Energy stored U = 1/2 * C * V² = 1/2 * 10 × 10^-6 F * (50 V)² = 0.0125 J.

Energy U = 1/2 * C * V² = 1/2 * 5 × 10^-6 F * (12 V)² = 0.36 mJ.

Charge Q is given by Q = CV. Here, Q = 4 µF * 12 V = 48 µC.

The energy (U) stored in a capacitor is given by U = 1/2 CV², where C is the capacitance and V is the potential difference.

Energy stored in a capacitor is given by U = 1/2 CV² = 1/2 * 3 x 10^-6 F * (12 V)² = 0.36 mJ.

Energy stored U = 1/2 CV² = 1/2 * 4 x 10^-6 F * (12 V)² = 0.24 mJ.

The potential V across a capacitor is directly proportional to the charge. If the charge is doubled, the potential also doubles.

Potential energy U = q * V = -2 × 10^-6 C * 1000 N/C = -0.002 J.

Potential energy U = q * V = -4 × 10^-6 C * 200 N/C = -800 μJ.

Distance r = √(3² + 4²) = 5 m. V = k * q / r = (9 × 10^9) * (4 × 10^-6) / 5 = 720 V.

V = k * q / r = (9 × 10^9 N m²/C²) * (4 × 10^-6 C) / (3 m) = 1200 V.

Potential energy U = q * V, where V = E * d. Assuming d = 1 m, U = 4 × 10^-6 C * 1000 N/C * 1 m = 4 mJ.

Electric potential energy (U) = Charge × Electric Field = 5 μC × 2000 N/C = 10 mJ.

Potential energy (U) = Charge × Electric Field × Distance. Assuming distance = 1 m, U = 5 μC × 2000 N/C = 10 mJ.

Charge Q = C × V = 4 µF × 12 V = 48 µC.

As the charged particle moves to a lower potential, it loses potential energy, which is converted into kinetic energy, thus increasing its kinetic energy.

As the charged particle moves from high potential to low potential, it loses potential energy, which is converted into kinetic energy, thus its kinetic energy increases.

For a charged sphere, the electric potential outside the sphere behaves as if all the charge were concentrated at the center, so V = kQ/r.

The electric field E between the plates of a parallel plate capacitor is given by E = V/d, where d is the separation between the plates.

The electric potential V at a distance r from a point charge Q is given by V = kQ/r. Here, V = (9 x 10^9 Nm²/C²)(5 x 10^-6 C)/(2 m) = 1125 V.

The electric potential inside a charged spherical conductor is constant and equal to the potential on its surface, which is Q/(4πε₀R).

The electric potential V on the surface of a charged spherical conductor is given by V = kQ/R.

The potential difference V = E * d = 200 N/C * 3 m = 600 V.

The electric field is the negative gradient of the electric potential. If the potential is constant (0 V), the electric field is zero.

Electric potential energy U is given by U = VQ. Here, U = 10 V * 2 C = 20 J.

Work done W = q(V1 - V2) = 2 C (10 V - 0 V) = 20 J.

Work done = Charge × Potential = 2 C × 10 V = 20 J.

Distance d = V / E = 100 V / 50 N/C = 2 m.

Work done W = q * V = 2 C * 100 V = 200 J.

If the electric field is directed towards the point, it indicates that the charge creating the field is negative.