Q. If the radius of a circular path is doubled, how does the centripetal force change for a constant mass and velocity?
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A.
It doubles.
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B.
It halves.
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C.
It remains the same.
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D.
It quadruples.
Solution
Centripetal force is given by F = mv^2/r. If r is doubled, the force is halved, assuming mass and velocity remain constant.
Correct Answer:
B
— It halves.
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Q. What is the gravitational potential energy of a 1 kg mass at a height of 10 m?
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A.
10 J
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B.
20 J
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C.
30 J
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D.
40 J
Solution
Using the formula PE = m * g * h, where g = 10 m/s^2, PE = 1 kg * 10 m/s^2 * 10 m = 100 J.
Correct Answer:
A
— 10 J
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Q. What is the potential energy of a 10 kg object at a height of 5 meters?
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A.
50 J
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B.
100 J
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C.
150 J
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D.
200 J
Solution
Potential energy is calculated using PE = m * g * h. Assuming g = 10 m/s^2, PE = 10 kg * 10 m/s^2 * 5 m = 500 J.
Correct Answer:
B
— 100 J
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Q. What is the rotational equivalent of Newton's second law?
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A.
τ = I * α
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B.
F = m * a
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C.
W = F * d
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D.
p = m * v
Solution
The rotational equivalent of Newton's second law is τ = I * α, where τ is torque, I is moment of inertia, and α is angular acceleration.
Correct Answer:
A
— τ = I * α
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Q. What is the work done when a force of 10 N moves an object 3 meters in the direction of the force?
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A.
30 J
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B.
10 J
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C.
3 J
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D.
0 J
Solution
Work done is calculated as W = F * d * cos(θ). Here, θ = 0 degrees, so W = 10 N * 3 m * cos(0) = 30 J.
Correct Answer:
A
— 30 J
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Q. Which of the following statements is true according to Newton's first law?
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A.
An object at rest stays at rest unless acted upon by a net force.
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B.
Force equals mass times acceleration.
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C.
For every action, there is an equal and opposite reaction.
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D.
Energy cannot be created or destroyed.
Solution
Newton's first law states that an object at rest stays at rest and an object in motion stays in motion unless acted upon by a net force.
Correct Answer:
A
— An object at rest stays at rest unless acted upon by a net force.
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