Q. A steel rod with a diameter of 10 mm is subjected to a tensile force of 20 kN. What is the stress in the rod?
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A.
1273.24 MPa
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B.
159.15 MPa
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C.
2000 MPa
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D.
500 MPa
Solution
Stress = Force / Area. The area A = π(d/2)² = π(0.005)² = 7.85e-5 m². Stress = 20000 N / 7.85e-5 m² = 254647.91 Pa or 254.65 MPa.
Correct Answer:
B
— 159.15 MPa
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Q. If a material has a Young's modulus of 200 GPa and is subjected to a tensile stress of 100 MPa, what is the strain?
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A.
0.0005
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B.
0.005
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C.
0.05
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D.
0.5
Solution
Strain can be calculated using the formula: Strain = Stress / Young's Modulus. Thus, Strain = 100 MPa / 200 GPa = 0.0005.
Correct Answer:
A
— 0.0005
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Q. In a bending moment diagram, what does a positive bending moment indicate?
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A.
Beam is sagging
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B.
Beam is hogging
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C.
Beam is in tension
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D.
Beam is in compression
Solution
A positive bending moment indicates that the beam is sagging, meaning the top fibers are in compression and the bottom fibers are in tension.
Correct Answer:
A
— Beam is sagging
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Q. What is the critical load for a column with a length of 3 m, a moment of inertia of 0.0001 m^4, and a modulus of elasticity of 200 GPa?
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A.
1.96 kN
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B.
2.45 kN
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C.
3.14 kN
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D.
4.00 kN
Solution
The critical load P = (π² * E * I) / (L²). Substituting the values: P = (π² * 200e9 * 0.0001) / (3²) = 1.96 kN.
Correct Answer:
A
— 1.96 kN
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Q. What is the formula for calculating stress?
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A.
Stress = Force / Area
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B.
Stress = Area / Force
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C.
Stress = Force * Area
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D.
Stress = Area * Force
Solution
Stress is defined as the force applied per unit area, hence the formula is Stress = Force / Area.
Correct Answer:
A
— Stress = Force / Area
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Q. What is the formula for calculating the moment of inertia for a rectangular beam?
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A.
I = (b * h^3) / 12
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B.
I = (h * b^3) / 12
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C.
I = b * h^2
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D.
I = (b * h) / 12
Solution
The moment of inertia for a rectangular beam is given by the formula I = (b * h^3) / 12, where b is the base width and h is the height.
Correct Answer:
A
— I = (b * h^3) / 12
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Q. What is the shear stress in a circular shaft subjected to a torque of 500 Nm and a diameter of 50 mm?
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A.
15.92 MPa
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B.
31.84 MPa
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C.
63.68 MPa
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D.
79.58 MPa
Solution
Shear stress τ = (T * r) / J, where J = (π/32) * d^4. For d = 0.05 m, J = (π/32) * (0.05)⁴ = 4.91e-9 m^4. τ = (500 * 0.025) / 4.91e-9 = 31.84 MPa.
Correct Answer:
B
— 31.84 MPa
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Q. What is the unit of stress in the SI system?
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A.
Pascal (Pa)
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B.
Newton (N)
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C.
Joule (J)
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D.
Kilogram (kg)
Solution
The unit of stress in the SI system is Pascal (Pa), which is equivalent to one Newton per square meter.
Correct Answer:
A
— Pascal (Pa)
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