Physics Study Resources for Competitive Exams

Physics

AC Circuits Current Electricity Electromagnetic Induction Electrostatics Gravitation Heat & Thermodynamics Kinematics Laws of Motion Magnetism Modern Physics Oscillations & Waves Ray Optics Rotational Motion Units & Dimensions Wave Optics Work, Energy & Power

Q. A 0.5 kg ball is thrown vertically upwards with a speed of 20 m/s. What is the maximum height it reaches?

A. 10 m
B. 20 m
C. 30 m
D. 40 m

Solution

Using the formula h = v²/(2g), where v = 20 m/s and g = 9.8 m/s², h = (20)²/(2 * 9.8) ≈ 20.4 m, which rounds to 20 m.

Correct Answer: B — 20 m

Learn More →

Q. A 1 kg ball is dropped from a height of 20 m. What is its velocity just before it hits the ground? (g = 10 m/s²) (2021)

A. 10 m/s
B. 20 m/s
C. 15 m/s
D. 5 m/s

Solution

Using the formula v = √(2gh) = √(2 × 10 m/s² × 20 m) = √400 = 20 m/s.

Correct Answer: B — 20 m/s

Learn More →

Q. A 1 kg ball is thrown horizontally from a height of 5 m. How long does it take to hit the ground? (g = 10 m/s²) (2022)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Using the formula h = 1/2 gt², 5 m = 1/2 * 10 m/s² * t², t² = 1, t = √1 = 2 s.

Correct Answer: B — 2 s

Learn More →

Q. A 1 kg ball is thrown vertically upwards with a velocity of 20 m/s. What is the maximum height it reaches? (g = 10 m/s²) (2021)

A. 20 m
B. 30 m
C. 40 m
D. 10 m

Solution

Using the formula h = v² / (2g) = (20 m/s)² / (2 × 10 m/s²) = 20 m.

Correct Answer: A — 20 m

Learn More →

Q. A 1 kg block of ice at 0°C is placed in 2 kg of water at 20°C. What will be the final temperature of the mixture? (Specific heat of water = 4.2 kJ/kg°C, Latent heat of fusion of ice = 334 kJ/kg) (2021)

A. 0°C
B. 10°C
C. 20°C
D. 15°C

Solution

Heat lost by water = Heat gained by ice. Calculate to find the final temperature.

Correct Answer: B — 10°C

Learn More →

Q. A 1 kg block of ice at 0°C is placed in 2 kg of water at 20°C. What will be the final temperature of the mixture? (Assume no heat loss to the surroundings)

A. 0°C
B. 10°C
C. 15°C
D. 20°C

Solution

Using the principle of conservation of energy, the heat lost by water equals the heat gained by ice. Final temperature can be calculated to be approximately 10°C.

Correct Answer: B — 10°C

Learn More →

Q. A 1 kg block of ice at 0°C is placed in 2 kg of water at 80°C. What will be the final temperature of the mixture? (Assume no heat loss to the surroundings) (2019)

A. 0°C
B. 40°C
C. 60°C
D. 80°C

Solution

Using the principle of conservation of energy, the heat lost by water equals the heat gained by ice. The final temperature will be 0°C as the ice will melt.

Correct Answer: B — 40°C

Learn More →

Q. A 1 kg block of metal at 100°C is placed in 2 kg of water at 20°C. Assuming no heat loss to the surroundings, what will be the final temperature? (Specific heat of water = 4.2 kJ/kg°C) (2022)

A. 25°C
B. 30°C
C. 35°C
D. 40°C

Solution

Using the principle of conservation of energy, set heat lost by metal equal to heat gained by water to find the final temperature.

Correct Answer: C — 35°C

Learn More →

Q. A 1 kg block of metal at 100°C is placed in 2 kg of water at 20°C. Assuming no heat loss to the surroundings, what is the final temperature of the system? (Specific heat of water = 4.18 kJ/kg°C, specific heat of metal = 0.9 kJ/kg°C) (2020)

A. 25°C
B. 30°C
C. 35°C
D. 40°C

Solution

Using the principle of conservation of energy, set heat lost by metal equal to heat gained by water to find the final temperature.

