Newton's Laws for Competitive Exam Success

Newtons Laws

Q. A 1 kg ball is thrown upwards with a force of 10 N. What is the net force acting on the ball at the peak of its motion?

A. 0 N
B. 10 N
C. 5 N
D. 20 N

Solution

At the peak, the only force acting on the ball is its weight (10 N down), so the net force is 0 N.

Correct Answer: A — 0 N

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Q. A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is the force exerted by the spring when it is compressed by 0.1 m?

A. 2 N
B. 5 N
C. 10 N
D. 20 N

Solution

Using Hooke's Law, F = kx = 200 N/m * 0.1 m = 20 N.

Correct Answer: C — 10 N

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Q. A 1 kg object is pushed with a force of 10 N. If the frictional force is 4 N, what is the net force acting on the object?

A. 6 N
B. 10 N
C. 4 N
D. 0 N

Solution

Net force = applied force - frictional force = 10 N - 4 N = 6 N.

Correct Answer: A — 6 N

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Q. A 10 kg object is at rest on a surface. If a force of 30 N is applied, what is the object's acceleration assuming the friction is negligible?

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².

Correct Answer: C — 3 m/s²

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Q. A 10 kg object is dropped from a height. What is the force acting on it just before it hits the ground?

A. 10 N
B. 20 N
C. 30 N
D. 40 N

Solution

The force acting on the object is its weight, F = mg = 10 kg * 10 m/s² = 100 N.

Correct Answer: B — 20 N

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Q. A 10 kg object is hanging at rest from a rope. What is the tension in the rope?

A. 0 N
B. 10 N
C. 100 N
D. 50 N

Solution

The tension in the rope must balance the weight of the object. T = mg = 10 kg * 10 m/s² = 100 N.

Correct Answer: C — 100 N

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Q. A 10 kg object is hanging from a rope. What is the tension in the rope when the object is at rest?

A. 0 N
B. 10 N
C. 100 N
D. 50 N

Solution

At rest, the tension in the rope equals the weight of the object: T = mg = 10 kg * 10 m/s² = 100 N.

Correct Answer: C — 100 N

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Q. A 10 kg object is pushed with a force of 30 N. If the frictional force is 10 N, what is the net force?

A. 10 N
B. 20 N
C. 30 N
D. 40 N

Solution

Net force = applied force - friction = 30 N - 10 N = 20 N.

Correct Answer: B — 20 N

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Q. A 12 kg object is at rest on a horizontal surface. What is the normal force acting on it?

A. 0 N
B. 12 N
C. 120 N
D. 100 N

Solution

The normal force equals the weight of the object: N = mg = 12 kg * 10 m/s² = 120 N.

Correct Answer: C — 120 N

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Q. A 12 kg object is in free fall. What is the force acting on it due to gravity?

A. 12 N
B. 24 N
C. 36 N
D. 48 N

Solution

The force due to gravity is F = mg = 12 kg * 9.8 m/s² = 117.6 N (approximately 120 N).

Correct Answer: B — 24 N

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Q. A 12 kg object is moving with a velocity of 5 m/s. What is its momentum?

A. 30 kg·m/s
B. 60 kg·m/s
C. 90 kg·m/s
D. 120 kg·m/s

Solution

Momentum p = mv = 12 kg * 5 m/s = 60 kg·m/s.

Correct Answer: B — 60 kg·m/s

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Q. A 12 kg object is pulled with a force of 24 N. If the object experiences a frictional force of 4 N, what is its acceleration?

A. 1.67 m/s²
B. 2 m/s²
C. 2.5 m/s²
D. 3 m/s²

Solution

Net force = 24 N - 4 N = 20 N. Acceleration a = F/m = 20 N / 12 kg = 1.67 m/s².

Correct Answer: B — 2 m/s²

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Q. A 15 kg box is pushed with a force of 30 N. If the frictional force opposing the motion is 10 N, what is the acceleration of the box?

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Net force = applied force - friction = 30 N - 10 N = 20 N. Acceleration a = F/m = 20 N / 15 kg = 1.33 m/s².

Correct Answer: B — 2 m/s²

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Q. A 15 kg box is pushed with a force of 45 N. What is the acceleration of the box? (Assume no friction)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, we have a = F/m = 45 N / 15 kg = 3 m/s².

Correct Answer: C — 3 m/s²

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Q. A 15 kg box is pushed with a force of 60 N on a rough surface with a frictional force of 15 N. What is the box's acceleration?

A. 3 m/s²
B. 4 m/s²
C. 5 m/s²
D. 6 m/s²

Solution

Net force = 60 N - 15 N = 45 N. Acceleration a = F/m = 45 N / 15 kg = 3 m/s².

