Ohms Law
Q. A 10-ohm resistor has a voltage of 20 volts across it. What is the current flowing through the resistor?
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A.
1 A
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B.
2 A
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C.
3 A
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D.
4 A
Solution
Using Ohm's Law, I = V / R = 20 V / 10 Ω = 2 A.
Correct Answer: B — 2 A
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Q. A 10-ohm resistor has a voltage of 50 volts across it. What is the current flowing through the resistor?
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A.
5 A
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B.
10 A
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C.
15 A
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D.
20 A
Solution
Using Ohm's Law, I = V / R = 50 V / 10 Ω = 5 A.
Correct Answer: B — 10 A
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Q. A 10-ohm resistor is connected to a 20-volt battery. What is the power dissipated by the resistor?
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A.
40 W
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B.
20 W
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C.
10 W
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D.
2 W
Solution
Power (P) can be calculated using P = V^2 / R = 20^2 / 10 = 400 / 10 = 40 W.
Correct Answer: A — 40 W
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Q. A circuit has a voltage of 12 volts and a resistance of 4 ohms. What is the current flowing through the circuit?
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A.
3 A
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B.
4 A
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C.
2 A
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D.
1 A
Solution
Using Ohm's Law, I = V / R = 12 V / 4 Ω = 3 A.
Correct Answer: A — 3 A
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Q. A circuit has a voltage of 12V and a resistance of 4Ω. What is the current flowing through the circuit?
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A.
3A
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B.
4A
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C.
12A
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D.
48A
Solution
Using Ohm's Law, I = V/R = 12V / 4Ω = 3A.
Correct Answer: A — 3A
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Q. A circuit has a voltage of 24 volts and a current of 6 amperes. What is the resistance?
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A.
4 Ω
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B.
6 Ω
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C.
8 Ω
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D.
12 Ω
Solution
Using Ohm's Law, R = V / I = 24 V / 6 A = 4 Ω.
Correct Answer: A — 4 Ω
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Q. A resistor of 10 ohms is connected to a 20V battery. What is the current flowing through the resistor?
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A.
0.5 A
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B.
1 A
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C.
2 A
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D.
5 A
Solution
Using Ohm's Law, I = V/R = 20V / 10Ω = 2 A.
Correct Answer: C — 2 A
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Q. If a 10Ω resistor is connected to a 20V battery, what is the power dissipated by the resistor?
-
A.
20W
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B.
40W
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C.
100W
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D.
200W
Solution
Power (P) can be calculated using P = V^2/R. Here, P = 20V^2 / 10Ω = 400 / 10 = 40W.
Correct Answer: B — 40W
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Q. If a 12V battery is connected across a 4 ohm resistor, what is the power dissipated in the resistor?
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A.
12 W
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B.
24 W
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C.
36 W
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D.
48 W
Solution
Power (P) can be calculated using P = V^2 / R = 12V^2 / 4Ω = 144 / 4 = 36 W.
Correct Answer: B — 24 W
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Q. If a 12V battery is connected to a 4 ohm resistor, what is the power dissipated by the resistor?
-
A.
12 W
-
B.
24 W
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C.
36 W
-
D.
48 W
Solution
Power (P) can be calculated using P = V^2 / R = 12V^2 / 4Ω = 36 W.
Correct Answer: B — 24 W
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Q. If a 60W light bulb operates at 120V, what is the resistance of the bulb?
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A.
240 ohms
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B.
120 ohms
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C.
60 ohms
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D.
30 ohms
Solution
Power (P) = V^2 / R, so R = V^2 / P = (120V)^2 / 60W = 240 ohms.
Correct Answer: B — 120 ohms
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Q. If a circuit has a current of 0.5 A and a resistance of 20 ohms, what is the voltage?
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A.
10 V
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B.
5 V
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C.
15 V
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D.
20 V
Solution
Using Ohm's Law, V = I * R = 0.5 A * 20 Ω = 10 V.
Correct Answer: A — 10 V
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Q. If a circuit has a current of 3 A and a resistance of 4 ohms, what is the voltage across the circuit?
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A.
7 V
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B.
12 V
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C.
15 V
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D.
20 V
Solution
Using Ohm's Law, V = IR = 3 A * 4 Ω = 12 V.
Correct Answer: B — 12 V
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Q. If a circuit has a current of 5 A and a resistance of 10 Ω, what is the power consumed in the circuit?
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A.
50 W
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B.
25 W
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C.
10 W
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D.
5 W
Solution
Power (P) can be calculated using P = I^2 * R = (5 A)^2 * 10 Ω = 25 A^2 * 10 Ω = 250 W.
Correct Answer: A — 50 W
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Q. If a circuit has a current of 5 A and a resistance of 10 Ω, what is the voltage?
-
A.
50 V
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B.
5 V
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C.
10 V
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D.
15 V
Solution
Using Ohm's Law, V = I * R = 5 A * 10 Ω = 50 V.
Correct Answer: A — 50 V
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Q. If a circuit has a voltage of 24 volts and a current of 6 amperes, what is the resistance?
-
A.
