Plants have a cell wall made of cellulose, which is a defining characteristic.

Eukarya is the group of organisms that have a true nucleus.

Gymnosperms are known for having seeds, which are not enclosed in fruits.

Pteridophytes are known for having true roots, stems, and leaves.

Gymnosperms are known for producing seeds, which are not enclosed in an ovary.

Pteridophytes are known for producing spores as a means of reproduction.

Bryophytes, such as mosses and liverworts, are primarily aquatic and require water for reproduction.

Pteridophytes reproduce through spores, while angiosperms and gymnosperms reproduce through seeds.

The -OCH3 group shows +M effect as it donates electrons through resonance.

The –OH group donates electron density through resonance, exhibiting a +M effect.

-NO2 is a strong electron-withdrawing group that decreases electron density on the benzene ring.

Iodobutane can be converted to an alcohol by hydrolysis, while bromobenzene requires a different mechanism due to its aromatic nature.

Tertiary haloalkanes like 3-bromopropane can undergo elimination reactions more readily due to the stability of the resulting alkene.

2-bromobutane can undergo elimination to form an alkene due to the presence of a beta-hydrogen.

2-bromobutane can undergo elimination to form an alkene due to the presence of a beta-hydrogen.

Iodoethane is the most reactive due to the weaker C-I bond compared to C-Br, C-Cl, and C-F bonds.

Iodoethane has the highest boiling point due to the larger size and polarizability of iodine.

Iodoethane is least soluble in water due to its larger size and lower polarity compared to the others.

3-bromobutane is more likely to undergo elimination due to steric hindrance, favoring the formation of alkenes.

3-bromopropane is more reactive due to the stability of the tertiary carbocation formed during the reaction.

3-bromopropane is a tertiary haloalkane, which is more reactive towards nucleophilic substitution due to steric hindrance and stability of the carbocation formed.

3-chloropropane is a tertiary haloalkane and will undergo elimination more readily due to the stability of the resulting alkene.

2-bromopropane undergoes elimination readily due to the formation of a stable alkene.

Tertiary haloalkanes like 3-chloropropane undergo nucleophilic substitution more readily due to steric hindrance and the stability of the carbocation formed during the reaction.

All of the listed haloarenes can undergo nucleophilic substitution under suitable conditions.

Nitrochlorobenzene is most reactive due to the electron-withdrawing nitro group, which stabilizes the negative charge in the intermediate.

Iodobenzene is the most reactive towards nucleophilic substitution due to the weaker C-I bond compared to the other haloarenes.

23.40 has 4 significant figures, while 0.0450 has 3.

25.00 has 4 significant figures due to the trailing zeros.

H2O has two lone pairs and two bonding pairs, resulting in a bent geometry.