Kinematics Study Materials for Competitive Exams

Kinematics

Q. A ball is thrown upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (Take g = 10 m/s²) (2023)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Time to reach maximum height = initial velocity / g = 20 / 10 = 2 s.

Correct Answer: B — 2 s

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Q. A ball is thrown upwards with a speed of 25 m/s. How long will it take to reach the maximum height? (Assume g = 10 m/s²)

A. 2.5 s
B. 3 s
C. 4 s
D. 5 s

Solution

Time to reach maximum height = initial velocity / g = 25 / 10 = 2.5 s.

Correct Answer: A — 2.5 s

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Q. A ball is thrown upwards with an initial velocity of 20 m/s. How long will it take to reach the maximum height? (g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Using the formula: t = v/g = 20/10 = 2 s.

Correct Answer: B — 2 s

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Q. A ball is thrown vertically upwards with a speed of 15 m/s. How high will it rise before coming to a stop? (2023)

A. 11.25 m
B. 15 m
C. 22.5 m
D. 30 m

Solution

Using the formula: height = (initial velocity^2) / (2 * g), where g = 9.8 m/s². Height = (15^2) / (2 * 9.8) = 11.25 m.

Correct Answer: A — 11.25 m

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Q. A car moving at 30 m/s applies brakes and comes to a stop in 6 seconds. What is the distance covered during braking? (2023)

A. 90 m
B. 120 m
C. 150 m
D. 180 m

Solution

Using the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. Here, acceleration = (0 - 30) / 6 = -5 m/s². Distance = 30 * 6 + 0.5 * (-5) * 6^2 = 180 - 90 = 90 m.

Correct Answer: B — 120 m

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Q. A cyclist travels at a speed of 10 m/s for 5 seconds. What distance does he cover? (2023)

A. 25 m
B. 50 m
C. 75 m
D. 100 m

Solution

Distance = speed * time = 10 m/s * 5 s = 50 m.

Correct Answer: B — 50 m

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Q. A cyclist travels at a speed of 15 m/s for 2 minutes. How far does he travel?

A. 1800 m
B. 1200 m
C. 900 m
D. 600 m

Solution

Distance = speed * time. Time in seconds = 2 * 60 = 120 s. Distance = 15 m/s * 120 s = 1800 m.

Correct Answer: A — 1800 m

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Q. A cyclist travels at a speed of 15 m/s for 2 minutes. How far does the cyclist travel?

A. 1800 m
B. 1200 m
C. 900 m
D. 600 m

Solution

Distance = speed * time. Time in seconds = 2 minutes = 120 seconds. Distance = 15 m/s * 120 s = 1800 m.

Correct Answer: A — 1800 m

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Q. A cyclist travels at a speed of 15 m/s for 20 seconds. What distance does he cover?

A. 200 m
B. 300 m
C. 400 m
D. 500 m

Solution

Distance = speed * time = 15 m/s * 20 s = 300 m.

Correct Answer: C — 400 m

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Q. A cyclist travels at a speed of 15 m/s for 20 seconds. What distance does the cyclist cover?

A. 150 m
B. 300 m
C. 400 m
D. 600 m

Solution

Distance = speed * time = 15 m/s * 20 s = 300 m.

Correct Answer: B — 300 m

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Q. A projectile is launched at an angle of 30 degrees with an initial speed of 20 m/s. What is the maximum height reached? (g = 10 m/s²)

A. 5 m
B. 10 m
C. 15 m
D. 20 m

Solution

Maximum height h = (u^2 * sin²θ) / (2g) = (20² * (1/2)²) / (2 * 10) = 5 m.

Correct Answer: B — 10 m

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Q. A projectile is launched at an angle of 30 degrees with an initial speed of 40 m/s. What is the maximum height reached? (g = 10 m/s²)

A. 80 m
B. 60 m
C. 40 m
D. 20 m

Solution

Maximum height = (u^2 * sin²θ) / (2g) = (40^2 * (1/2)) / (2 * 10) = 80 m.

Correct Answer: B — 60 m

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Q. A runner completes a 400 m lap in 50 seconds. What is his average velocity?

A. 6 m/s
B. 7 m/s
C. 8 m/s
D. 9 m/s

Solution

Average velocity = total distance / total time = 400 m / 50 s = 8 m/s.

Correct Answer: A — 6 m/s

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Q. A runner completes a 400 m lap in 50 seconds. What is the runner's average velocity?

A. 8 m/s
B. 6 m/s
C. 4 m/s
D. 2 m/s

Solution

Average velocity = total displacement / total time. Since the runner returns to the starting point, displacement = 0. Average velocity = 0 m/s.

Correct Answer: A — 8 m/s

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Q. A stone is thrown horizontally from a height of 45 m. How long will it take to hit the ground? (Take g = 10 m/s²) (2023)

A. 3 s
B. 4.5 s
C. 5 s
D. 6 s

Solution

Using h = 0.5 * g * t^2, we have 45 = 0.5 * 10 * t^2. Solving gives t^2 = 9, so t = 3 s.

