Coordination Compounds
Q. In the complex [Ni(CO)4], what is the hybridization of the nickel atom?
A.
sp
B.
sp2
C.
sp3
D.
d2sp3
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Solution
Nickel in [Ni(CO)4] undergoes sp3 hybridization as it forms four sigma bonds with CO ligands.
Correct Answer: C — sp3
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Q. What is the color of the complex [Cu(H2O)6]2+?
A.
Blue
B.
Green
C.
Red
D.
Yellow
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Solution
[Cu(H2O)6]2+ is known to exhibit a blue color due to d-d transitions in the presence of water ligands.
Correct Answer: A — Blue
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Q. What is the coordination number of the central metal ion in the complex [Co(NH3)6]Cl3?
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Solution
The coordination number is determined by the number of ligands attached to the central metal ion. In [Co(NH3)6]Cl3, there are six NH3 ligands, so the coordination number is 6.
Correct Answer: C — 6
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Q. What is the formula for the complex formed when silver ion reacts with ammonia?
A.
Ag(NH3)2+
B.
Ag(NH3)2Cl
C.
Ag(NH3)3+
D.
Ag(NH3)4+
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Solution
The complex formed is Ag(NH3)2+, which is known as the diamminesilver(I) ion.
Correct Answer: A — Ag(NH3)2+
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Q. What is the geometry of the complex [Ag(NH3)2]+?
A.
Linear
B.
Tetrahedral
C.
Square Planar
D.
Octahedral
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Solution
The geometry of [Ag(NH3)2]+ is linear due to the coordination number of 2.
Correct Answer: A — Linear
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Q. What is the hybridization of the central metal ion in the complex [Cu(NH3)4]2+?
A.
sp
B.
sp2
C.
sp3
D.
dsp2
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Solution
In [Cu(NH3)4]2+, the copper ion undergoes dsp2 hybridization to accommodate four ligands.
Correct Answer: D — dsp2
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Q. What is the hybridization of the central metal ion in [Ni(CO)4]?
A.
sp
B.
sp2
C.
sp3
D.
d2sp3
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Solution
In [Ni(CO)4], the nickel ion undergoes sp3 hybridization to accommodate four CO ligands.
Correct Answer: C — sp3
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Q. What is the oxidation state of chromium in the complex [Cr(NH3)4Cl2]Cl?
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Solution
Let the oxidation state of Cr be x. The equation is x + 4(0) + 2(-1) = +1 (from Cl). Solving gives x = +3.
Correct Answer: B — +3
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Q. What is the oxidation state of chromium in [Cr(NH3)4Cl2]+?
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Solution
Let the oxidation state of Cr be x. The equation is x + 4(0) + 2(-1) = +1. Solving gives x = +3.
Correct Answer: B — +3
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Q. What is the oxidation state of chromium in [Cr(NH3)4Cl2]Cl?
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Solution
Let the oxidation state of Cr be x. The equation is x + 4(0) + 2(-1) = +1. Solving gives x = +3.
Correct Answer: B — +3
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Q. What is the oxidation state of chromium in [Cr(NH3)6]Cl3?
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Solution
The complex is neutral, and the three chloride ions contribute -3 charge. Therefore, the oxidation state of Cr must be +3.
Correct Answer: B — +3
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Q. What is the primary factor that determines the color of coordination compounds?
A.
Nature of the metal ion
B.
Nature of the ligands
C.
Geometry of the complex
D.
All of the above
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Solution
The color of coordination compounds is influenced by the metal ion, ligands, and geometry, affecting d-d transitions.
Correct Answer: D — All of the above
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Q. What type of hybridization occurs in the complex ion [Ni(CN)4]2-?
A.
sp
B.
sp2
C.
sp3
D.
dsp2
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Solution
In [Ni(CN)4]2-, nickel has a coordination number of 4 and uses dsp2 hybridization.
Correct Answer: D — dsp2
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Q. What type of hybridization occurs in the complex [Ni(CO)4]?
A.
sp
B.
sp2
C.
sp3
D.
d2sp3
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Solution
[Ni(CO)4] has a tetrahedral geometry, which corresponds to sp3 hybridization.
Correct Answer: C — sp3
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Q. What type of hybridization occurs in [Ni(CN)4]2-?
A.
sp
B.
sp2
C.
sp3
D.
dsp2
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Solution
[Ni(CN)4]2- has a square planar geometry, which corresponds to dsp2 hybridization.
Correct Answer: D — dsp2
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Q. What type of isomerism is shown by the complex [Co(en)3]Cl3?
A.
Geometrical
B.
Optical
C.
Structural
D.
Coordination
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Solution
[Co(en)3]Cl3 shows optical isomerism because it has chiral centers due to the bidentate ligand ethylenediamine (en).
