Coulombs Law and Electric Field - Exam Prep Techniques

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Coulombs Law and Electric Field - Circuit Analysis Techniques

Q. If a resistor of 10Ω is connected across a 20V power supply, what is the power dissipated by the resistor?

A. 20 W
B. 40 W
C. 10 W
D. 5 W

Solution

Power P = V²/R = (20V)² / 10Ω = 400/10 = 40 W.

Correct Answer: B — 40 W

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Q. In a parallel circuit with a 12V battery and two resistors (4Ω and 12Ω), what is the total current supplied by the battery?

A. 1 A
B. 2 A
C. 3 A
D. 4 A

Solution

Total current I = V/R_total. R_total = 1/(1/4 + 1/12) = 3Ω. I = 12V / 3Ω = 4 A.

Correct Answer: C — 3 A

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Q. In a series circuit with a 12V battery and two resistors (4Ω and 6Ω), what is the total current flowing through the circuit?

A. 0.5 A
B. 1 A
C. 1.2 A
D. 2 A

Solution

Total resistance R = R1 + R2 = 4Ω + 6Ω = 10Ω. Current I = V/R = 12V / 10Ω = 1.2 A.

Correct Answer: B — 1 A

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Q. What is the electric potential at a point 3 m away from a charge of +2 µC?

A. 0.6 V
B. 1.2 V
C. 2.4 V
D. 4.8 V

Solution

V = k * q / r = (8.99 x 10^9 N m²/C²) * (2 x 10^-6 C) / 3 m = 5.99 V.

Correct Answer: B — 1.2 V

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Q. What is the equivalent capacitance of two capacitors (3 µF and 6 µF) in series?

A. 2 µF
B. 1.5 µF
C. 9 µF
D. 18 µF

Solution

1/Ceq = 1/C1 + 1/C2 = 1/3 + 1/6 = 1/2. Therefore, Ceq = 2 µF.

Correct Answer: B — 1.5 µF

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Q. What is the potential difference across a capacitor of 10 µF charged to 5V?

A. 0.05 V
B. 0.5 V
C. 5 V
D. 50 V

Solution

The potential difference across a capacitor is equal to the voltage it is charged to, which is 5 V.

Correct Answer: C — 5 V

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