Force F = k * |q₁ * q₂| / r² = (8.99 x 10^9 N m²/C² * |3 x 10^-6 C * -2 x 10^-6 C|) / (0.1 m)² = 0.54 N.

Using Ohm's law, I = V/R = 24 V / 6 Ω = 4 A.

According to Coulomb's law, the force F between two point charges is inversely proportional to the square of the distance r between them. If the distance is doubled, the force becomes F/4.

Potential difference V = E * d = 2000 N/C * 0.05 m = 100 V.

The total resistance in series is R_total = R1 + R2 = 4Ω + 6Ω = 10Ω. Using Ohm's law, I = V/R_total = 12V / 10Ω = 1.2A.

The peak voltage is the coefficient of the sine function, which is 10 V.

In a purely resistive AC circuit, the voltage and current are in phase, meaning they reach their maximum and minimum values at the same time.

When capacitors are connected in series, the total capacitance decreases and is given by the formula 1/C_total = 1/C1 + 1/C2 + ... + 1/Cn.

Capacitance C = (ε₀ * ε_r * A) / d = (8.85 x 10^-12 F/m * 5 * 2 m²) / 0.01 m = 8.85 x 10^-11 F = 1.77 µF.

Dielectric constant ε_r = C_material / C_air = 30 µF / 10 µF = 3.

Energy stored U = 0.5 * C * V² = 0.5 * 5 x 10^-6 F * (12 V)² = 0.36 mJ.

Equivalent resistance R_eq = R₁ + R₂ + R₃ = 4 Ω + 6 Ω + 12 Ω = 22 Ω.

The potential difference V across a capacitor is given by V = Q/C. Therefore, V = 10μC / 5μF = 2V.

Total capacitance C_total = 1 / (1/C₁ + 1/C₂) = 1 / (1/4 + 1/6) = 2.4 µF.