Correct Answer: B — Optical
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Q. What type of isomerism is shown by the complex [Co(NH3)5Cl]Br?
A.
Geometric
B.
Optical
C.
Linkage
D.
Coordination
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Solution
Geometric isomerism occurs due to different arrangements of ligands around the central metal ion.
Correct Answer: A — Geometric
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Q. What type of isomerism is shown by [Co(en)3]3+?
A.
Geometrical
B.
Optical
C.
Structural
D.
Linkage
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Solution
[Co(en)3]3+ exhibits optical isomerism because it has chiral centers due to the bidentate ligand ethylenediamine (en).
Correct Answer: B — Optical
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Q. What type of isomerism is shown by [Cr(en)3]3+?
A.
Geometrical
B.
Optical
C.
Linkage
D.
Coordination
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Solution
[Cr(en)3]3+ shows optical isomerism because it has chiral centers due to the bidentate nature of the ethylenediamine (en) ligands.
Correct Answer: B — Optical
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Q. What type of isomerism is shown by [Cr(NH3)5Cl]SO4?
A.
Geometrical
B.
Optical
C.
Linkage
D.
Coordination
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Solution
Coordination isomerism occurs when the composition of the coordination sphere differs, as seen in this complex.
Correct Answer: D — Coordination
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Q. Which of the following complexes exhibits geometrical isomerism?
A.
[Co(NH3)3Cl3]
B.
[Ni(CN)4]2-
C.
[CuCl4]2-
D.
[Fe(CO)6]
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Solution
[Co(NH3)3Cl3] can exhibit geometrical isomerism due to the presence of different ligands in a square planar geometry.
Correct Answer: A — [Co(NH3)3Cl3]
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Q. Which of the following complexes exhibits optical isomerism?
A.
[Cr(en)3]3+
B.
[Co(NH3)6]3+
C.
[NiCl2(H2O)4]
D.
[CuCl2]
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Solution
The complex [Cr(en)3]3+ exhibits optical isomerism due to its chiral nature.
Correct Answer: A — [Cr(en)3]3+
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Q. Which of the following complexes is an example of a bidentate ligand?
A.
[Cu(NH3)4]SO4
B.
[Fe(CN)6]3-
C.
[Ni(en)3]Cl2
D.
[AgCl2]-
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Solution
Ethylenediamine (en) is a bidentate ligand as it can form two bonds with the metal ion.
Correct Answer: C — [Ni(en)3]Cl2
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Q. Which of the following complexes is expected to be diamagnetic?
A.
[Fe(H2O)6]3+
B.
[Cu(NH3)4]2+
C.
[Co(NH3)6]3+
D.
[Ni(CO)4]
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Solution
[Ni(CO)4] is diamagnetic because all electrons are paired in the presence of the strong field ligand CO.
Correct Answer: D — [Ni(CO)4]
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Q. Which of the following complexes is paramagnetic?
A.
[Fe(CN)6]3-
B.
[Co(NH3)6]3+
C.
[CuCl4]2-
D.
[MnO4]-
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Solution
[Co(NH3)6]3+ has unpaired electrons and is therefore paramagnetic.
Correct Answer: B — [Co(NH3)6]3+
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Q. Which of the following is a bidentate ligand?
A.
NH3
B.
EDTA
C.
Cl-
D.
H2O
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Solution
EDTA is a bidentate ligand because it can form two bonds with a metal ion due to its two donor atoms.
Correct Answer: B — EDTA
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Q. Which of the following ligands is a strong field ligand?
A.
I-
B.
Br-
C.
CN-
D.
Cl-
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Solution
CN- is a strong field ligand and causes a large splitting of d-orbitals, leading to low-spin complexes.
Correct Answer: C — CN-
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Q. Which of the following statements is true about coordination compounds?
A.
They always have a positive charge
B.
They can exhibit color
C.
They cannot form complexes
D.
They are always soluble in water
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Solution
Coordination compounds can exhibit color due to d-d transitions and are not limited to having a positive charge.
Correct Answer: B — They can exhibit color
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Q. Which of the following statements is true about the complex ion [Co(NH3)6]3+?
A.
It is paramagnetic
B.
It is diamagnetic
C.
It has a coordination number of 4
D.
It contains a transition metal
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Solution
Cobalt is a transition metal, and the complex has a coordination number of 6.
Correct Answer: D — It contains a transition metal
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Q. Which of the following statements is true about the complex [Cr(NH3)6]3+?
A.
It is tetrahedral
B.
It is octahedral
C.
It is square planar
D.
It is linear
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Solution
[Cr(NH3)6]3+ has an octahedral geometry due to the six ligands surrounding the chromium ion.
Correct Answer: B — It is octahedral
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