Motion in One Dimension

Q. A ball is dropped from a height of 80 m. How long will it take to reach the ground? (Assume g = 10 m/s²)

A. 4 s
B. 5 s
C. 6 s
D. 8 s

Solution

Using the formula: h = 0.5 * g * t^2. 80 = 0.5 * 10 * t^2. Solving gives t^2 = 16, so t = 4 s.

Correct Answer: B — 5 s

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Q. A ball is thrown downward with an initial speed of 10 m/s from a height of 20 m. How long will it take to hit the ground? (Assume g = 10 m/s²)

A. 2 s
B. 3 s
C. 4 s
D. 5 s

Solution

Using the equation of motion: h = ut + 0.5gt². 20 = 10t + 0.5 * 10 * t². Rearranging gives 5t² + 10t - 20 = 0. Solving this quadratic gives t = 2 s.

Correct Answer: C — 4 s

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Q. A ball is thrown downward with an initial speed of 10 m/s from a height of 20 m. How long will it take to hit the ground? (g = 10 m/s²)

A. 2 s
B. 3 s
C. 4 s
D. 5 s

Solution

Using the equation of motion: h = ut + 0.5gt². 20 = 10t + 0.5 * 10 * t². Rearranging gives 5t² + 10t - 20 = 0. Solving this quadratic gives t = 2 s.

Correct Answer: B — 3 s

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Q. A ball is thrown downward with an initial speed of 5 m/s from a height of 20 m. How long will it take to hit the ground? (g = 10 m/s²)

A. 2 s
B. 3 s
C. 4 s
D. 5 s

Solution

Using the equation of motion: h = ut + 0.5gt². 20 = 5t + 0.5 * 10 * t². Rearranging gives 5t + 5t² - 20 = 0. Solving the quadratic gives t = 2 s.

Correct Answer: B — 3 s

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Q. A ball is thrown downwards with an initial velocity of 5 m/s from a height of 20 m. How long will it take to hit the ground? (g = 10 m/s²)

A. 2 s
B. 3 s
C. 4 s
D. 5 s

Solution

Using the equation of motion: h = ut + 0.5gt². 20 = 5t + 0.5 * 10 * t². This simplifies to 5t + 5t² - 20 = 0. Solving gives t = 2 s.

Correct Answer: B — 3 s

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Q. A ball is thrown horizontally from the top of a cliff 45 m high. How far from the base of the cliff will it land if it is thrown with a speed of 10 m/s?

A. 20 m
B. 30 m
C. 40 m
D. 50 m

Solution

Time to fall = sqrt(2h/g) = sqrt(2*45/9.8) ≈ 3.03 s. Horizontal distance = speed * time = 10 * 3.03 ≈ 30.3 m, approximately 30 m.

Correct Answer: B — 30 m

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Q. A ball is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will it land? (Assume g = 10 m/s² and initial horizontal speed = 20 m/s)

A. 40 m
B. 60 m
C. 80 m
D. 100 m

Solution

Time to fall = √(2h/g) = √(2*80/10) = 4 s. Horizontal distance = speed * time = 20 * 4 = 80 m.

Correct Answer: C — 80 m

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Q. A ball is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will it land? (Assume g = 10 m/s² and horizontal speed = 20 m/s)

A. 20 m
B. 40 m
C. 60 m
D. 80 m

Solution

Time to fall = √(2h/g) = √(2*80/10) = 4 s. Horizontal distance = speed * time = 20 m/s * 4 s = 80 m.

Correct Answer: C — 60 m

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Q. A ball is thrown horizontally from the top of a cliff with a speed of 15 m/s. If the cliff is 45 m high, how far from the base of the cliff will the ball land?

A. 30 m
B. 45 m
C. 60 m
D. 75 m

Solution

Time to fall = √(2h/g) = √(2*45/10) = 3 s. Horizontal distance = speed * time = 15 m/s * 3 s = 45 m.

Correct Answer: C — 60 m

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Q. A body moves in a straight line with a uniform acceleration of 2 m/s². If its initial velocity is 5 m/s, what will be its velocity after 10 seconds?

A. 25 m/s
B. 20 m/s
C. 15 m/s
D. 10 m/s

Solution

Final velocity = initial velocity + acceleration * time = 5 + 2 * 10 = 25 m/s.

Correct Answer: A — 25 m/s

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Q. A body moving with a uniform speed of 10 m/s covers a distance of 100 m. How much time does it take?

A. 5 s
B. 10 s
C. 15 s
D. 20 s

Solution

Time = distance / speed = 100 m / 10 m/s = 10 s.

Correct Answer: B — 10 s

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Q. A car accelerates uniformly from rest to a speed of 20 m/s in 10 seconds. What is the distance covered by the car during this time?

A. 100 m
B. 200 m
C. 300 m
D. 400 m

Solution

Using the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. Here, initial velocity = 0, final velocity = 20 m/s, time = 10 s. Acceleration = (final velocity - initial velocity) / time = 2 m/s². Distance = 0 + 0.5 * 2 * 10² = 100 m.

Correct Answer: B — 200 m

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Q. A car travels 100 m in 4 seconds. What is its average speed?

A. 20 m/s
B. 25 m/s
C. 30 m/s
D. 35 m/s

Solution

Average speed = total distance / total time = 100 m / 4 s = 25 m/s.

Correct Answer: B — 25 m/s

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Q. A cyclist accelerates from rest at a rate of 1 m/s². How far will he travel in 10 seconds?

A. 50 m
B. 100 m
C. 150 m
D. 200 m

Solution

Using the formula: distance = initial velocity * time + 0.5 * acceleration * time². Distance = 0 + 0.5 * 1 * 10² = 50 m.

