Q. If the capacitance of a capacitor is doubled while the voltage remains constant, what happens to the charge stored?
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A.
It doubles
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B.
It halves
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C.
It remains the same
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D.
It quadruples
Solution
Charge (Q) stored in a capacitor is given by Q = C * V. If C is doubled and V remains constant, Q also doubles.
Correct Answer:
A
— It doubles
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Q. If the capacitance of a capacitor is doubled, what happens to the charge stored if the voltage remains constant?
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A.
Charge is halved
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B.
Charge remains the same
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C.
Charge is doubled
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D.
Charge is quadrupled
Solution
Capacitance (C) is defined as C = Q/V. If C is doubled and V remains constant, Q must also double.
Correct Answer:
C
— Charge is doubled
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Q. If two capacitors are connected in series, how is the total capacitance (C_total) calculated?
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A.
1/C_total = 1/C1 + 1/C2
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B.
C_total = C1 + C2
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C.
C_total = C1 * C2
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D.
C_total = C1 - C2
Solution
For capacitors in series, the total capacitance is given by 1/C_total = 1/C1 + 1/C2.
Correct Answer:
A
— 1/C_total = 1/C1 + 1/C2
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Q. If two capacitors of capacitance C1 and C2 are connected in series, what is the equivalent capacitance (Ceq)?
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A.
Ceq = C1 + C2
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B.
Ceq = 1 / (1/C1 + 1/C2)
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C.
Ceq = C1 * C2
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D.
Ceq = (C1 * C2) / (C1 + C2)
Solution
The equivalent capacitance for capacitors in series is given by Ceq = 1 / (1/C1 + 1/C2).
Correct Answer:
B
— Ceq = 1 / (1/C1 + 1/C2)
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Q. What happens to the electric potential energy when a positive charge moves away from another positive charge?
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A.
It increases
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B.
It decreases
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C.
It remains the same
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D.
It becomes zero
Solution
As a positive charge moves away from another positive charge, the electric potential energy decreases due to the repulsive force.
Correct Answer:
B
— It decreases
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Q. What is the electric field (E) due to a point charge (Q) at a distance (r)?
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A.
E = k * Q / r^2
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B.
E = k * Q * r^2
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C.
E = Q / (4 * π * ε * r)
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D.
E = Q / (4 * π * ε * r^2)
Solution
The electric field due to a point charge is given by E = k * Q / r^2.
Correct Answer:
A
— E = k * Q / r^2
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Q. What is the electric potential (V) at a distance (r) from a point charge (Q)?
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A.
V = k * Q / r
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B.
V = k * Q * r
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C.
V = Q / (4 * π * ε * r^2)
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D.
V = Q / (4 * π * ε * r)
Solution
The electric potential due to a point charge is given by V = k * Q / r, where k is Coulomb's constant.
Correct Answer:
A
— V = k * Q / r
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Q. What is the formula for the energy stored in a capacitor?
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A.
U = 1/2 C V^2
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B.
U = C V
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C.
U = C V^2
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D.
U = 1/2 Q V
Solution
The energy (U) stored in a capacitor is given by U = 1/2 C V^2.
Correct Answer:
A
— U = 1/2 C V^2
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Q. What is the relationship between voltage (V), current (I), and resistance (R) according to Ohm's Law?
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A.
V = I * R
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B.
I = V * R
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C.
R = V / I
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D.
V = R / I
Solution
According to Ohm's Law, the relationship is V = I * R.
Correct Answer:
A
— V = I * R
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