The angle of the first minimum in single-slit diffraction is given by sin(θ) = λ/a, where a is the width of the slit.

According to the diffraction principle, as the slit width decreases, the width of the central maximum increases.

The angle for the first minimum in single-slit diffraction is given by a sin θ = λ, hence θ = λ/a.

For destructive interference in a thin film with a higher refractive index below, the condition is 2t = (m + 1/2)λ/n, where n is the refractive index of the film.

The angular separation (θ) is directly proportional to the wavelength (λ). Therefore, increasing λ increases the angular separation.

The fringe width is directly proportional to the wavelength. Therefore, increasing the wavelength increases the distance between the fringes.

Fringe separation is directly proportional to the wavelength. If the wavelength increases, the fringe separation also increases.

The position of the first minimum in single-slit diffraction is given by a sin(θ) = λ. Increasing λ will cause θ to increase, moving the minimum away from the center.

The width of the central maximum in single-slit diffraction is directly proportional to the wavelength. Increasing the wavelength increases the width.

Decreasing the distance between the slits increases the diffraction effect, causing the central maximum to become wider.

The central maximum has the maximum intensity because all light waves arrive in phase at this point, leading to constructive interference.

Fringe separation (β) = λD/d = (500 x 10^-9 m)(1 m)/(0.1 x 10^-3 m) = 0.5 mm.

Fringe width (β) is given by β = λD/d. If λ is halved, β will also be halved.

When light reflects off a denser medium, a phase change of π occurs, leading to destructive interference for certain path differences.

At the center of a thin film, constructive interference occurs for longer wavelengths (red light), making red the dominant color seen.

If destructive interference occurs for blue light, the color seen will be the complementary color, which is red.

If the film thickness causes constructive interference for blue light, blue will appear at the center of the pattern.

At the center of the thin film interference pattern, the color that appears is typically green due to the constructive interference of wavelengths in that range.

The color that appears at the center of the pattern corresponds to the wavelength that experiences constructive interference, which in this case is red light.

All these factors can affect the path difference and thus shift the interference pattern in thin film interference.

Increasing the slit width decreases the fringe width because the angle of diffraction decreases.

Fringe separation is directly proportional to the distance from the slits to the screen. Increasing this distance increases the fringe separation.

The maximum number of bright fringes is given by the formula n = d/λ. Here, n = 0.1 mm / 500 nm = 200, which means 20 bright fringes can be observed on either side of the central maximum.

The maximum number of bright fringes depends on the wavelength and the slit separation, as it determines how many integer multiples of the wavelength fit within the observable range.

For constructive interference in a soap bubble, the minimum thickness should be λ/4, accounting for the phase change upon reflection.

The angle of diffraction is directly proportional to the wavelength of light used in a diffraction grating, as described by the grating equation.

The angle of diffraction is inversely proportional to the wavelength; as the wavelength increases, the angle of diffraction decreases.