Q. A ball is thrown horizontally from the top of a cliff 45 m high. How far from the base of the cliff will it land if it is thrown with a speed of 10 m/s?
A.
20 m
B.
30 m
C.
40 m
D.
50 m
Solution
Time to fall = sqrt(2h/g) = sqrt(2*45/9.8) ≈ 3.03 s. Horizontal distance = speed * time = 10 * 3.03 ≈ 30.3 m, approximately 30 m.
Q. A ball is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will it land? (Assume g = 10 m/s² and horizontal speed = 20 m/s)
A.
20 m
B.
40 m
C.
60 m
D.
80 m
Solution
Time to fall = √(2h/g) = √(2*80/10) = 4 s. Horizontal distance = speed * time = 20 m/s * 4 s = 80 m.
Q. A ball is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will it land? (Assume g = 10 m/s² and initial horizontal speed = 20 m/s)
A.
40 m
B.
60 m
C.
80 m
D.
100 m
Solution
Time to fall = √(2h/g) = √(2*80/10) = 4 s. Horizontal distance = speed * time = 20 * 4 = 80 m.
Q. A ball is thrown horizontally from the top of a cliff with a speed of 15 m/s. If the cliff is 45 m high, how far from the base of the cliff will the ball land?
A.
30 m
B.
45 m
C.
60 m
D.
75 m
Solution
Time to fall = √(2h/g) = √(2*45/10) = 3 s. Horizontal distance = speed * time = 15 m/s * 3 s = 45 m.
Q. A body moves in a straight line with a uniform acceleration of 2 m/s². If its initial velocity is 5 m/s, what will be its velocity after 10 seconds?
A.
25 m/s
B.
20 m/s
C.
15 m/s
D.
10 m/s
Solution
Final velocity = initial velocity + acceleration * time = 5 + 2 * 10 = 25 m/s.
Understanding "Motion in One Dimension" is crucial for students preparing for various school and competitive exams. This topic lays the foundation for concepts in physics and is frequently tested through MCQs and objective questions. Practicing these questions not only enhances your conceptual clarity but also boosts your confidence, helping you score better in exams.
What You Will Practise Here
Basic definitions and concepts of motion in one dimension
Equations of motion and their applications
Graphical representation of motion: distance-time and velocity-time graphs
Understanding speed, velocity, and acceleration
Free fall and motion under gravity
Relative motion concepts
Solving numerical problems using formulas
Exam Relevance
The topic of "Motion in One Dimension" is a staple in CBSE, State Boards, NEET, and JEE exams. It often appears in the form of conceptual questions, numerical problems, and graphical analysis. Students can expect questions that require them to apply equations of motion or interpret graphs, making it essential to master this topic for effective exam preparation.
Common Mistakes Students Make
Confusing speed with velocity, especially in directional contexts
Misapplying equations of motion without understanding their conditions
Overlooking the significance of units in calculations
Failing to accurately interpret distance-time and velocity-time graphs
FAQs
Question: What are the key equations of motion in one dimension? Answer: The key equations include:
1) v = u + at,
2) s = ut + 1/2 at²,
3) v² = u² + 2as, where u is initial velocity, v is final velocity, a is acceleration, t is time, and s is displacement.
Question: How can I improve my understanding of this topic? Answer: Regular practice of MCQs and solving numerical problems will enhance your understanding and application of concepts in motion.
Now is the time to take charge of your exam preparation! Dive into our practice MCQs on Motion in One Dimension and test your understanding to achieve the best results in your upcoming exams.
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