Q. A charged particle moves in a magnetic field B with a velocity v. What is the expression for the magnetic force acting on the particle?
A.qvB
B.qvBsinθ
C.qvBcosθ
D.qB
Solution
The magnetic force acting on a charged particle moving in a magnetic field is given by F = qvBsinθ, where θ is the angle between the velocity and the magnetic field.
Q. A charged particle moves in a magnetic field. What is the condition for the particle to experience maximum force?
A.Velocity is zero
B.Velocity is parallel to the field
C.Velocity is perpendicular to the field
D.Charge is zero
Solution
The magnetic force on a charged particle is given by F = qvB sin(θ). The force is maximum when the angle θ is 90 degrees, meaning the velocity is perpendicular to the magnetic field.
Correct Answer: C — Velocity is perpendicular to the field
Q. A charged particle moves in a magnetic field. What is the effect of the magnetic field on the particle's motion?
A.It accelerates the particle
B.It changes the particle's speed
C.It changes the particle's direction
D.It has no effect
Solution
A magnetic field exerts a force on a charged particle that is perpendicular to both the velocity of the particle and the magnetic field, changing its direction but not its speed.
Correct Answer: C — It changes the particle's direction
Q. A circular loop of radius R carries a current I. What is the magnetic field at the center of the loop?
A.μ₀I/(2R)
B.μ₀I/R
C.μ₀I/(4R)
D.μ₀I/(8R)
Solution
The magnetic field at the center of a circular loop carrying current I is given by the formula B = (μ₀I)/(2R), where μ₀ is the permeability of free space.
Q. A circular loop of wire is placed in a uniform magnetic field. What happens to the induced EMF if the magnetic field strength is doubled?
A.Induced EMF is halved
B.Induced EMF remains the same
C.Induced EMF is doubled
D.Induced EMF is quadrupled
Solution
According to Faraday's law of electromagnetic induction, the induced EMF is directly proportional to the rate of change of magnetic flux. If the magnetic field strength is doubled, the induced EMF will also double.
Q. A particle with charge q moves with velocity v in a magnetic field B. What is the expression for the magnetic force acting on the particle?
A.F = qvB
B.F = qvB sin(θ)
C.F = qB
D.F = qvB cos(θ)
Solution
The magnetic force acting on a charged particle moving in a magnetic field is given by F = qvB sin(θ), where θ is the angle between the velocity vector and the magnetic field vector.
Q. A solenoid produces a uniform magnetic field inside it. What factors affect the strength of this magnetic field?
A.Length of the solenoid
B.Number of turns per unit length
C.Current through the solenoid
D.All of the above
Solution
The strength of the magnetic field inside a solenoid is affected by the number of turns per unit length and the current flowing through it, as well as the length of the solenoid.
Q. If the magnetic field strength is doubled, what happens to the force on a charged particle moving perpendicular to the field?
A.It doubles
B.It halves
C.It remains the same
D.It quadruples
Solution
The force on a charged particle is directly proportional to the magnetic field strength, so if the magnetic field strength is doubled, the force also doubles.
Q. In a solenoid, what factor does NOT affect the strength of the magnetic field inside it?
A.Number of turns per unit length
B.Current through the solenoid
C.Length of the solenoid
D.Permeability of the core material
Solution
The length of the solenoid does not affect the strength of the magnetic field inside it; it is determined by the number of turns per unit length, the current, and the permeability of the core material.