Correct Answer: B — 100 m

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Q. A cyclist accelerates from rest at a rate of 1 m/s². How far will he travel in 8 seconds?

A. 32 m
B. 40 m
C. 48 m
D. 64 m

Solution

Using the formula: distance = initial velocity * time + 0.5 * acceleration * time². Distance = 0 + 0.5 * 1 * 8² = 32 m.

Correct Answer: C — 48 m

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Q. A cyclist accelerates from rest at a rate of 2 m/s². How far will he travel in 10 seconds?

A. 100 m
B. 50 m
C. 200 m
D. 150 m

Solution

Using the formula: distance = ut + 0.5at². Here, u = 0, a = 2 m/s², t = 10 s. Distance = 0 + 0.5 * 2 * 10² = 100 m.

Correct Answer: A — 100 m

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Q. A particle moves in a straight line with an acceleration of 4 m/s². If its initial velocity is 2 m/s, what will be its velocity after 5 seconds?

A. 22 m/s
B. 20 m/s
C. 18 m/s
D. 16 m/s

Solution

Using the formula: final velocity = initial velocity + acceleration * time. Final velocity = 2 + 4 * 5 = 22 m/s.

Correct Answer: A — 22 m/s

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Q. A stone is thrown downward with an initial velocity of 5 m/s from a height of 45 m. How long will it take to hit the ground? (Assume g = 10 m/s²)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using the equation of motion: h = ut + 0.5gt². 45 = 5t + 0.5 * 10 * t². Solving the quadratic gives t = 3 s.

Correct Answer: B — 4 s

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Q. A stone is thrown vertically upward with a speed of 20 m/s. How long will it take to reach the maximum height? (g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Using the formula: v = u - gt. At maximum height, v = 0. So, 0 = 20 - 10t. Solving gives t = 2 s.

Correct Answer: B — 2 s

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Q. A stone is thrown vertically upward with a speed of 20 m/s. How long will it take to reach the maximum height? (Assume g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Time to reach maximum height = initial velocity / g = 20 / 10 = 2 s.

Correct Answer: B — 2 s

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Q. A stone is thrown vertically upward with a speed of 20 m/s. How long will it take to reach the maximum height?

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Time to reach maximum height = initial velocity / g = 20 / 10 = 2 s.

Correct Answer: B — 2 s

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Q. A stone is thrown vertically upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (Assume g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Using the formula: time = (final velocity - initial velocity) / g. At maximum height, final velocity = 0. Time = (0 - 20) / -10 = 2 s.

Correct Answer: B — 2 s

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Q. A stone is thrown vertically upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Using the formula: v = u - gt. At maximum height, v = 0. So, 0 = 20 - 10t. Solving gives t = 2 s.

Correct Answer: B — 2 s

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Q. A train moving with a speed of 60 km/h applies brakes and comes to a stop in 5 seconds. What is the magnitude of its acceleration?

A. -3 m/s²
B. -2 m/s²
C. -1 m/s²
D. -4 m/s²

Solution

First, convert speed to m/s: 60 km/h = 60/3.6 = 16.67 m/s. Using the formula: acceleration = (final velocity - initial velocity) / time = (0 - 16.67) / 5 = -3.33 m/s², approximately -3 m/s².

Correct Answer: A — -3 m/s²

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Q. A train moving with a speed of 72 km/h applies brakes and comes to a stop in 10 seconds. What is the magnitude of its acceleration?

A. -2 m/s²
B. -3 m/s²
C. -4 m/s²
D. -5 m/s²

Solution

First convert speed to m/s: 72 km/h = 20 m/s. Using the formula: acceleration = (final velocity - initial velocity) / time = (0 - 20) / 10 = -2 m/s².

Correct Answer: C — -4 m/s²

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Q. A train travels 120 km at a uniform speed. If it takes 2 hours to complete the journey, what is the speed of the train?

A. 50 km/h
B. 60 km/h
C. 70 km/h
D. 80 km/h

Solution

Speed = distance / time = 120 km / 2 h = 60 km/h.

Correct Answer: B — 60 km/h

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Q. A train travels at a speed of 72 km/h. How long will it take to cover a distance of 180 km?

A. 2 hours
B. 2.5 hours
C. 3 hours
D. 3.5 hours

Solution

Time = distance / speed. Convert speed to m/s: 72 km/h = 20 m/s. Time = 180 km / 72 km/h = 2.5 hours.

Correct Answer: C — 3 hours

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Q. A vehicle moving with a speed of 60 km/h applies brakes and comes to a stop in 5 seconds. What is the deceleration?

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Convert speed to m/s: 60 km/h = 16.67 m/s. Deceleration = (final velocity - initial velocity) / time = (0 - 16.67) / 5 = -3.33 m/s², approximately 3 m/s².

Correct Answer: B — 3 m/s²

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Q. An object is dropped from a height of 80 m. How long will it take to reach the ground?

A. 4 s
B. 5 s
C. 6 s
D. 8 s

Solution

Using the formula: h = 0.5 * g * t², where h = 80 m and g = 9.8 m/s². Solving for t gives t = sqrt(2h/g) = sqrt(2*80/9.8) ≈ 4.04 s, approximately 4 s.

Correct Answer: B — 5 s

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Q. An object is dropped from a height of 80 m. How long will it take to reach the ground? (Assume g = 10 m/s²)

A. 4 s
B. 5 s
C. 6 s
D. 8 s

Solution

Using the formula: h = 0.5 * g * t². 80 = 0.5 * 10 * t². Solving gives t² = 16, so t = 4 s.

Correct Answer: B — 5 s

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Showing 1 to 30 of 37 (2 Pages)

Motion in One Dimension

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