Correct Answer: A — 3 s

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Q. A stone is thrown horizontally from the top of a cliff 45 m high. How long does it take to hit the ground? (g = 10 m/s²)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using h = 0.5 * g * t^2, rearranging gives t = sqrt(2h/g) = sqrt(2 * 45 / 10) = sqrt(9) = 3 s.

Correct Answer: B — 4 s

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Q. A stone is thrown horizontally from the top of a cliff 45 m high. How long does it take to hit the ground? (Assume g = 10 m/s²)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using h = 0.5 * g * t^2, rearranging gives t = sqrt(2h/g) = sqrt(2 * 45 / 10) = sqrt(9) = 3 s.

Correct Answer: B — 4 s

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Q. A stone is thrown horizontally from the top of a cliff 45 m high. How long will it take to hit the ground? (Assume g = 10 m/s²)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using the formula: h = 0.5 * g * t^2. Rearranging gives t = sqrt(2h/g) = sqrt(2 * 45 / 10) = sqrt(9) = 3 s.

Correct Answer: B — 4 s

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Q. A stone is thrown horizontally from the top of a cliff 80 m high. How long does it take to hit the ground? (g = 10 m/s²)

A. 4 s
B. 8 s
C. 10 s
D. 12 s

Solution

Using the formula: h = 0.5 * g * t^2. Rearranging gives t = sqrt(2h/g) = sqrt(2 * 80 / 10) = sqrt(16) = 4 s.

Correct Answer: A — 4 s

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Q. A train moving at 72 km/h applies brakes and comes to a stop in 10 seconds. What is the acceleration of the train?

A. -2 m/s²
B. -3 m/s²
C. -4 m/s²
D. -5 m/s²

Solution

First convert speed to m/s: 72 km/h = 20 m/s. Using the formula: a = (v - u) / t = (0 - 20) / 10 = -2 m/s².

Correct Answer: C — -4 m/s²

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Q. A train moving at 72 km/h applies brakes and comes to a stop in 5 seconds. What is the deceleration? (2023)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

First convert speed to m/s: 72 km/h = 20 m/s. Deceleration = (final velocity - initial velocity) / time = (0 - 20) / 5 = -4 m/s².

Correct Answer: C — 4 m/s²

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Q. A train moving at 72 km/h applies brakes and comes to a stop in 5 seconds. What is the acceleration of the train?

A. -4 m/s²
B. -5 m/s²
C. -6 m/s²
D. -7 m/s²

Solution

First convert speed to m/s: 72 km/h = 20 m/s. Using the formula: acceleration = (final velocity - initial velocity) / time = (0 - 20) / 5 = -4 m/s².

Correct Answer: B — -5 m/s²

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Q. A vehicle travels 100 m in 5 seconds. What is its average speed?

A. 10 m/s
B. 15 m/s
C. 20 m/s
D. 25 m/s

Solution

Average speed = total distance / total time = 100 m / 5 s = 20 m/s.

Correct Answer: A — 10 m/s

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Q. A vehicle travels with a uniform speed of 60 km/h. How far will it travel in 2 hours? (2023)

A. 80 km
B. 100 km
C. 120 km
D. 140 km

Solution

Distance = speed * time = 60 km/h * 2 h = 120 km.

Correct Answer: C — 120 km

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Q. An object is dropped from a height of 80 m. How long will it take to reach the ground? (Take g = 10 m/s²) (2023)

A. 4 s
B. 8 s
C. 10 s
D. 12 s

Solution

Using the formula: h = 0.5 * g * t^2. Rearranging gives t = sqrt(2h/g) = sqrt(2*80/10) = sqrt(16) = 4 s.

Correct Answer: B — 8 s

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Q. An object moves with a uniform acceleration of 2 m/s². If it starts from rest, what will be its velocity after 5 seconds?

A. 5 m/s
B. 10 m/s
C. 15 m/s
D. 20 m/s

Solution

Using the formula: v = u + at, where u = 0, a = 2 m/s², t = 5 s. v = 0 + 2 * 5 = 10 m/s.

Correct Answer: B — 10 m/s

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Q. An object moves with a uniform speed of 10 m/s. How far will it travel in 15 seconds?

A. 100 m
B. 150 m
C. 200 m
D. 250 m

Solution

Distance = speed * time = 10 m/s * 15 s = 150 m.

Correct Answer: B — 150 m

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Q. An object moves with a uniform speed of 20 m/s. How far will it travel in 15 seconds?

A. 200 m
B. 300 m
C. 400 m
D. 500 m

Solution

Distance = speed * time = 20 m/s * 15 s = 300 m.

Correct Answer: C — 400 m

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Q. If a vehicle accelerates from 0 to 60 m/s in 12 seconds, what is its acceleration?

A. 2 m/s²
B. 4 m/s²
C. 5 m/s²
D. 6 m/s²

Solution

Using the formula: a = (v - u) / t = (60 - 0) / 12 = 5 m/s².

Correct Answer: B — 4 m/s²

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Kinematics

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