Correct Answer: B — 4 m/s²

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Q. A 15 kg object is at rest on a table. What is the force exerted by the table on the object?

A. 0 N
B. 15 N
C. 150 N
D. 10 N

Solution

The normal force equals the weight of the object: 15 kg * 10 m/s² = 150 N.

Correct Answer: C — 150 N

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Q. A 15 kg object is in equilibrium. What is the net force acting on it?

A. 0 N
B. 15 N
C. 30 N
D. 45 N

Solution

In equilibrium, the net force acting on the object is 0 N.

Correct Answer: A — 0 N

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Q. A 15 kg object is pushed with a force of 45 N. What is the acceleration of the object?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, acceleration a = F/m = 45 N / 15 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. A 2 kg block is sliding on a frictionless surface. If a force of 6 N is applied, what is its acceleration?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 6 m/s²

Solution

Using F = ma, acceleration a = F/m = 6 N / 2 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. A 2 kg object is in free fall. What is the net force acting on it?

A. 0 N
B. 2 N
C. 20 N
D. 19.6 N

Solution

The net force is equal to the weight of the object: F = mg = 2 kg * 9.8 m/s² = 19.6 N.

Correct Answer: C — 20 N

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Q. A 2 kg object is pulled with a force of 8 N. What is the acceleration of the object?

A. 2 m/s²
B. 4 m/s²
C. 6 m/s²
D. 8 m/s²

Solution

Using F = ma, we find a = F/m = 8 N / 2 kg = 4 m/s².

Correct Answer: B — 4 m/s²

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Q. A 2 kg object is sliding on a frictionless surface with a velocity of 4 m/s. What is the momentum of the object?

A. 8 kg·m/s
B. 2 kg·m/s
C. 4 kg·m/s
D. 16 kg·m/s

Solution

Momentum p = mv = 2 kg * 4 m/s = 8 kg·m/s.

Correct Answer: A — 8 kg·m/s

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Q. A 2 kg object is sliding on a frictionless surface with a velocity of 5 m/s. What is the momentum of the object?

A. 10 kg·m/s
B. 5 kg·m/s
C. 2 kg·m/s
D. 1 kg·m/s

Solution

Momentum p = mv = 2 kg * 5 m/s = 10 kg·m/s.

Correct Answer: A — 10 kg·m/s

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Q. A 20 kg object is dropped from a height. What is the force acting on it just before it hits the ground?

A. 0 N
B. 20 N
C. 200 N
D. 10 N

Solution

The force acting on the object is its weight: F = mg = 20 kg * 10 m/s² = 200 N.

Correct Answer: C — 200 N

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Q. A 25 kg object is pulled with a force of 100 N. What is the acceleration of the object?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Using F = ma, we have a = F/m = 100 N / 25 kg = 4 m/s².

Correct Answer: D — 5 m/s²

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Q. A 25 kg object is pushed with a force of 100 N. If the frictional force is 25 N, what is the acceleration of the object?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 100 N - 25 N = 75 N. Acceleration a = F/m = 75 N / 25 kg = 3 m/s².

Correct Answer: B — 3 m/s²

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Q. A 25 kg object is subjected to a force of 50 N. What is its acceleration?

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, we find a = F/m = 50 N / 25 kg = 2 m/s².

Correct Answer: B — 2 m/s²

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Q. A 3 kg block is on a table and a horizontal force of 15 N is applied. If the frictional force is 5 N, what is the acceleration of the block?

A. 2 m/s²
B. 3 m/s²
C. 5 m/s²
D. 10 m/s²

Solution

Net force = applied force - friction = 15 N - 5 N = 10 N. Acceleration a = F/m = 10 N / 3 kg = 3.33 m/s².

Correct Answer: A — 2 m/s²

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Q. A 3 kg block is pulled with a force of 12 N. If the frictional force is 3 N, what is the acceleration of the block?

A. 3 m/s²
B. 4 m/s²
C. 2 m/s²
D. 1 m/s²

Solution

Net force = applied force - friction = 12 N - 3 N = 9 N. Acceleration a = F/m = 9 N / 3 kg = 3 m/s².

Correct Answer: B — 4 m/s²

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Q. A 3 kg block is sliding down a frictionless incline of 30 degrees. What is the acceleration of the block?

A. 3.9 m/s²
B. 4.9 m/s²
C. 9.8 m/s²
D. 1.5 m/s²

Solution

The acceleration down the incline is given by a = g * sin(θ) = 9.8 m/s² * sin(30°) = 4.9 m/s².

Correct Answer: A — 3.9 m/s²

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Newtons Laws

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