Correct Answer: C — 35°C

Learn More →

Q. A 1 kg block of metal at 100°C is placed in 2 kg of water at 20°C. If the final temperature of the system is 30°C, what is the specific heat capacity of the metal? (Specific heat of water = 4.18 J/g°C) (2020)

A. 0.5 J/g°C
B. 1.0 J/g°C
C. 1.5 J/g°C
D. 2.0 J/g°C

Solution

Using the principle of conservation of energy, calculate the specific heat capacity of the metal.

Correct Answer: B — 1.0 J/g°C

Learn More →

Q. A 1 kg block of metal at 100°C is placed in 2 kg of water at 20°C. What is the final temperature of the system? (Specific heat of water = 4.18 J/g°C, specific heat of metal = 0.9 J/g°C) (2021)

A. 25°C
B. 30°C
C. 35°C
D. 40°C

Solution

Using conservation of energy: m1*c1*(T_initial - T_final) = m2*c2*(T_final - T_initial). Solving gives T_final = 35°C.

Correct Answer: C — 35°C

Learn More →

Q. A 1 kg block of metal at 100°C is placed in 2 kg of water at 20°C. What will be the final temperature of the system assuming no heat loss? (2022)

A. 30°C
B. 40°C
C. 50°C
D. 60°C

Solution

Using the principle of conservation of energy: m1*c1*(T_initial1 - T_final) = m2*c2*(T_final - T_initial2). Solving gives T_final = 50°C.

Correct Answer: C — 50°C

Learn More →

Q. A 1 kg object is dropped from a height. What is its velocity just before it hits the ground (neglect air resistance)? (2020)

A. 10 m/s
B. 14 m/s
C. 20 m/s
D. 30 m/s

Solution

Using v² = u² + 2gh, v = √(0 + 2 × 9.8 m/s² × h). For h = 20 m, v = √(392) = 20 m/s.

Correct Answer: C — 20 m/s

Learn More →

Q. A 10 kg block is pushed with a force of 50 N. What is its acceleration? (2023)

A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 15 m/s²

Solution

Using Newton's second law, F = ma, we have a = F/m = 50 N / 10 kg = 5 m/s².

Correct Answer: B — 5 m/s²

Learn More →

Q. A 10 kg object is at rest. A force of 30 N is applied. What is the final velocity after 3 seconds? (2023)

A. 3 m/s
B. 6 m/s
C. 9 m/s
D. 12 m/s

Solution

Using F = ma, a = F/m = 30 N / 10 kg = 3 m/s². Final velocity v = u + at = 0 + 3 m/s² × 3 s = 9 m/s.

Correct Answer: B — 6 m/s

Learn More →

Q. A 10 kg object is dropped from a height of 20 m. What is its potential energy at the top? (2020)

A. 200 J
B. 1000 J
C. 1500 J
D. 3000 J

Solution

Potential Energy = mass × g × height = 10 kg × 10 m/s² × 20 m = 2000 J

Correct Answer: B — 1000 J

Learn More →

Q. A 10 kg object is dropped from a height of 20 m. What is its potential energy at the top? (g = 9.8 m/s²) (1960)

A. 196 J
B. 98 J
C. 294 J
D. 490 J

Solution

Potential Energy (PE) = mgh = 10 kg × 9.8 m/s² × 20 m = 1960 J.

Correct Answer: C — 294 J

Learn More →

Q. A 10 kg object is dropped from a height of 20 m. What is the potential energy at the top? (2022)

A. 200 J
B. 1000 J
C. 500 J
D. 400 J

Solution

Potential Energy = mass × g × height = 10 kg × 9.8 m/s² × 20 m = 1960 J

Correct Answer: B — 1000 J

Learn More →

Q. A 10 kg object is lifted to a height of 2 m. What is the work done against gravity? (g = 9.8 m/s²)

A. 196 J
B. 98 J
C. 20 J
D. 39.2 J

Solution

Work done (W) = m × g × h = 10 kg × 9.8 m/s² × 2 m = 196 J.

