Speed of light in medium = c/n = (3 x 10^8 m/s) / 1.33 ≈ 2.25 x 10^8 m/s.

Wavelength in medium = λ/v = λ0/n = 600 nm / 1.5 = 400 nm.

The speed of light in a medium is given by v = c/n, where n is the refractive index. If n > 1, the speed decreases.

The speed of light in a medium is given by v = c/n, where n is the refractive index. If n > 1, then v < c, meaning the speed decreases.

The speed of light in a medium is less than that in vacuum, given by v = c/n, where n > 1.

The wavelength of light decreases in a medium with a refractive index greater than 1, as it is given by λ' = λ/n.

The wavelength of light decreases in a medium with a refractive index greater than 1, as λ' = λ/n.

When light reflects off a medium with a higher refractive index, it undergoes a phase change of π (180 degrees).

Increasing the number of slits increases the intensity of the maxima due to constructive interference.

Increasing the number of slits increases the sharpness of the maxima, thus decreasing the angular width.

Increasing the slit width results in a wider central maximum due to the decrease in diffraction effects.

Fringe separation is directly proportional to the distance from the slits to the screen; increasing this distance increases fringe separation.

Fringe separation is directly proportional to the distance from the slits to the screen (D), hence it increases.

Moving one mirror changes the path length of one beam, causing the fringes to move apart or closer depending on the direction of movement.

Moving one of the mirrors changes the path length of one beam, causing a shift in the interference pattern.

Moving one of the mirrors changes the path length, causing a shift in the interference pattern (fringes).

For single-slit diffraction, the first minimum occurs at sin θ = λ/a. Here, sin θ = 600 x 10^-9 m / 0.5 x 10^-3 m = 0.0012, θ ≈ 0.0698 rad ≈ 4°.

The angle for the first minimum in single-slit diffraction is given by sin(θ) = λ/a, where a is the slit width.

The first minimum in a single-slit diffraction pattern occurs at sin(θ) = λ/a, where a is the width of the slit.

Angular width = 2λ/a. Here, a = 0.5 mm = 500 μm, so angular width = 2 * 500 nm / 500 μm = 0.002 rad = 0.2 rad.

The first minimum in a single-slit diffraction pattern occurs at θ = λ/a, where a is the width of the slit.

The colors in soap bubbles are due to thin film interference caused by the reflection and refraction of light at the film's surfaces.

When light reflects off a medium with a higher refractive index, a phase change of π occurs, leading to destructive interference.

Wavelength in the film λ' = λ/n. If λ = 900 nm, then λ' = 900 nm / 1.5 = 600 nm.

For constructive interference in a thin film, the condition is 2t = mλ, where m is an integer.

For destructive interference in a thin film, the condition is 2t = (m + 1/2)λ, where m is an integer.

For destructive interference in a thin film, the condition is 2t = (m + 1/2)λ, where m is an integer.

Constructive interference for blue light indicates that blue will be the color seen due to the film thickness.

The color seen depends on the thickness of the film and the wavelength of light. Typically, red is seen due to constructive interference for certain thicknesses.

At the center of the film with thickness λ/2, destructive interference occurs for all wavelengths, leading to no color.