Q. A 1 kg ball is thrown upwards with a force of 10 N. What is the net force acting on the ball at the peak of its motion?
A.
0 N
B.
10 N
C.
5 N
D.
20 N
Show solution
Solution
At the peak, the only force acting on the ball is its weight (10 N down), so the net force is 0 N.
Correct Answer:
A
— 0 N
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Q. A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is the force exerted by the spring when it is compressed by 0.1 m?
A.
2 N
B.
5 N
C.
10 N
D.
20 N
Show solution
Solution
Using Hooke's Law, F = kx = 200 N/m * 0.1 m = 20 N.
Correct Answer:
C
— 10 N
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Q. A 1 kg object is pushed with a force of 10 N. If the frictional force is 4 N, what is the net force acting on the object?
A.
6 N
B.
10 N
C.
4 N
D.
0 N
Show solution
Solution
Net force = applied force - frictional force = 10 N - 4 N = 6 N.
Correct Answer:
A
— 6 N
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Q. A 10 kg object is at rest on a surface. If a force of 30 N is applied, what is the object's acceleration assuming the friction is negligible?
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².
Correct Answer:
C
— 3 m/s²
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Q. A 10 kg object is dropped from a height. What is the force acting on it just before it hits the ground?
A.
10 N
B.
20 N
C.
30 N
D.
40 N
Show solution
Solution
The force acting on the object is its weight, F = mg = 10 kg * 10 m/s² = 100 N.
Correct Answer:
B
— 20 N
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Q. A 10 kg object is hanging at rest from a rope. What is the tension in the rope?
A.
0 N
B.
10 N
C.
100 N
D.
50 N
Show solution
Solution
The tension in the rope must balance the weight of the object. T = mg = 10 kg * 10 m/s² = 100 N.
Correct Answer:
C
— 100 N
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Q. A 10 kg object is hanging from a rope. What is the tension in the rope when the object is at rest?
A.
0 N
B.
10 N
C.
100 N
D.
50 N
Show solution
Solution
At rest, the tension in the rope equals the weight of the object: T = mg = 10 kg * 10 m/s² = 100 N.
Correct Answer:
C
— 100 N
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Q. A 10 kg object is pushed with a force of 30 N. If the frictional force is 10 N, what is the net force?
A.
10 N
B.
20 N
C.
30 N
D.
40 N
Show solution
Solution
Net force = applied force - friction = 30 N - 10 N = 20 N.
Correct Answer:
B
— 20 N
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Q. A 12 kg object is at rest on a horizontal surface. What is the normal force acting on it?
A.
0 N
B.
12 N
C.
120 N
D.
100 N
Show solution
Solution
The normal force equals the weight of the object: N = mg = 12 kg * 10 m/s² = 120 N.
Correct Answer:
C
— 120 N
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Q. A 12 kg object is in free fall. What is the force acting on it due to gravity?
A.
12 N
B.
24 N
C.
36 N
D.
48 N
Show solution
Solution
The force due to gravity is F = mg = 12 kg * 9.8 m/s² = 117.6 N (approximately 120 N).
Correct Answer:
B
— 24 N
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Q. A 12 kg object is moving with a velocity of 5 m/s. What is its momentum?
A.
30 kg·m/s
B.
60 kg·m/s
C.
90 kg·m/s
D.
120 kg·m/s
Show solution
Solution
Momentum p = mv = 12 kg * 5 m/s = 60 kg·m/s.
Correct Answer:
B
— 60 kg·m/s
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Q. A 12 kg object is pulled with a force of 24 N. If the object experiences a frictional force of 4 N, what is its acceleration?
A.
1.67 m/s²
B.
2 m/s²
C.
2.5 m/s²
D.
3 m/s²
Show solution
Solution
Net force = 24 N - 4 N = 20 N. Acceleration a = F/m = 20 N / 12 kg = 1.67 m/s².
Correct Answer:
B
— 2 m/s²
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Q. A 15 kg box is pushed with a force of 30 N. If the frictional force opposing the motion is 10 N, what is the acceleration of the box?
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
Show solution
Solution
Net force = applied force - friction = 30 N - 10 N = 20 N. Acceleration a = F/m = 20 N / 15 kg = 1.33 m/s².
Correct Answer:
B
— 2 m/s²
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Q. A 15 kg box is pushed with a force of 45 N. What is the acceleration of the box? (Assume no friction)
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
Show solution
Solution
Using F = ma, we have a = F/m = 45 N / 15 kg = 3 m/s².
Correct Answer:
C
— 3 m/s²
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Q. A 15 kg box is pushed with a force of 60 N on a rough surface with a frictional force of 15 N. What is the box's acceleration?
A.
3 m/s²
B.
4 m/s²
C.
5 m/s²
D.
6 m/s²
Show solution
Solution
Net force = 60 N - 15 N = 45 N. Acceleration a = F/m = 45 N / 15 kg = 3 m/s².
Correct Answer:
B
— 4 m/s²
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Q. A 15 kg object is at rest on a table. What is the force exerted by the table on the object?
A.
0 N
B.
15 N
C.
150 N
D.
10 N
Show solution
Solution
The normal force equals the weight of the object: 15 kg * 10 m/s² = 150 N.
Correct Answer:
C
— 150 N
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Q. A 15 kg object is in equilibrium. What is the net force acting on it?
A.
0 N
B.
15 N
C.
30 N
D.
45 N
Show solution
Solution
In equilibrium, the net force acting on the object is 0 N.
Correct Answer:
A
— 0 N
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Q. A 15 kg object is pushed with a force of 45 N. What is the acceleration of the object?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 45 N / 15 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. A 2 kg block is sliding on a frictionless surface. If a force of 6 N is applied, what is its acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
6 m/s²
Show solution
Solution
Using F = ma, acceleration a = F/m = 6 N / 2 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. A 2 kg object is in free fall. What is the net force acting on it?