Correct Answer: A — 196 J

Learn More →

Q. A 10 kg object is moving with a velocity of 4 m/s. What is its kinetic energy?

A. 80 J
B. 40 J
C. 20 J
D. 160 J

Solution

Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 10 kg × (4 m/s)² = 80 J

Correct Answer: A — 80 J

Learn More →

Q. A 10 kg object is subjected to a net force of 30 N. What is its acceleration? (2022)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².

Correct Answer: B — 3 m/s²

Learn More →

Q. A 10 kg object is thrown upwards with a velocity of 15 m/s. What is the maximum height it reaches? (g = 9.8 m/s²)

A. 11.5 m
B. 22.5 m
C. 15.0 m
D. 7.5 m

Solution

Using energy conservation: KE_initial = PE_max; 0.5 * m * v² = mgh; h = v² / (2g) = (15 m/s)² / (2 * 9.8 m/s²) = 11.5 m.

Correct Answer: A — 11.5 m

Learn More →

Q. A 10 kg object is thrown vertically upward with a speed of 20 m/s. What is the maximum height reached by the object? (g = 10 m/s²) (2020)

A. 20 m
B. 30 m
C. 40 m
D. 50 m

Solution

Using the formula h = v² / (2g), h = (20 m/s)² / (2 * 10 m/s²) = 20 m.

Correct Answer: B — 30 m

Learn More →

Q. A 10 kg object is thrown vertically upwards with a velocity of 20 m/s. What is the maximum height it reaches? (g = 10 m/s²) (2023)

A. 20 m
B. 40 m
C. 30 m
D. 10 m

Solution

Using the formula h = (v²)/(2g) = (20 m/s)² / (2 × 10 m/s²) = 20 m.

Correct Answer: B — 40 m

Learn More →

Q. A 10 N force is applied at an angle of 60° to the horizontal while moving an object 4 m. What is the work done?

A. 20 J
B. 40 J
C. 30 J
D. 10 J

Solution

Work done (W) = F × d × cos(θ) = 10 N × 4 m × cos(60°) = 10 × 4 × 0.5 = 20 J.

Correct Answer: C — 30 J

Learn More →

Q. A 10 N force is applied to move an object 3 m. What is the work done if the force is applied at an angle of 60 degrees to the direction of motion?

A. 15 J
B. 30 J
C. 25 J
D. 20 J

Solution

Work done = Force × Distance × cos(θ) = 10 N × 3 m × cos(60°) = 10 N × 3 m × 0.5 = 15 J

Correct Answer: A — 15 J

Learn More →

Q. A 10 Ω resistor is connected to a 20 V battery. What is the current flowing through the resistor?

A. 2 A
B. 0.5 A
C. 5 A
D. 10 A

Solution

Using Ohm's law, V = IR, where V = 20 V and R = 10 Ω. Therefore, I = V/R = 20/10 = 2 A.

Correct Answer: A — 2 A

Learn More →

Q. A 100 g piece of metal at 100°C is placed in 200 g of water at 20°C. What will be the final temperature of the system? (Specific heat of water = 4.2 J/g°C, specific heat of metal = 0.5 J/g°C) (2023)

A. 30°C
B. 40°C
C. 50°C
D. 60°C

Solution

Using the heat transfer equation, we can find the final temperature to be 50°C.

Correct Answer: C — 50°C

Learn More →

Q. A 100 W bulb is connected to a 220 V supply. What is the current flowing through the bulb?

A. 0.45 A
B. 1.0 A
C. 2.2 A
D. 2.5 A

Solution

Using the formula P = VI, where P = 100 W and V = 220 V, the current I = P/V = 100/220 ≈ 0.45 A.

Correct Answer: A — 0.45 A

Learn More →

Q. A 100 W bulb is used for 5 hours. How much energy does it consume? (2016)

A. 500 Wh
B. 1000 Wh
C. 200 Wh
D. 250 Wh

Solution

Energy consumed = Power × Time = 100 W × 5 h = 500 Wh.

Correct Answer: A — 500 Wh

Learn More →

Showing 1 to 30 of 846 (29 Pages)

Physics

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?