Vertically opposite angles are equal, so the angle is also 40 degrees.

Same-side interior angles are supplementary, so angle 2 = 180 - 70 = 110 degrees.

Alternate exterior angles are equal, so angle B also measures 120 degrees.

The slope is undefined because the x-coordinates are the same, indicating a vertical line.

The interior angle on the same side is supplementary to the exterior angle, so it measures 180 - 130 = 50 degrees.

Alternate exterior angles are equal to their corresponding angles, so the alternate exterior angle is 150 degrees.

The slope of the line 2x + 3y = 6 is -2/3. A line parallel to it will have the same slope. Using point-slope form, the equation becomes 3y - 2 = -2/3(2 - 1), which simplifies to 2x + 3y = 8.

The slope of the parallel line remains 3. Using point-slope form, y - 1 = 3(x - 1) gives y = 3x - 2.

Using the point-slope form, the equation is y - 2 = 3(x - 1), which simplifies to y = 3x - 1.

Parallel lines have the same slope, so the slope of the other line is also 3.

Corresponding angles are equal, so the angle on the other line is also 40 degrees.

Corresponding angles are equal when two parallel lines are cut by a transversal.

Using point-slope form: y - 2 = 3(x - 1) simplifies to y = 3x - 1.

Alternate exterior angles are equal when two parallel lines are cut by a transversal.

Same-side interior angles are supplementary, so 180 - 40 = 140 degrees.

Corresponding angles are equal, so the angle on the other line is also 70 degrees.

The distance between two parallel lines y = mx + b1 and y = mx + b2 is |b2 - b1| / √(1 + m^2). Here, |(-5) - 3| / √(1 + 2^2) = 8/√5.

The distance between two parallel lines y = mx + b1 and y = mx + b2 is |b2 - b1| / √(1 + m^2). Here, |(-4) - 1| / √(1 + 3^2) = 5 / √10 = 5/√10.

The distance between two parallel lines of the form y = mx + b1 and y = mx + b2 is given by |b2 - b1| / sqrt(1 + m^2). Here, |(-3) - 1| / sqrt(1 + 4) = 4 / sqrt(5) which approximates to 1.

Parallel lines have the same slope, so the slope of the parallel line is -1/2.

Parallel lines have the same slope, so the slope of L2 is also 2.

The slope is calculated as (y2 - y1) / (x2 - x1). Here, (7 - 3) / (2 - 2) is undefined because the denominator is 0.

The slope is calculated as (y2 - y1) / (x2 - x1) = (7 - 3) / (4 - 2) = 4/2 = 2.

Parallel lines have the same slope, so the slope of line B is also -1/2.

The slope of line B is the same as line A, which is -1/2.

Parallel lines have the same slope, so the slope of the parallel line is -1/2.

The sum of angles in a triangle is 180 degrees. Let x be the measure of each equal angle: 50 + 2x = 180, so 2x = 130, thus x = 65 degrees.

The distance formula gives d = |y2 - y1| = |10 - 4| = 6.

Corresponding angles are equal when two parallel lines are cut by a transversal.

Corresponding angles are equal when two parallel lines are cut by a transversal.