Area of a circle = πr². Using π ≈ 3.14, Area = 3.14 × (7)² = 3.14 × 49 = 153.86 cm², which rounds to 154 cm².

Area of a circle = πr² = (22/7) × (7)² = (22/7) × 49 = 154 cm².

Area = πr² = 3.14 × (7)² = 3.14 × 49 = 153.86 cm², which rounds to 154 cm².

Radius = diameter/2 = 5 m. Area = πr² = 3.14 × 5² = 78.5 m².

Volume of cone = (1/3)πr²h; Volume of cylinder = πr²h. Therefore, cone's volume is one-third of the cylinder's volume.

Volume of a cone = (1/3)πr²h = (1/3)π(2)²(6) = (1/3)π(4)(6) = 8π cm³.

The surface area of a cone is given by SA = πr(r + l), where l is the slant height. Here, l = √(r² + h²) = √(2² + 6²) = √40. Thus, SA = π(2)(2 + √40) = 20π.

The surface area of a cone is given by SA = πr(r + l), where l is the slant height. Here, l = √(3² + 4²) = 5, so SA = π(3)(3 + 5) = 24π.

The volume of a cone is given by V = (1/3)πr²h. Here, r = 4 and h = 9, so V = (1/3)π(4)²(9) = 48π.

The surface area of a cone is given by SA = πr(r + l), where l is the slant height. Here, l = √(5² + 12²) = 13, so SA = π(5)(5 + 13) = 90π cm².

Volume = (1/3)πr²h = (1/3) * 3.14 * (4)² * 9 = 113.04 cm³.

The volume of a cylinder is given by V = πr²h. Substituting the values, V = π(3)²(10) = 90π cm³.

Using the volume formula V = πr²h, we have 100π = πr²(10). Thus, r² = 10, so r = √10 cm.

Using the volume formula V = πr²h, we have 200π = πr²(10). Thus, r² = 20, so r = √20 = 4.47 cm.

Volume = πr²h. Therefore, 100π = πr²(10) => r² = 10 => r = √10 ≈ 3.16 cm.

Total surface area = 2πr(h + r) = 2π(3)(5 + 3) = 2π(3)(8) = 48π ≈ 150.8 m².

The volume of a cylinder is given by the formula V = πr²h. Here, r = 3 and h = 5, so V = π(3)²(5) = 45π.

Volume of a hemisphere = (2/3)πr³ = (2/3)π(3)³ = (2/3)π(27) = 18π cm³.

Area = base × height = 8 × 5 = 40 m².

Perimeter = 2 × (length + width) = 2 × (12 + 5) = 2 × 17 = 34 m.

Let the width be x units. Then the length is 2x units. Area = length × width = 2x * x = 2x^2. Setting this equal to 200 gives 2x^2 = 200, so x^2 = 100, and x = 10 units.

Let the width be x meters. Then the length is 2x meters. Area = length × width = 2x * x = 2x^2. Setting this equal to 200 gives 2x^2 = 200, so x^2 = 100, and x = 10 meters.

Let the width be x cm, then the length is 2x cm. The perimeter is given by 2(length + width) = 48, which simplifies to 2(2x + x) = 48, leading to x = 8 cm. The area is length × width = 2x * x = 2(8)(8) = 128 cm².

Area = length × width. 48 = 12 × width, so width = 48/12 = 4 cm.

Area = length × width. Thus, 48 = 12 × width, giving width = 48/12 = 4 meters.

Area = length × width. Thus, 60 = 12 × width, giving width = 60/12 = 5 meters.

Let width = x, then length = 3x. Area = length × width = 3x * x = 3x² = 75. Thus, x² = 25, x = 5, and length = 15 meters.

Let width = x, then length = 3x. Perimeter = 2(length + width) = 2(3x + x) = 8x = 64, so x = 8 cm. Area = length × width = 3x * x = 3(8)(8) = 192 cm².

Perimeter = 2(length + width) = 2(50 + 30) = 2 × 80 = 160 m.

Area of the garden = 12 × 5 = 60 m². Area of the garden with the path = (12 + 2) × (5 + 2) = 14 × 7 = 98 m². Area of the path = 98 - 60 = 38 m².