Current, Resistance and Ohm's Law

Current, Resistance and Ohms Law - Electric Field Problems

Q. A circuit has a total voltage of 12V and a total resistance of 3 ohms. What is the total current in the circuit?

A. 4 A
B. 3 A
C. 2 A
D. 1 A

Solution

Using Ohm's Law, I = V/R. Here, I = 12V / 3Ω = 4 A.

Correct Answer: A — 4 A

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Q. If a capacitor of 5 microfarads is charged to 20 volts, what is the energy stored in the capacitor?

A. 0.01 J
B. 0.02 J
C. 0.05 J
D. 0.1 J

Solution

The energy (U) stored in a capacitor is given by U = 0.5 * C * V^2. Here, U = 0.5 * 5 x 10^-6 F * (20^2) = 0.02 J.

Correct Answer: B — 0.02 J

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Q. If a circuit has a total resistance of 10 Ω and a current of 2 A, what is the voltage across the circuit?

A. 5 V
B. 10 V
C. 20 V
D. 15 V

Solution

Using Ohm's Law: V = I * R = 2 A * 10 Ω = 20 V.

Correct Answer: C — 20 V

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Q. If a resistor of 10 ohms is connected to a 5V battery, what is the current flowing through the resistor?

A. 0.5 A
B. 1 A
C. 2 A
D. 0.2 A

Solution

Using Ohm's Law, I = V/R. Here, I = 5V / 10Ω = 0.5 A.

Correct Answer: B — 1 A

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Q. If two capacitors of 4 µF and 6 µF are connected in parallel, what is the total capacitance?

A. 10 µF
B. 24 µF
C. 2.4 µF
D. 12 µF

Solution

C_eq = C1 + C2 = 4 µF + 6 µF = 10 µF.

Correct Answer: A — 10 µF

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Q. In a parallel circuit with two resistors of 6 ohms and 12 ohms, what is the equivalent resistance?

A. 4 ohms
B. 8 ohms
C. 2 ohms
D. 3 ohms

Solution

For parallel resistors, 1/R_eq = 1/R1 + 1/R2. Here, 1/R_eq = 1/6 + 1/12 = 2/12 + 1/12 = 3/12, so R_eq = 4 ohms.

Correct Answer: A — 4 ohms

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Q. What is the current flowing through a 20 Ω resistor when a voltage of 100 V is applied?

A. 5 A
B. 10 A
C. 15 A
D. 20 A

Solution

Using Ohm's Law: I = V / R = 100 V / 20 Ω = 5 A.

Correct Answer: B — 10 A

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Q. What is the current through a 15 ohm resistor connected to a 45V source?

A. 3 A
B. 2 A
C. 1 A
D. 4 A

Solution

Using Ohm's Law, I = V/R. Here, I = 45V / 15Ω = 3 A.

Correct Answer: A — 3 A

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Q. What is the electric field (E) at a distance of 2 meters from a point charge of 5 microcoulombs?

A. 1125 N/C
B. 450 N/C
C. 225 N/C
D. 900 N/C

Solution

Using Coulomb's law, E = k * |q| / r^2, where k = 8.99 x 10^9 N m^2/C^2, q = 5 x 10^-6 C, and r = 2 m. E = (8.99 x 10^9) * (5 x 10^-6) / (2^2) = 1125 N/C.

Correct Answer: A — 1125 N/C

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Q. What is the electric field strength between two parallel plates separated by 0.1 m with a potential difference of 100 V?

A. 1000 N/C
B. 500 N/C
C. 100 N/C
D. 2000 N/C

Solution

The electric field (E) is given by E = V/d. Here, E = 100V / 0.1m = 1000 N/C.

Correct Answer: A — 1000 N/C

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Q. What is the equivalent resistance of three resistors of 4 ohms, 6 ohms, and 12 ohms connected in series?

A. 22 ohms
B. 12 ohms
C. 10 ohms
D. 8 ohms

Solution

In series, R_eq = R1 + R2 + R3 = 4Ω + 6Ω + 12Ω = 22Ω.

Correct Answer: A — 22 ohms

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Q. What is the force between two charges of +2 µC and -3 µC separated by a distance of 0.5 m?

A. -1.08 N
B. -0.72 N
C. 1.08 N
D. 0.72 N

Solution

Using Coulomb's law: F = k * |q1 * q2| / r^2 = (8.99 x 10^9 N m²/C²) * |(2 x 10^-6 C) * (-3 x 10^-6 C)| / (0.5 m)^2 = -1.08 N.

Correct Answer: A — -1.08 N

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Q. What is the force between two charges of 1 microcoulomb each, separated by a distance of 0.5 meters?

A. 0.36 N
B. 0.72 N
C. 0.18 N
D. 0.09 N

Solution

Using Coulomb's law, F = k * |q1 * q2| / r^2. Here, F = (8.99 x 10^9) * (1 x 10^-6)^2 / (0.5^2) = 0.36 N.

Correct Answer: A — 0.36 N

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Q. What is the potential difference across a capacitor of 2 microfarads charged to 10 volts?

A. 20 mC
B. 0.02 C
C. 0.02 mC
D. 0.2 C

Solution

The charge (Q) on a capacitor is given by Q = C * V. Here, Q = 2 x 10^-6 F * 10 V = 20 x 10^-6 C = 20 mC.

Correct Answer: A — 20 mC

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Q. What is the potential difference across a capacitor of 5 µF charged to 12 V?

A. 0.06 C
B. 0.06 J
C. 0.06 V
D. 0.06 F

Solution

The energy stored in a capacitor is U = 0.5 * C * V^2 = 0.5 * 5 x 10^-6 F * (12 V)^2 = 0.36 J.

Correct Answer: B — 0.06 J

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Q. What is the total current in a circuit with a 12 V battery and a total resistance of 4 Ω?

A. 3 A
B. 4 A
C. 6 A
D. 2 A

Solution

Using Ohm's Law: I = V / R = 12 V / 4 Ω = 3 A.

Correct Answer: C — 6 A

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Showing 1 to 16 of 16 (1 Pages)

Current, Resistance and Ohms Law - Electric Field Problems

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