Leading zeros do not count, but the trailing zero after the decimal does. Therefore, 0.05060 has 4 significant figures.

The significant figures are 5, 0, and the trailing zero counts, totaling 3.

Leading zeros do not count as significant figures. The significant figures in 0.00456 are 4, 5, and 6, which totals to 3 significant figures.

The significant figures are 7, 8, 9, and the trailing zero counts.

The trailing zero after the decimal point counts as a significant figure.

All non-zero digits are significant, so 1002 has 4 significant figures.

5000 has 1 significant figure unless specified otherwise (e.g., 5000. has 4 significant figures).

5000 has 1 significant figure unless specified with a decimal point (e.g., 5000. has 4).

To round 0.0001234 to two significant figures, we look at the first two non-zero digits (1 and 2) and round up, resulting in 0.00013.

To round 0.05060 to three significant figures, we keep the first three significant digits (5, 0, and 6), resulting in 0.0506.

Leading zeros are not significant. The significant figures are 5, 0, 0, which gives a total of 3 significant figures.

The number 0.0600 m has 3 significant figures. The leading zeros do not count, but the trailing zeros after the decimal point do.

The number 150.0 has 4 significant figures because the trailing zero after the decimal point counts as significant.

The uncertainty is 0.1 cm, as the last digit is in the tenths place.

Leading zeros are not significant. The significant figures are 4, 5, 6, which gives a total of 4 significant figures.

The measurement 0.00780 m has three significant figures (the zeros before the 7 are not significant, but the zero after the 8 is).

The leading zeros are not significant, but the trailing zero after 78 is significant. Therefore, it has 3 significant figures.

Leading zeros do not count as significant figures. The significant figures in 0.007890 are 7, 8, 9, and 0, which totals to 4 significant figures.

The number 1500 m has 2 significant figures unless specified otherwise (e.g., with a decimal point). Without a decimal, trailing zeros are not counted.

Without a decimal point, trailing zeros are not considered significant. Therefore, 1500 has 2 significant figures.

The answer should have 1 decimal place, as 0.3 has the least decimal places.

The answer should have 2 significant figures, as the least number of significant figures in the factors is 2.

The result should have 2 significant figures, as the least number of significant figures in the factors is 2.

The answer should have 2 decimal places, as 0.3 has the least precision.

The result should have 3 significant figures, as 0.0034 has the least precision.

The significant figures are 7, 8, 9, and 0, totaling 4 significant figures.

In 0.03040, the leading zeros do not count, but the trailing zero after the decimal does. Therefore, there are 4 significant figures.

All digits in 123.45 are significant, giving a total of 5 significant figures.

The significant figures are 1, 5, and the trailing zero after the decimal point.

The number 2500 kg has two significant figures unless specified otherwise (e.g., with a decimal point).