The water surface inside the capillary tube is concave due to the adhesive forces between water and the tube material being stronger than the cohesive forces among water molecules.

Using the capillary rise formula, h = (2γcosθ)/(ρgr), where γ is surface tension, θ is contact angle, ρ is density, g is acceleration due to gravity, and r is radius.

The height of the liquid column in a capillary tube is determined by both surface tension and the density of the liquid, as described by the capillary rise formula.

The water will rise in the capillary tube due to capillary action, which is a result of surface tension.

Stress is defined as force per unit area. Doubling the diameter increases the area by a factor of four, thus reducing the stress.

Tensile stress is given by force/area. Halving the radius reduces the area by a factor of four, thus the stress quadruples for the same force.

For a drop to remain in equilibrium, the upward force due to surface tension must balance the downward gravitational force.

Using Poiseuille's law, the flow rate Q = (π * r^4 * ΔP) / (8 * η * L). Assuming L = 1 m, Q = (π * (0.05)^4 * 1000) / (8 * 0.1 * 1) = 0.01 m³/s.

The fractional change in volume is given by ΔV/V = ΔP/B. Here, ΔP = 50 MPa = 0.05 GPa, so ΔV/V = 0.05/200 = 0.00025.

The fractional change in volume ΔV/V is given by ΔV/V = ΔP/B, where ΔP = 10 MPa and B = 200 GPa, resulting in 0.00005.

The change in volume ΔV/V = P/B, so ΔV/V = 50 MPa / 200 GPa = 0.025%.

A material is considered elastic if it returns to its original shape after the removal of the applied stress.

Young's modulus (Y) = Stress / Strain = 100 MPa / 0.002 = 50 GPa.

The insect can walk on water due to surface tension, which creates a 'skin' on the surface of the water.

The insect can walk on water because of surface tension, which creates a 'skin' on the surface that can support the weight of the insect.

The insect can walk on water due to surface tension, which creates a 'skin' on the surface that can support the weight of the insect.

Surface area of a sphere = 4πr² = 4π(5)² = 100π cm².

Adding soap to water decreases the surface tension because soap molecules disrupt the cohesive forces between water molecules.

Using Hooke's law, k = F/x = 10 N / 0.05 m = 200 N/m.

The extension of the wire can be calculated using the formula: extension = (F * L) / (A * Y).

The elongation ΔL of a wire is given by ΔL = (F * L) / (A * Y), where Y is Young's modulus.

Surfactants lower the surface tension of water by disrupting the cohesive forces between water molecules.

The addition of soap decreases the surface tension of water by disrupting the cohesive forces between water molecules.

A viscosity of 0.5 Pa·s indicates that the fluid is relatively thick and flows less easily compared to fluids with lower viscosity.

A liquid droplet takes the shape of a sphere because this shape minimizes the surface area for a given volume, thus minimizing surface energy.

In a perfectly spherical droplet, the cohesive forces are balanced, resulting in a net force of zero.

A high surface tension indicates strong intermolecular forces, as these forces are responsible for the cohesive behavior of the liquid.

Plastic deformation means that the material does not return to its original shape after the load is removed.

When a material is stretched beyond its elastic limit, it undergoes permanent deformation and does not return to its original shape.

Young's modulus is a material property and does not change with the dimensions of the wire.