Magnetic Fields and Electromagnetic Induction

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Magnetic Fields and Electromagnetic Induction - Electric Field Problems

Q. In a series circuit with a 12 V battery and two resistors of 4 Ω and 6 Ω, what is the current flowing through the circuit?

A. 1.2 A
B. 0.8 A
C. 2 A
D. 1 A

Solution

Total resistance R = R1 + R2 = 4 Ω + 6 Ω = 10 Ω. Current I = V/R = 12 V / 10 Ω = 1.2 A.

Correct Answer: A — 1.2 A

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Q. What is the energy stored in a capacitor of 20 µF charged to 10 V?

A. 0.1 J
B. 0.2 J
C. 0.05 J
D. 0.15 J

Solution

Energy U = 0.5 * C * V² = 0.5 * 20 x 10^-6 F * (10 V)² = 0.1 J.

Correct Answer: B — 0.2 J

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Q. What is the potential difference across a capacitor of 10 µF charged to 5 V?

A. 0.05 J
B. 0.1 J
C. 0.2 J
D. 0.15 J

Solution

Energy stored in a capacitor U = 0.5 * C * V² = 0.5 * 10 x 10^-6 F * (5 V)² = 0.125 J.

Correct Answer: B — 0.1 J

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Q. What is the total resistance in a parallel circuit with resistors of 3 Ω, 6 Ω, and 12 Ω?

A. 1 Ω
B. 2 Ω
C. 4 Ω
D. 3 Ω

Solution

1/R_eq = 1/R1 + 1/R2 + 1/R3 = 1/3 + 1/6 + 1/12. R_eq = 2 Ω.

Correct Answer: B — 2 Ω

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Q. What is the voltage across a 10 Ω resistor carrying a current of 3 A?

A. 30 V
B. 15 V
C. 10 V
D. 20 V

Solution

Using Ohm's law, V = I * R = 3 A * 10 Ω = 30 V.

Correct Answer: A — 30 V

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