a circular orbit around the Earth. If its speed is doubled, what happens to the radius of its orbit?
A.
It remains the same
B.
It doubles
C.
It increases by a factor of four
D.
It decreases by a factor of four
Solution
If the speed of a satellite is doubled, the radius of its orbit decreases by a factor of four due to the relationship between speed and radius in circular motion.
Correct Answer:
D
— It decreases by a factor of four
Q. A satellite is in a circular orbit around the Earth. If its speed is doubled, what will happen to its orbital radius?
A.
It will remain the same.
B.
It will double.
C.
It will increase by a factor of four.
D.
It will decrease by a factor of four.
Solution
If the speed of a satellite is doubled, the orbital radius will decrease by a factor of four, as orbital speed is inversely proportional to the square root of the radius.
Correct Answer:
D
— It will decrease by a factor of four.
Q. A satellite is in a circular orbit around the Earth. If the radius of the orbit is halved, what happens to the gravitational force acting on the satellite?
A.
It remains the same
B.
It doubles
C.
It quadruples
D.
It decreases by half
Solution
The gravitational force is inversely proportional to the square of the distance; halving the radius increases the force by a factor of four.
Q. If a satellite's speed is less than the required orbital speed, what will happen?
A.
It will remain in orbit.
B.
It will fall back to Earth.
C.
It will escape into space.
D.
It will move to a higher orbit.
Solution
If a satellite's speed is less than the required orbital speed, it will not have enough centripetal force to maintain its orbit and will fall back to Earth.
Q. If the radius of the Earth is R and a satellite is in a circular orbit at a height h above the Earth's surface, what is the expression for the orbital speed v of the satellite?
A.
v = sqrt(GM/(R+h))
B.
v = sqrt(GM/R)
C.
v = sqrt(GM/(R-h))
D.
v = sqrt(GM/(R^2 + h^2))
Solution
The orbital speed v of a satellite is given by v = sqrt(GM/(R+h)), where M is the mass of the Earth and G is the gravitational constant.
Q. If the radius of the Earth is R and a satellite is in a geostationary orbit, what is the height of the satellite above the Earth's surface?
A.
R/2
B.
R
C.
R/3
D.
R/4
Solution
A geostationary satellite orbits at a height of approximately 36,000 km above the Earth's surface, which is about R (the radius of the Earth) plus the height of the satellite.
Q. If the radius of the Earth is R and a satellite is in a low Earth orbit at a height h, what is the expression for the gravitational force acting on the satellite?
A.
G * M * m / (R + h)^2
B.
G * M * m / R^2
C.
G * M * m / (R - h)^2
D.
G * M * m / (R + h)
Solution
The gravitational force acting on the satellite is given by Newton's law of gravitation, which states that F = G * (M * m) / (R + h)^2, where M is the mass of the Earth and m is the mass of the satellite.
Understanding "Satellite Motion" is crucial for students preparing for various school and competitive exams. This topic not only forms a significant part of the physics syllabus but also helps in grasping fundamental concepts of motion and gravity. Practicing MCQs and objective questions on Satellite Motion can enhance your exam preparation, boost your confidence, and improve your chances of scoring better in exams.
What You Will Practise Here
Key concepts of satellite motion and its significance in physics.
Understanding the laws of planetary motion and gravitational force.
Formulas related to orbital velocity and period of satellites.
Types of satellites: geostationary and polar satellites.
Diagrams illustrating satellite orbits and trajectories.
Applications of satellites in communication and weather forecasting.
Common numerical problems related to satellite motion.
Exam Relevance
Satellite Motion is a recurring topic in CBSE, State Boards, NEET, and JEE exams. Students can expect questions that test their understanding of the laws governing satellite motion, calculations involving orbital speed, and the implications of satellite technology. Common question patterns include multiple-choice questions that require conceptual clarity and problem-solving skills, making it essential to practice thoroughly.
Common Mistakes Students Make
Confusing the concepts of geostationary and polar satellites.
Misapplying formulas related to orbital velocity and period.
Overlooking the significance of gravitational force in satellite motion.
Failing to interpret diagrams correctly, leading to errors in understanding orbits.
FAQs
Question: What is the difference between geostationary and polar satellites? Answer: Geostationary satellites orbit the Earth at the same rotational speed, appearing stationary over one point, while polar satellites pass over the poles, providing global coverage.
Question: How do I calculate the orbital velocity of a satellite? Answer: The orbital velocity can be calculated using the formula \( v = \sqrt{\frac{GM}{r}} \), where \( G \) is the gravitational constant, \( M \) is the mass of the Earth, and \( r \) is the distance from the center of the Earth to the satellite.
Now is the time to enhance your understanding of Satellite Motion! Dive into our practice MCQs and test your knowledge to excel in your exams. Remember, consistent practice is the key to success!
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