A.
0 N
B.
2 N
C.
20 N
D.
19.6 N
Show solution
Solution
The net force is equal to the weight of the object: F = mg = 2 kg * 9.8 m/s² = 19.6 N.
Correct Answer:
C
— 20 N
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Q. A 2 kg object is pulled with a force of 8 N. What is the acceleration of the object?
A.
2 m/s²
B.
4 m/s²
C.
6 m/s²
D.
8 m/s²
Show solution
Solution
Using F = ma, we find a = F/m = 8 N / 2 kg = 4 m/s².
Correct Answer:
B
— 4 m/s²
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Q. A 2 kg object is sliding on a frictionless surface with a velocity of 4 m/s. What is the momentum of the object?
A.
8 kg·m/s
B.
2 kg·m/s
C.
4 kg·m/s
D.
16 kg·m/s
Show solution
Solution
Momentum p = mv = 2 kg * 4 m/s = 8 kg·m/s.
Correct Answer:
A
— 8 kg·m/s
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Q. A 2 kg object is sliding on a frictionless surface with a velocity of 5 m/s. What is the momentum of the object?
A.
10 kg·m/s
B.
5 kg·m/s
C.
2 kg·m/s
D.
1 kg·m/s
Show solution
Solution
Momentum p = mv = 2 kg * 5 m/s = 10 kg·m/s.
Correct Answer:
A
— 10 kg·m/s
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Q. A 20 kg object is dropped from a height. What is the force acting on it just before it hits the ground?
A.
0 N
B.
20 N
C.
200 N
D.
10 N
Show solution
Solution
The force acting on the object is its weight: F = mg = 20 kg * 10 m/s² = 200 N.
Correct Answer:
C
— 200 N
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Q. A 25 kg object is pulled with a force of 100 N. What is the acceleration of the object?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Using F = ma, we have a = F/m = 100 N / 25 kg = 4 m/s².
Correct Answer:
D
— 5 m/s²
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Q. A 25 kg object is pushed with a force of 100 N. If the frictional force is 25 N, what is the acceleration of the object?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
Net force = 100 N - 25 N = 75 N. Acceleration a = F/m = 75 N / 25 kg = 3 m/s².
Correct Answer:
B
— 3 m/s²
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Q. A 25 kg object is subjected to a force of 50 N. What is its acceleration?
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
Show solution
Solution
Using F = ma, we find a = F/m = 50 N / 25 kg = 2 m/s².
Correct Answer:
B
— 2 m/s²
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Q. A 3 kg block is on a table and a horizontal force of 15 N is applied. If the frictional force is 5 N, what is the acceleration of the block?
A.
2 m/s²
B.
3 m/s²
C.
5 m/s²
D.
10 m/s²
Show solution
Solution
Net force = applied force - friction = 15 N - 5 N = 10 N. Acceleration a = F/m = 10 N / 3 kg = 3.33 m/s².
Correct Answer:
A
— 2 m/s²
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Q. A 3 kg block is pulled with a force of 12 N. If the frictional force is 3 N, what is the acceleration of the block?
A.
3 m/s²
B.
4 m/s²
C.
2 m/s²
D.
1 m/s²
Show solution
Solution
Net force = applied force - friction = 12 N - 3 N = 9 N. Acceleration a = F/m = 9 N / 3 kg = 3 m/s².
Correct Answer:
B
— 4 m/s²
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Q. A 3 kg block is sliding down a frictionless incline of 30 degrees. What is the acceleration of the block?
A.
3.9 m/s²
B.
4.9 m/s²
C.
9.8 m/s²
D.
1.5 m/s²
Show solution
Solution
The acceleration down the incline is given by a = g * sin(θ) = 9.8 m/s² * sin(30°) = 4.9 m/s².
Correct Answer:
A
— 3.9 m/s²
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Showing 1 to 30 of 96 (4 Pages)
Newtons Laws MCQ & Objective Questions
Understanding Newton's Laws is crucial for students preparing for school and competitive exams in India. These laws form the foundation of classical mechanics and are frequently tested in various formats, including MCQs and objective questions. Practicing these questions not only enhances your conceptual clarity but also boosts your confidence, helping you score better in exams.
What You Will Practise Here
Newton's First Law of Motion: Concepts and applications
Newton's Second Law of Motion: Understanding force, mass, and acceleration
Newton's Third Law of Motion: Action and reaction pairs
Real-life applications of Newton's Laws in daily scenarios
Key formulas related to Newton's Laws
Common misconceptions and clarifications
Diagrams illustrating the laws and their applications
Exam Relevance
Newton's Laws are integral to the physics syllabus across various educational boards in India, including CBSE and State Boards. They are often featured in competitive exams like NEET and JEE. Students can expect questions that test their understanding of concepts, application of formulas, and problem-solving skills. Common question patterns include numerical problems, conceptual questions, and application-based scenarios.
Common Mistakes Students Make
Confusing the definitions of the three laws of motion
Misapplying the second law in numerical problems
Overlooking the significance of units in calculations
Failing to identify action-reaction pairs in real-world situations
FAQs
Question: What are Newton's Laws of Motion?Answer: Newton's Laws of Motion are three fundamental principles that describe the relationship between the motion of an object and the forces acting on it.
Question: How can I prepare effectively for questions on Newton's Laws?Answer: Regular practice of MCQs and objective questions related to Newton's Laws, along with understanding the underlying concepts, will enhance your preparation.
Don't miss the chance to solidify your understanding of Newton's Laws! Start solving practice MCQs today and test your knowledge to excel in your exams.
