The speed of the wave v is given by v = fλ. Here, f = 2 Hz and λ = 1 m (from the wave equation). Thus, v = 2 * 1 = 2 m/s.

The wave speed v can be found from the equation v = fλ. Here, f = 4 Hz and λ = 2 m (from k = 2π/λ, k = 1 m⁻¹). Thus, v = 4 Hz * 2 m = 8 m/s.

'k' is the wave number, which is related to the wavelength λ by the equation k = 2π/λ.

'A' represents the amplitude of the wave, which is the maximum displacement from the equilibrium position.

In the wave equation y(x, t) = A sin(kx - ωt), A represents the amplitude of the wave, which is the maximum displacement from the equilibrium position.

The phase velocity v is given by v = ω/k.

The amplitude of the wave is given directly by A in the wave equation. Here, A = 2 m.

Wavelength λ is given by λ = v/f. Here, v = 300 m/s and f = 150 Hz. Thus, λ = 300/150 = 2.0 m.

The wavelength λ can be calculated using the formula v = fλ. Thus, λ = v/f = 300 m/s / 150 Hz = 2 m.

Wavelength λ = v/f = 300 m/s / 75 Hz = 4 m.

The speed of a wave is given by the formula v = fλ, where f is the frequency and λ is the wavelength. Here, v = 500 Hz * 2 m = 1000 m/s.

Wavelength (λ) can be calculated using the formula λ = v/f. Here, λ = 300 m/s / 150 Hz = 2 m.

The wavelength λ can be calculated using the formula v = fλ. Thus, λ = v/f = 300 m/s / 150 Hz = 2 m.

Wavelength λ = v/f = 300/150 = 2 m.

Using the wave equation v = fλ, we can find frequency f = v/λ = 500 m/s / 2 m = 250 Hz.

Frequency (f) = speed (v) / wavelength (λ) = 500 m/s / 5 m = 100 Hz.

The speed of the wave is given by v = fλ. Here, v = 500 Hz * 2 m = 1000 m/s.

Wavelength (λ) can be calculated using the formula λ = v/f. Here, λ = 300 m/s / 150 Hz = 2 m.

Wavelength (λ) = Speed (v) / Frequency (f) = 300 m/s / 150 Hz = 2 m.

Wavelength λ = v/f = 340 m/s / 170 Hz = 2.0 m.

Wind speed in km/h = 15 m/s * 3.6 = 54 km/h.

Absolute error = Relative error * True value = 0.1 * 10 = 1 kg.

Percentage error = (Absolute error / Measured value) * 100 = (1 / 50) * 100 = 2%

Using the formula ω = ω₀ + αt, where ω₀ = 0, α = 2 rad/s², and t = 5 s, we get ω = 0 + 2*5 = 10 rad/s.

Using the formula ω = ω₀ + αt, we have ω = 10 rad/s + (2 rad/s²)(5 s) = 20 rad/s.

Final angular velocity = initial angular velocity + (angular acceleration × time) = 10 + (2 × 5) = 20 rad/s.

Linear speed v = rω = 0.5 m * 10 rad/s = 5 m/s.

The total kinetic energy is the sum of translational and rotational kinetic energy. K.E. = (1/2)Mv² + (1/2)(Iω²) where I = (1/2)MR² for a solid cylinder.

The linear velocity v of the center of the wheel is given by v = Rω.

For rolling without slipping, the linear velocity v is related to angular velocity ω by the equation v = Rω.