4 Ω
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B.
6 Ω
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C.
8 Ω
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D.
12 Ω
Solution
Using Ohm's Law, R = V / I = 24 V / 6 A = 4 Ω.
Correct Answer: C — 8 Ω
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Q. If a resistor has a resistance of 5 ohms and a current of 2 amperes flows through it, what is the voltage across the resistor?
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A.
10 V
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B.
5 V
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C.
2.5 V
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D.
1 V
Solution
Using Ohm's Law, V = I * R = 2 A * 5 Ω = 10 V.
Correct Answer: A — 10 V
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Q. If a resistor is connected to a 9V battery and the current flowing through it is 3A, what is the resistance of the resistor?
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A.
1 Ω
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B.
3 Ω
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C.
9 Ω
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D.
27 Ω
Solution
Using Ohm's Law, R = V / I = 9 V / 3 A = 3 Ω.
Correct Answer: C — 9 Ω
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Q. If the current in a circuit is 5 A and the resistance is 2 ohms, what is the power consumed in the circuit?
-
A.
10 W
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B.
25 W
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C.
5 W
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D.
2.5 W
Solution
Power (P) can be calculated using P = I^2R = (5 A)^2 * 2 Ω = 25 W.
Correct Answer: B — 25 W
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Q. If the current in a circuit is doubled while the resistance remains constant, what happens to the voltage?
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A.
It doubles
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B.
It halves
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C.
It remains the same
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D.
It quadruples
Solution
According to Ohm's Law, if the current (I) is doubled and resistance (R) remains constant, the voltage (V) must also double.
Correct Answer: A — It doubles
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Q. If the resistance in a circuit is doubled while keeping the voltage constant, what happens to the current?
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A.
It doubles.
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B.
It halves.
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C.
It remains the same.
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D.
It quadruples.
Solution
According to Ohm's Law (I = V/R), if resistance (R) is doubled and voltage (V) remains constant, the current (I) will be halved.
Correct Answer: B — It halves.
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Q. If the resistance of a circuit is doubled while the voltage remains constant, what happens to the current?
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A.
It doubles
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B.
It halves
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C.
It remains the same
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D.
It quadruples
Solution
According to Ohm's Law, I = V/R. If R is doubled, the current I will be halved.
Correct Answer: B — It halves
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Q. If the voltage across a conductor is 15 volts and the current is 3 amperes, what is the resistance?
-
A.
5 Ω
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B.
10 Ω
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C.
15 Ω
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D.
20 Ω
Solution
Using Ohm's Law, R = V / I = 15 V / 3 A = 5 Ω.
Correct Answer: A — 5 Ω
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Q. If the voltage across a resistor is tripled, what happens to the current through it, assuming resistance remains constant?
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A.
It triples.
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B.
It doubles.
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C.
It remains the same.
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D.
It decreases.
Solution
According to Ohm's Law (I = V/R), if voltage (V) is tripled and resistance (R) remains constant, the current (I) will also triple.
Correct Answer: A — It triples.
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Q. In a circuit, if the voltage is increased from 5V to 15V while the resistance remains constant at 5 ohms, what is the change in current?
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A.
Increases by 1 A
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B.
Increases by 2 A
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C.
Increases by 3 A
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D.
Increases by 4 A
Solution
Initial current I1 = 5V / 5Ω = 1 A; Final current I2 = 15V / 5Ω = 3 A; Change in current = I2 - I1 = 3 A - 1 A = 2 A.
Correct Answer: C — Increases by 3 A
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Q. In a circuit, if the voltage is increased while keeping the resistance constant, what happens to the current?
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A.
It decreases
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B.
It increases
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C.
It remains constant
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D.
It becomes zero
Solution
According to Ohm's Law, if voltage increases and resistance remains constant, the current will increase.
Correct Answer: B — It increases
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Q. In a circuit, if the voltage is increased while the resistance remains constant, what happens to the current?
-
A.
It decreases
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B.
It increases
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C.
It remains the same
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D.
It becomes zero
Solution
According to Ohm's Law, if the voltage (V) increases and resistance (R) remains constant, the current (I) increases.
Correct Answer: B — It increases
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Q. In a parallel circuit, if one resistor fails, what happens to the total current?
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A.
It increases.
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B.
It decreases.
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C.
It remains the same.
-
D.
It becomes zero.
Solution
In a parallel circuit, if one resistor fails, the total current decreases because the total resistance increases.
Correct Answer: B — It decreases.
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Q. In a series circuit, if one resistor fails (opens), what happens to the current in the circuit?
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A.
It increases
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B.
It decreases
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C.
It becomes zero
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D.
It remains the same
Solution
In a series circuit, if one resistor fails, the circuit is broken and the current becomes zero.
Correct Answer: C — It becomes zero
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Q. In a series circuit, if one resistor fails open, what happens to the current in the circuit?
-
A.
It increases
-
B.
It decreases
-
C.
It becomes zero
-
D.
It remains the same
Solution
In a series circuit, if one resistor fails open, the current becomes zero because the circuit is broken.
Correct Answer: C — It becomes zero
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