The radius r is half of the diameter, so r = 12/2 = 6 cm. The area A = πr² = π(6)² = 36π cm².

Using the intersecting chords theorem, AE * EB = CE * DE. Thus, 3 * 4 = CE * 2, which gives CE = 6 cm.

Using the intersecting chords theorem, AE * EB = CE * ED. Thus, 3 * 4 = CE * 6, which gives CE = 2 cm.

The angle subtended at any point on the circle is half of the angle subtended at the center. Therefore, it is 120/2 = 60 degrees.

The angle subtended at any point on the remaining part of the circle is half of the angle at the center, so it is 60 degrees.

The radius is half of the diameter. Therefore, the radius is 12 cm / 2 = 6 cm.

The area of a circle is given by the formula A = πr². Therefore, A = π(7)² = 49π cm², which is approximately 154 cm².

The distance between the center of a circle and any point on the circle is defined as the radius.

The length of an arc is given by L = (θ/360) * 2πr. Thus, L = (90/360) * 2 * π * 10 = 15.7 cm.

The area A of a circle is given by A = πr². Therefore, r² = 50, which gives r = √50 = 5√2 cm, approximately 7.07 cm.

The angles formed by two tangents drawn from a point outside the circle are equal.

The angle subtended at the center of the circle is always double the angle subtended at the circumference by the same arc.