Major Competitive Exams

My Learning Cart

Major Competitive Exams

Download Q&A

Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

Civil Services Defence Exams Engineering & Architecture Admissions Government Jobs Management Admissions Undergraduate

Q. A research team found that 50% of a certain habitat's species are insects. If there are 400 species total, how many are insects?

A. 150
B. 200
C. 250
D. 300

Solution

50% of 400 is 0.50 * 400 = 200.

Correct Answer: B — 200

Q. A researcher finds that a certain plant species grows at a rate of 5 cm per month. How tall will the plant be after 2 years?

A. 60 cm
B. 70 cm
C. 80 cm
D. 90 cm

Solution

5 cm/month * 24 months = 120 cm tall.

Correct Answer: C — 80 cm

Q. A researcher finds that a certain plant species has a growth rate of 5 cm per month. How tall will the plant be after 2 years if it starts at 10 cm?

A. 70 cm
B. 80 cm
C. 90 cm
D. 100 cm

Solution

2 years = 24 months. Growth = 5 cm/month * 24 months = 120 cm. Total height = 10 cm + 120 cm = 130 cm.

Correct Answer: C — 90 cm

Q. A researcher finds that their study results can be manipulated to favor a certain outcome. They can either publish the results as they are or alter them for a more favorable outcome. What is the ethical choice?

A. Publish altered results
B. Publish true results
C. Withhold publication
D. Seek external funding

Solution

The ethical choice is to publish true results to maintain integrity in research.

Correct Answer: B — Publish true results

Q. A researcher needs to dilute a 10M solution to a 1M solution. If they take 100 mL of the 10M solution, how much water should they add?

A. 900 mL
B. 1000 mL
C. 1100 mL
D. 1200 mL

Solution

Using the dilution formula C1V1 = C2V2, 10M * 100mL = 1M * V2. V2 = 1000 mL. Water to add = 1000 mL - 100 mL = 900 mL.

Correct Answer: A — 900 mL

Q. A resistor of 10 ohms is connected to a 20V battery. What is the current flowing through the resistor?

A. 0.5 A
B. 1 A
C. 2 A
D. 5 A

Solution

Using Ohm's Law, I = V/R = 20V / 10Ω = 2 A.

Correct Answer: C — 2 A

Q. A resistor of 10 Ω and a capacitor of 100 μF are connected in series to an AC source of frequency 50 Hz. What is the capacitive reactance? (2020)

A. 3.18 Ω
B. 31.8 Ω
C. 0.318 Ω
D. 318 Ω

Solution

Capacitive reactance Xc = 1/(2πfC) = 1/(2π(50)(100 × 10^-6)) ≈ 3.18 Ω.

Correct Answer: A — 3.18 Ω

Q. A resistor of 10Ω is connected across a 20V battery. What is the power consumed by the resistor? (2021)

A. 40W
B. 20W
C. 10W
D. 5W

Solution

Power (P) is given by P = V^2/R = 20V^2 / 10Ω = 400W / 10 = 40W.

Correct Answer: A — 40W

Q. A resistor of 10Ω is connected to a 20V battery. What is the power consumed by the resistor? (2021)

A. 40W
B. 20W
C. 10W
D. 2W

Solution

Power (P) is given by P = V^2/R = (20V)^2 / 10Ω = 400/10 = 40W.

Correct Answer: A — 40W

Q. A resistor of 10Ω is connected to a 20V power supply. What is the power consumed by the resistor? (2021)

A. 40W
B. 20W
C. 10W
D. 2W

Solution

Power (P) is given by P = V^2/R = (20V)^2 / 10Ω = 400/10 = 40W.

Correct Answer: A — 40W

Q. A response team has 80% of their supplies ready. If they have 1,000 units of supplies, how many units are not ready?

A. 100
B. 200
C. 300
D. 400

Solution

Units not ready = 20% of 1,000 = 0.20 * 1,000 = 200 units.

Correct Answer: B — 200

Q. A retailer bought a bicycle for $300 and sold it for $360. What is the profit percentage?

A. 15%
B. 20%
C. 25%
D. 30%

Solution

Profit = Selling Price - Cost Price = $360 - $300 = $60. Profit Percentage = (Profit / Cost Price) * 100 = ($60 / $300) * 100 = 20%.

Correct Answer: B — 20%

Q. A retailer bought a watch for $120 and sold it for $150. What is the profit percentage?

A. 20%
B. 25%
C. 30%
D. 15%

Solution

Profit = Selling Price - Cost Price = $150 - $120 = $30. Profit Percentage = (Profit/Cost Price) * 100 = ($30/$120) * 100 = 25%.

Correct Answer: B — 25%

Q. A retailer bought a watch for $80 and marked it up by 25%. What is the marked price?

A. $90
B. $100
C. $110
D. $120

Solution

Marked Price = Cost Price + Markup = 80 + (25% of 80) = 80 + 20 = $100.

Correct Answer: C — $110

Q. A retailer bought a watch for $80 and sold it for $100. What is the gain in dollars?

A. $15
B. $20
C. $25
D. $30

Solution

Gain = Selling Price - Cost Price = 100 - 80 = 20.

