According to Kirchhoff's Current Law, total current entering = total current leaving. 2A + 3A + 1A = 6A.

According to Kirchhoff's Current Law, the total current entering a junction equals the total current leaving it. Total entering = 2A + 3A + 4A = 9A.

According to Kirchhoff's Current Law, the sum of currents entering a junction equals the sum of currents leaving. Therefore, I_out = 2A + 3A + 4A = 9A.

According to Kirchhoff's Current Law, the total current entering a junction equals the total current leaving it. Therefore, total current leaving = 2A + 3A + 5A = 10A.

Kirchhoff's Voltage Law states that the sum of the electrical potential differences (voltage) around any closed circuit is zero.

Kirchhoff's Voltage Law states that the sum of the electromotive forces and potential differences in any closed loop is zero.

Power P = V^2 / R. Here, P = 9^2 / 3 = 81 / 3 = 27 W.

Total resistance R = R1 + R2 = 3Ω + 9Ω = 12Ω. Using Ohm's law, I = V/R = 12V/12Ω = 1A.

The equivalent resistance for resistors in parallel is 1/R_total = 1/R1 + 1/R2 + 1/R3 = 1/3 + 1/3 + 1/3 = 1Ω. The total current is I = V/R_total = 9V / 1Ω = 9A.

Using Ohm's law, I = V/R = 10V / 5Ω = 2A.

Total resistance R = R1 + R2 = 3Ω + 6Ω = 9Ω. Using Ohm's law, I = V/R = 12V / 9Ω = 1.33A.

The total resistance is 4 + 8 = 12 ohms. The current is I = V/R = 12V / 12 ohms = 1 A. The voltage across the 8 ohm resistor is V = I * R = 1 A * 8 ohms = 8 V.

Using the voltage divider rule, V2 = (R2 / (R1 + R2)) * Vtotal = (10 / (5 + 10)) * 15 = 10V.

Voltage across R2 = (R2 / (R1 + R2)) * V = (10Ω / (5Ω + 10Ω)) * 15V = 10V.

Total resistance R = 5Ω + 10Ω = 15Ω. Current I = V/R = 15V/15Ω = 1A. Power P = I^2 * R = 1^2 * 10 = 10W.

Using the voltage divider rule, V2 = (R2 / (R1 + R2)) * Vtotal = (12 / (6 + 12)) * 24 = 16V.

Using the voltage divider rule, V6Ω = (R6Ω / (R3Ω + R6Ω)) * Vtotal = (6 / (3 + 6)) * 9 = 6V.

Using Ohm's Law, V = I * R. Here, V = 2 A * 5 ohms = 10 V.

Power (P) = I^2 * R = (2^2) * 5 = 4 * 5 = 20W.

Using Ohm's Law, V = I * R = 2A * 5Ω = 10V.

Power (P) = I^2 * R = 3^2 * 10 = 9 * 10 = 90W.

Power (P) = I^2 * R = (3A)^2 * 5Ω = 9 * 5 = 45W.

Power (P) = I^2 * R = (3A)^2 * 5Ω = 9A^2 * 5Ω = 45W.

Power (P) = I^2 * R = 5^2 * 10 = 25 * 10 = 250W.

Using Ohm's Law (V = IR), the voltage is V = 5A * 10Ω = 50V.

Using Ohm's law, V = I * R, we have V = 3 A * 6 ohms = 18 V.

Using Ohm's law, V = I * R, we have V = 5 A * 10 ohms = 50 V.

Using Ohm's Law, V = I * R = 5A * 10Ω = 50V.

Using Ohm's Law, V = I * R = 1.5A * 10Ω = 15V.

Using Ohm's Law, V = I * R = 2A * 10Ω = 20V.