Q. How many subnets can be created from a Class B network with a subnet mask of 255.255.255.0?
-
A.
256
-
B.
128
-
C.
64
-
D.
32
Solution
Using a subnet mask of 255.255.255.0 on a Class B network allows for 256 subnets, as it borrows 8 bits from the host portion.
Correct Answer:
A
— 256
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Q. How many subnets can be created from a Class C network with a default subnet mask of 255.255.255.0 if 3 bits are borrowed?
Solution
Borrowing 3 bits from the host portion allows for 2^3 = 8 subnets, but with 2 reserved for network and broadcast, 6 usable subnets remain.
Correct Answer:
A
— 4
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Q. How many total IP addresses are available in a subnet with a /22 CIDR notation?
-
A.
1024
-
B.
512
-
C.
256
-
D.
64
Solution
A /22 subnet provides 2^(32-22) = 2^10 = 1024 total IP addresses.
Correct Answer:
A
— 1024
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Q. How many usable IP addresses are available in a subnet with a /29 subnet mask?
Solution
A /29 subnet mask provides 8 total addresses, of which 6 are usable for hosts after excluding the network and broadcast addresses.
Correct Answer:
B
— 6
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Q. If a device has an IP address of 172.16.5.10 with a subnet mask of 255.255.255.0, what is its network address?
-
A.
172.16.5.0
-
B.
172.16.5.10
-
C.
172.16.0.0
-
D.
172.16.5.255
Solution
The network address is determined by the IP address and subnet mask; for 172.16.5.10/24, the network address is 172.16.5.0.
Correct Answer:
A
— 172.16.5.0
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Q. If a network has the IP address 192.168.1.0/24, what is the broadcast address?
-
A.
192.168.1.255
-
B.
192.168.1.0
-
C.
192.168.1.1
-
D.
192.168.1.254
Solution
The broadcast address for the subnet 192.168.1.0/24 is 192.168.1.255, which is the highest address in the subnet.
Correct Answer:
A
— 192.168.1.255
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Q. In a subnet with a subnet mask of 255.255.255.248, how many usable IP addresses are there?
Solution
A subnet mask of 255.255.255.248 allows for 2^3 - 2 = 6 usable IP addresses.
Correct Answer:
B
— 6
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Q. What is the CIDR notation for a subnet mask of 255.255.255.128?
-
A.
/25
-
B.
/26
-
C.
/27
-
D.
/24
Solution
The CIDR notation for a subnet mask of 255.255.255.128 is /25, indicating that the first 25 bits are used for the network.
Correct Answer:
A
— /25
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Q. What is the first usable IP address in the subnet 10.0.0.0/22?
-
A.
10.0.0.1
-
B.
10.0.0.0
-
C.
10.0.3.255
-
D.
10.0.0.2
Solution
The first usable IP address in the subnet 10.0.0.0/22 is 10.0.0.1, as 10.0.0.0 is the network address.
Correct Answer:
A
— 10.0.0.1
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Q. What is the maximum number of hosts that can be accommodated in a subnet with a subnet mask of 255.255.255.224?
Solution
A subnet mask of 255.255.255.224 provides 32 IP addresses, of which 30 are usable for hosts after accounting for the network and broadcast addresses.
Correct Answer:
A
— 30
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Q. What is the maximum number of hosts that can be accommodated in a subnet with a subnet mask of 255.255.255.240?
Solution
A subnet mask of 255.255.255.240 provides 4 bits for host addresses, allowing for 2^4 - 2 = 14 usable hosts.
Correct Answer:
A
— 14
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Q. What is the subnet mask for a Class C IP address with 30 usable hosts?
-
A.
255.255.255.252
-
B.
255.255.255.240
-
C.
255.255.255.248
-
D.
255.255.255.254
Solution
A Class C address with 30 usable hosts requires a subnet mask of 255.255.255.252, which allows for 4 IP addresses (2 usable).
Correct Answer:
A
— 255.255.255.252
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Q. What is the subnet mask for a network with 30 usable IP addresses?
-
A.
255.255.255.252
-
B.
255.255.255.248
-
C.
255.255.255.240
-
D.
255.255.255.224
Solution
A subnet mask of 255.255.255.252 allows for 2 usable IP addresses (4 total - 2 for network and broadcast), which is suitable for point-to-point links.
Correct Answer:
A
— 255.255.255.252
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Q. What is the total number of hosts in a subnet with a /18 subnet mask?
-
A.
16382
-
B.
16384
-
C.
8190
-
D.
8192
Solution
A /18 subnet mask allows for 2^(32-18) = 16384 total addresses, of which 16382 are usable for hosts.
Correct Answer:
B
— 16384
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Q. Which of the following IP addresses is a valid host address in the subnet 172.16.0.0/20?
-
A.
172.16.0.0
-
B.
172.16.15.255
-
C.
172.16.0.1
-
D.
172.16.16.1
Solution
The valid host addresses in the subnet 172.16.0.0/20 range from 172.16.0.1 to 172.16.15.254, making 172.16.0.1 a valid host address.
Correct Answer:
C
— 172.16.0.1
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