Correct Answer: B — $20

Q. A retailer bought a watch for $80 and sold it for $100. What is the gain in percentage?

A. 25%
B. 30%
C. 20%
D. 15%

Solution

Gain = Selling Price - Cost Price = 100 - 80 = 20. Gain Percentage = (Gain/Cost Price) * 100 = (20/80) * 100 = 25%.

Correct Answer: A — 25%

Q. A retailer buys a bicycle for $300 and sells it for $360. What is the profit percentage? (2023)

A. 15%
B. 20%
C. 25%
D. 30%

Solution

Profit = Selling Price - Cost Price = 360 - 300 = 60. Profit Percentage = (Profit/Cost Price) * 100 = (60/300) * 100 = 20%.

Correct Answer: B — 20%

Q. A retailer buys a watch for $120 and sells it at a profit of 15%. What is the selling price?

A. $138
B. $140
C. $144
D. $150

Solution

The selling price is calculated as $120 + (15% of $120) = $120 + $18 = $138.

Correct Answer: C — $144

Q. A retailer buys a watch for $150 and sells it at a profit of 25%. What is the selling price? (2023)

A. $175
B. $180
C. $187.5
D. $200

Solution

Selling Price = Cost Price + Profit = 150 + (25% of 150) = 150 + 37.5 = $187.5.

Correct Answer: C — $187.5

Q. A retailer buys a watch for $150 and sells it for $180. What is the profit percentage?

A. 15%
B. 20%
C. 25%
D. 30%

Solution

Profit = Selling Price - Cost Price = 180 - 150 = 30. Profit Percentage = (30/150) * 100 = 20%.

Correct Answer: B — 20%

Q. A retailer buys a watch for $300 and sells it at a profit of 15%. What is the selling price?

A. $345
B. $350
C. $360
D. $375

Solution

Selling Price = Cost Price + Profit = $300 + ($300 * 0.15) = $300 + $45 = $345.

Correct Answer: A — $345

Q. A retailer marks a product 40% above the cost price. If the cost price is $50, what is the marked price?

A. $60
B. $70
C. $80
D. $90

Solution

Marked Price = Cost Price + 40% of Cost Price = 50 + 0.40 * 50 = 50 + 20 = 70.

Correct Answer: C — $80

Q. A retailer marks up the price of a product by 25% and then offers a discount of 10%. If the cost price is $80, what is the final selling price?

A. $90
B. $92
C. $95
D. $100

Solution

Marked Price = Cost Price + 25% of Cost Price = 80 + 20 = $100. Discount = 10% of 100 = $10. Selling Price = 100 - 10 = $90.

Correct Answer: B — $92

Q. A retailer marks up the price of a watch by 25% and then offers a discount of 10%. If the cost price is $200, what is the selling price?

A. $220
B. $230
C. $240
D. $250

Solution

Marked Price = Cost Price + 25% of Cost Price = 200 + 50 = 250. Discount = 10% of 250 = 25. Selling Price = Marked Price - Discount = 250 - 25 = 225.

Correct Answer: C — $240

Q. A retailer marks up the price of a watch by 25% and then offers a discount of 10%. If the cost price is $200, what is the final selling price?

A. $220
B. $225
C. $230
D. $240

Solution

Marked Price = Cost Price + 25% of Cost Price = 200 + 50 = $250. Discount = 10% of 250 = 25. Selling Price = 250 - 25 = $225.

Correct Answer: C — $230

Q. A retailer offers a discount of 15% on a jacket priced at $200. What is the selling price after the discount?

A. $170
B. $180
C. $190
D. $160

Solution

Discount = 15% of 200 = 0.15 * 200 = 30. Selling Price = 200 - 30 = 170.

Correct Answer: B — $180

Q. A retailer sells a bicycle for $300 after applying a discount of 10%. What was the original price of the bicycle?

A. $270
B. $330
C. $300
D. $350

Solution

Let the original price be x. After a 10% discount, the selling price is x - (0.10 * x) = 0.90x. Setting this equal to $300 gives 0.90x = $300, so x = $300 / 0.90 = $333.33.

Correct Answer: B — $330

Q. A rhombus has diagonals of lengths 12 cm and 16 cm. What is the area of the rhombus?

A. 96 cm²
B. 48 cm²
C. 72 cm²
D. 60 cm²

Solution

Area of a rhombus = (1/2) × d1 × d2. Thus, Area = (1/2) × 12 × 16 = 96 cm².

Correct Answer: A — 96 cm²

Q. A right triangle has an area of 30 square units and one leg measuring 10 units. What is the length of the other leg?

A. 3
B. 6
C. 9
D. 12

Solution

Area = (1/2) * base * height, so 30 = (1/2) * 10 * height. Thus, height = 6.

Correct Answer: B — 6

Q. A right triangle has an area of 30 square units and one leg measuring 5 units. What is the length of the other leg?

A. 6
B. 10
C. 12
D. 15

Solution

Area = (1/2) * base * height, so 30 = (1/2) * 5 * height. Thus, height = 30 * 2 / 5 = 12.

Correct Answer: B — 10

Showing 2881 to 2910 of 31669 (1056 Pages)

School

College

Degree

Competitve

Skills

Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely