Q. A strip footing is placed on a sandy soil with a friction angle of 30 degrees. What is the approximate value of the bearing capacity factor N_q?
A.
1.5
B.
2.5
C.
3.5
D.
4.5
Solution
For a friction angle of 30 degrees, the bearing capacity factor N_q can be approximated using the formula N_q = e^(π * tan(φ)) * tan(45 + φ/2). For φ = 30 degrees, N_q is approximately 3.5.
Q. For a foundation subjected to a vertical load, what is the primary mode of failure?
A.
Shear failure
B.
Bearing capacity failure
C.
Settlement failure
D.
Tensile failure
Solution
The primary mode of failure for a foundation subjected to vertical loads is typically bearing capacity failure, which occurs when the soil can no longer support the applied load.
Q. What is the bearing capacity of a square footing with a side length of 1.5 m on a soil with a cohesion of 40 kPa and a depth of 1 m?
A.
120 kPa
B.
160 kPa
C.
200 kPa
D.
240 kPa
Solution
The ultimate bearing capacity for a square footing can be calculated as q_u = c*N_c + q. For a depth of 1 m, N_c is approximately 5.0. Thus, q_u = 40 kPa * 5 = 200 kPa.
Q. What is the ultimate bearing capacity of a shallow foundation on a cohesive soil with a cohesion of 50 kPa and a depth of 1.5 m?
A.
100 kPa
B.
150 kPa
C.
200 kPa
D.
250 kPa
Solution
The ultimate bearing capacity (q_u) can be calculated using the formula q_u = c*N_c, where c is the cohesion and N_c is the bearing capacity factor. For a depth of 1.5 m, N_c is approximately 5.0. Thus, q_u = 50 kPa * 5 = 250 kPa.