Increasing the size of the halogen atom generally increases the reactivity of haloalkanes due to the weaker C-X bond.

As the size of the halogen increases, the bond strength decreases due to the longer bond length and weaker overlap.

The reaction forms a Grignard reagent, which is an organomagnesium compound.

The reaction of benzene with bromine in the presence of FeBr3 leads to the formation of bromobenzene through electrophilic aromatic substitution.

The reaction of 1-bromopropane with magnesium in dry ether forms propylmagnesium bromide, a Grignard reagent.

The reaction forms propylmagnesium chloride, a Grignard reagent.

Chlorobenzene reacts with sodium hydroxide at high temperature to form phenol through nucleophilic aromatic substitution.

The reaction is an example of an SN2 reaction, where sodium ethoxide acts as a nucleophile, leading to the formation of 1-ethoxybutane.

The reaction leads to the formation of 1-butanol through an SN2 mechanism.

The reaction of chlorobenzene with sodium hydroxide at high temperature leads to the formation of phenol through nucleophilic substitution.

The reaction of 1-bromobutane with sodium ethoxide leads to the formation of ethyl butyl ether through an SN2 mechanism.

The reaction is an example of an SN2 reaction, leading to the formation of 1-ethoxybutane.

The reaction leads to the formation of 1-cyanobutane through nucleophilic substitution.

The reaction leads to the formation of 2-methylpropene through an elimination reaction.

The reaction of 1-chloropropane with potassium tert-butoxide leads to the formation of propene via an elimination reaction.

Chlorobenzene reacts with sodium hydroxide at high temperature to form phenol.

The hydrolysis of 1-chloropropane in the presence of water yields propan-1-ol as the main product.

The reaction of 1-bromopropane with sodium ethoxide leads to the formation of ethyl propyl ether through nucleophilic substitution.

1-cyanobutane is formed through nucleophilic substitution where the cyanide ion acts as a nucleophile.

Chlorobenzene reacts with sodium hydroxide in the presence of heat to form phenol via nucleophilic substitution.

The reaction of chlorobenzene with sodium hydroxide at high temperature leads to the formation of phenol through nucleophilic aromatic substitution.

1-bromobutane and 2-bromobutane are structural isomers as they differ in the position of the bromine atom.

The reaction of 2-bromopropane with a strong nucleophile typically follows the SN2 mechanism due to steric hindrance.

The reaction is a nucleophilic substitution where the cyanide ion replaces the bromine atom.

The treatment of 2-bromobutane with sodium ethoxide leads to an elimination reaction, forming an alkene.

Chlorobenzene undergoes nucleophilic substitution to form phenol when treated with sodium hydroxide at high temperature.

Haloalkanes react with alcoholic KOH primarily through nucleophilic substitution to form alcohols.

C4H9Cl (butyl chloride) has the highest molecular weight and thus the highest boiling point due to increased van der Waals forces.

Iodoethane is least soluble in water due to its larger non-polar iodine atom, which decreases the overall polarity of the molecule.

2-chloropropane can undergo elimination to form propene, while the others are less favorable for elimination.